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2.6 Chain Rule - Example 1 - e^(2x) 

rootmath
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www.rootmath.org | Calculus
We use the chain rule to take the derivative of e^(2x).

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1 окт 2024

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Комментарии : 72   
@weichaotee5025
@weichaotee5025 10 лет назад
another 1 of life's mysteries solved.
@Juntjumper
@Juntjumper 12 лет назад
thank you for making a video about something that isn't covered much on the internet! This video basically filled a "hole" in math information online!
@deubs3563
@deubs3563 3 года назад
@Stars of Velaris 8 years late
@JH-it2yr
@JH-it2yr 2 года назад
9 years later🐣
@guessmynamelol5393
@guessmynamelol5393 2 года назад
@@JH-it2yr 9 years and 3 months later 👀
@elablessed8838
@elablessed8838 10 лет назад
I am utterly amazed how that equates. This computation seems to have generated a Live on its own. Thank you for clarification, sir. It’s greatly appreciated!
@DarklightALBANIA
@DarklightALBANIA 12 лет назад
It doesn't look to me like the chain rule i have learned maybe I am wrong but : f(g(x))=f '(g(x))*g '(x)
@rootmath
@rootmath 12 лет назад
@DarklightALBANIA it's the same chain rule, just different notation. In this example, using your notation we have, f(x) = e^x and g(x) = (2x). So f(g(x)) = e^(2x). And the derivative is just what you said, f '(g(x))*g '(x) = e^(2x)*2
@MUHAMMADFAUZAN-qw7oc
@MUHAMMADFAUZAN-qw7oc 3 года назад
simple ....much better
@jameow4890
@jameow4890 Год назад
This guy is complicating it. I watch khan academy and it's much easier to understand.
@SuperSpaceKing
@SuperSpaceKing 2 года назад
Superb
@emilioyavar4876
@emilioyavar4876 2 года назад
MUCHAS GRACIAS!!!!!!!!
@whototrust2643
@whototrust2643 2 года назад
Thank you, helped me a lot!
@kbaitsi
@kbaitsi 4 года назад
Thank you! Understood it very quickly!
@annamays9064
@annamays9064 5 лет назад
Ur handwriting is beautiful
@lovelybiman
@lovelybiman 2 года назад
Very helpful video. thank you so much.
@OonHan
@OonHan 6 лет назад
2:51 when you take the derivative of *e^x* not _e_
@JH-it2yr
@JH-it2yr 2 года назад
I wish my calculus teacher could be like you!
@DawitTes
@DawitTes 7 лет назад
THANK YOU YOU BEAUTIFUL SOUL
@mrnosy1
@mrnosy1 11 лет назад
You can just put the co-efficient behind the derivative it doesnt make a difference and then take the derivative and multiply by the co-efficient. You can very easily prove it with the product rule: f(x)g(x) = f'(x)g(x) + f(x)g'(x)
@chadsification
@chadsification 6 лет назад
Thanks for the video, really appreciate it!
@xerxes_06
@xerxes_06 2 года назад
ty
@ShivKumar-rf7pi
@ShivKumar-rf7pi 5 лет назад
Thanks
@MomoMomo-en8fx
@MomoMomo-en8fx 8 лет назад
U sir are awesome, someone get this man a girlfriend- or four!!
@safakozturk8009
@safakozturk8009 4 года назад
I love the way you explain. But it seems that you miss the derivative of natural logarithm and exponential functions part... I couln't find that topics on your Calculus playlist. By the way, great work!
@dustinlabat7956
@dustinlabat7956 4 года назад
Thank you.
@JH-it2yr
@JH-it2yr 2 года назад
Very clearly, thank you a lot!
@AznNaruto3
@AznNaruto3 11 лет назад
So is the derivative of 4e^2x = (8e^2x)(2)?
@kajal217
@kajal217 7 лет назад
what would be the derivative of, log x^2x plz help me
@mehtabali2302
@mehtabali2302 5 лет назад
thanks for sharing his concepts....................
@kritimandubey1955
@kritimandubey1955 3 года назад
Thankyou sir by our heart
@NattyWerewolf
@NattyWerewolf 10 лет назад
great video
@gowrabdasdip8759
@gowrabdasdip8759 7 лет назад
what will be result of e^-2x??
@ihatedrake4
@ihatedrake4 8 лет назад
whats the derivative of this tlnt divided by e^t
@A13X371
@A13X371 11 лет назад
Thank you!!! :)
@gracenansamba2777
@gracenansamba2777 4 года назад
thanks God bless
@duruczimi
@duruczimi 8 лет назад
Great explanation! Thanks
@karthivenkat6636
@karthivenkat6636 6 лет назад
Thank you so much sir
@roshanrawani6411
@roshanrawani6411 7 лет назад
Love you sir😁😁😁😁
@charlesamofordjuoh9940
@charlesamofordjuoh9940 9 лет назад
thx for this video
@kotone6322
@kotone6322 4 года назад
Thank you!!
@hamzaalmokdim5300
@hamzaalmokdim5300 5 лет назад
thank you dude
@tapakornpimpru
@tapakornpimpru 9 лет назад
thank a lot bro.
@taurinenrgy
@taurinenrgy 7 лет назад
Thank you
@meena1983om
@meena1983om 4 года назад
Thanx are y American
@AaronRClark
@AaronRClark 10 лет назад
thank you
@فيلسوفالعرب-ظ3م
@فيلسوفالعرب-ظ3م 9 лет назад
much helpful
@elizabethelric3721
@elizabethelric3721 8 лет назад
Thank you!
@harryhirst5954
@harryhirst5954 7 лет назад
Thank you!!!
@yo322Ju
@yo322Ju 8 лет назад
Thanks!
@thesauce807
@thesauce807 10 лет назад
Ty
@renevos5822
@renevos5822 3 года назад
The e is for easy
@akbo3866
@akbo3866 3 года назад
Thanks
@chaimaeelmesrar9311
@chaimaeelmesrar9311 7 лет назад
فهمت بالانجليزية احسن من الشرح بالعربية 😪✌
@skfkfkd
@skfkfkd 8 лет назад
what if instead of e you use a different variable?
@BenJuan26
@BenJuan26 8 лет назад
+Serge Espejo e in this case is not a variable, it is a fundamental constant in mathematics. Its approximate value 2.718, but its important property is that the derivative of e^x is e^x. This would not work with any other number.
@skfkfkd
@skfkfkd 8 лет назад
thank you
@jademaverick8291
@jademaverick8291 6 лет назад
Were those the final answers?
@AmorFati72
@AmorFati72 5 лет назад
Yes
@wajahat5673
@wajahat5673 5 лет назад
Well no shit
@hamedalkatheeri5389
@hamedalkatheeri5389 5 лет назад
Why does he sound like ross from friends
@zeus433
@zeus433 7 лет назад
Wow, You sound a lot like sal khan.
@vivswanpadmeshya5044
@vivswanpadmeshya5044 6 лет назад
thanks
@rdvanyldz1114
@rdvanyldz1114 7 лет назад
nice
@LiKuTzU
@LiKuTzU 11 лет назад
thank you
@grisvolonte
@grisvolonte 8 лет назад
Thank you!!!
@prosurgeon6957
@prosurgeon6957 5 лет назад
you are the best, screw all of these ppl out there who are trying to make things difficult you are a legend man
@moncoeurpourvous
@moncoeurpourvous 11 лет назад
is this part of khan academy?
@SunilSingh-tg5hd
@SunilSingh-tg5hd 5 лет назад
No, it's not
@rickandelon9374
@rickandelon9374 7 лет назад
ONe thing PLz REmember THat d/dx e is actually not e itself its a constant that is 2.7184.... so its gonna be 0
@bowmanzz1
@bowmanzz1 6 лет назад
Is Stanford the MIT of the west coast?
@captainpetrson5812
@captainpetrson5812 8 лет назад
Next time please just do the question instead of babbling
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