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These problems are hard to start but became easy the more you learn. there is no - sqrt so the the domain would be from 2 to infinity. setting denominater = 0 is how you solve
the explanation is great but the range is not correct because if x is greater or equal to 2 and then when we add 2 to 1 then it becomes 3 then our range would be y is greater or equal to 3
Domain - domain is all the possible x values that can be inputted a rule So if there was a sqrt above the varible like f(x) = sqrt(x) it cant be negative because you cant find the sqrt of a negative number, so negative numbers are not included in the range. So it would be x >0/ = 0. Range is the same but instead of it being all the possible x values, its all the possible ys. This relies on the domain as the y /dependent variable typically does Using the last example but adding an + 5 to the expression y would be =5 or >5.
