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integral of sin(x)/x from 0 to inf by Feynman's Technique 

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The integral of sin(x)/x from 0 to inf by using Feynman's technique (aka differentiation under the integral sign). This integral is also called the Dirichlet integral. Check out another example of Feynman's technique of integration: • Feynman's Technique of...
Zachary's page: philosophicalm... ,
integral of sin(x)*e^(-bx), • The appetizer, integra...
Another example, Integral of ln(x^2+1)/(x+1) from 0 to 1 by Mu Prime Math, • It took me 3 hours to ...
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1 окт 2024

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Комментарии : 1,3 тыс.   
@112BALAGE112
@112BALAGE112 7 лет назад
You don't often see a man doing partial derivatives while wearing a partial derivative t-shirt.
@blackpenredpen
@blackpenredpen 7 лет назад
hahahahaha! honestly, that wasn't planned.
@ruiyingwu893
@ruiyingwu893 7 лет назад
blackpenredpen I just realised after reading this...
@yamenarhim9336
@yamenarhim9336 6 лет назад
me 2 lollll
@edwardtang3585
@edwardtang3585 6 лет назад
It seemed to me like some sort of band sign like Nike at first
@AlgyCuber
@AlgyCuber 6 лет назад
what’s the difference between partial derivative and normal derivative?
@_DD_15
@_DD_15 7 лет назад
This is so famous, i still remember 8 years ago, when my uni professor told me, there is psychiatric hospital for those who still try to find a primitive of sin(x) / x... lol
@mohamedabdullahi5708
@mohamedabdullahi5708 4 года назад
Kkkkk
@sharmisthaghosh9017
@sharmisthaghosh9017 4 года назад
Lol
@camkiranratna
@camkiranratna 4 года назад
For some reason , “lol” looks like mod(0)
@deltaspace0
@deltaspace0 4 года назад
@@camkiranratna do you mean absolute value?
@dclrk8331
@dclrk8331 4 года назад
@@deltaspace0 Absolute value is also called mod in some places.
@AmanteNoViolao
@AmanteNoViolao 7 лет назад
When you sleep in class 14:01
@bonbonpony
@bonbonpony 7 лет назад
More like when you blink in class :)
@peppybocan
@peppybocan 7 лет назад
but the answer was spoiled in that part :D
@Tomaplen
@Tomaplen 7 лет назад
when you struggle not to sleep
@AhnafAbdullah
@AhnafAbdullah 7 лет назад
Idk why was the video cut? lol
@blackpenredpen
@blackpenredpen 7 лет назад
Ahnaf Abdullah I wanted to add that explanation why b has to be nonnegative
@sonicpawnsyou
@sonicpawnsyou 7 лет назад
I see you have finally decided to clothe like a true mathematician, seeing your t-shirt involves partial derivatives. 👌
@blackpenredpen
@blackpenredpen 7 лет назад
MeowGrump lolllll this is a good one!!!
@ffggddss
@ffggddss 7 лет назад
asics = "Anime sane in corpore sano," "Sound mind/spirit in a sound body."
@koharaisevo3666
@koharaisevo3666 7 лет назад
Anima not anime (but that's somehow relevant :))))
@omarathon5922
@omarathon5922 6 лет назад
👌 looks like the partial derivative sign XD
@herbert164
@herbert164 6 лет назад
So, it is soul eater then?
@cycklist
@cycklist 7 лет назад
I really enjoy watching you integrate! Relaxing and fascinating at the same time. Isn't it!
@blackpenredpen
@blackpenredpen 7 лет назад
PompeyDB it is!
@jirehchoo2151
@jirehchoo2151 6 лет назад
it is, is not? It's!
@rehmmyteon5016
@rehmmyteon5016 5 лет назад
I really enjoy watching you disintegrate! Relaxing and fascinating at the same time. Isn't it!
@tens0r884
@tens0r884 4 года назад
@@rehmmyteon5016 lmao
@lisalisa9706
@lisalisa9706 7 лет назад
you told us not to trust wolfram and now you confirm your answer in wolfram. what am i supposed to do with my life now?
@brandong5687
@brandong5687 7 лет назад
Dokuta Viktor trust no one
@arthurreitz9540
@arthurreitz9540 7 лет назад
Dokuta Viktor Ask wolfram.
@blackpenredpen
@blackpenredpen 7 лет назад
Dokuta Viktor only if it gives the same answer as what we got.
@axemenace6637
@axemenace6637 6 лет назад
blackpenredpen what if what you got is by looking at Wolfram????
@MingruiCHENG
@MingruiCHENG 6 лет назад
then don't get things from Wolfram but just check your answer with it.
@rudycummings4671
@rudycummings4671 2 года назад
I recall doing this integral many years ago. Back then we used contour integration. We chose the contour to be a semi-circle of radius R centered at the origin . The origin was indented and cotoured with a semi-circle of radius r. The semi-circle was located in the upper-half of the Cartesian plane. Complex integration in one of the most potent methods for dealing with such problems.
@gertwallen
@gertwallen Год назад
I agree, I solved this too in my first course of Applied Mathematics in college where we used complex analysis techniques ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Ff4LRlflib0.html
@greatwhitesufi
@greatwhitesufi Год назад
Yeah that's true, that's how I learnt it/saw it first
@lasmatesdelamor4287
@lasmatesdelamor4287 Год назад
Integrales cerradas en variable compleja?
@louisrobitaille5810
@louisrobitaille5810 Год назад
You can do integrals on complex bounds (lower/upper) 😮? Or is it Real bounds but integrated on Complex functions?
@comp.lex4
@comp.lex4 Год назад
@@louisrobitaille5810 complex functions and complex bounds. Turns out that the path you take *mostly* doesn't matter!
@rishavmukherjee4251
@rishavmukherjee4251 4 года назад
"And once again, pi pops out of nowhere!"
@siguardvolsung
@siguardvolsung 6 лет назад
"This is so much fun, isn't it?" Sure.
@dannygjk
@dannygjk 5 лет назад
lol
@ShotgunLlama
@ShotgunLlama 7 лет назад
He's becoming self aware
@Aramil4
@Aramil4 7 лет назад
How so? What did you notice?
@Reluxthelegend
@Reluxthelegend 7 лет назад
isn't it?
@Lofila999
@Lofila999 Год назад
💀I’m in 11th starting trying to learn this as my physics part needs it.
@jemcel0397
@jemcel0397 7 лет назад
Believe in Math; Believe in the Pens; Believe in Black and Red Pens.
@blackpenredpen
@blackpenredpen 7 лет назад
yay!!!!
@MrAssassins117
@MrAssassins117 6 лет назад
Yes, i did It and i got 10 in my integral calculus exam :') two months ago !
@pranav2119
@pranav2119 3 года назад
@@MrAssassins117 now 3 years ago lol
@_.Infinity._
@_.Infinity._ 3 года назад
@@pranav2119 now 3 yrs and 14 hrs ago.
@not_vinkami
@not_vinkami 3 года назад
……人又相信 一世一生這膚淺對白 來吧送給你 要幾百萬人流淚過的歌 如從未聽過 誓言如幸福摩天輪 才令我因你 要呼天叫地愛愛愛愛那麼多…… If you know you'll know
@blackpenredpen
@blackpenredpen 3 года назад
Of course I know 😆
@2070user
@2070user 3 года назад
ahhh, that's why the intro song is so familiar, k歌之王 by Eason Chan!
@andraspongracz5996
@andraspongracz5996 4 года назад
The part where the constant C is determined by checking the limit of the function at infinity is very elegant. Beautiful proof. Of course, there are a lot of technical details that mathematicians would think about (is it correct to derivate inside the integral, exchange limit and integral, etc.). But this video is a great summary of the overall strategy. Very nice work!
@hyungmanpark4346
@hyungmanpark4346 Год назад
.l
@seanclough7810
@seanclough7810 7 лет назад
him: "And now let's draw the continuation arrow with also looks like the integration symbol. That's so cool." Me: "Ha." I happen to remember just enough calculus to follow along. Interesting. Thank you.
@blackpenredpen
@blackpenredpen 7 лет назад
Sean Clough yay! I am happy to hear!
@terapode
@terapode 6 лет назад
One of the best math videos I´v ever seen. Changing the function from x to b was a masterpiece.
@gertwallen
@gertwallen Год назад
Yes, Feynman was a brilliant mind
@MagnusSkiptonLLC
@MagnusSkiptonLLC 7 лет назад
Who else reads his shirt as "partial asics"?
@whiz8569
@whiz8569 5 лет назад
18:12 I like the idea that, after going through all that, we figure out that the integral from 0 to infinity of sin(x)/x dx is equal to... Some unknown value.
@antonquirgst2812
@antonquirgst2812 2 года назад
its not that unexpected though if you look at the function... its just looks very convergent.. (this can ofc be very deceiving)
@createyourownfuture5410
@createyourownfuture5410 2 года назад
@@antonquirgst2812 But there's the fact that as x grows larger, it tends to 0 because sin's at most 1 or -1.
@antonquirgst2812
@antonquirgst2812 2 года назад
@@createyourownfuture5410 yup - totally agree - x grows linear while sin(x) is periodic!
@createyourownfuture5410
@createyourownfuture5410 2 года назад
@@antonquirgst2812 Aaaand it approaches 0 from both sides
@josephcamavinga9721
@josephcamavinga9721 2 года назад
@@createyourownfuture5410 It actually approaches 1 from 0
@bonbonpony
@bonbonpony 7 лет назад
Now it's time for the Gamma function and some other Euler integrals ;>
@samiali2434
@samiali2434 5 лет назад
I came in just because i saw the name Feynman
@abdullahbinjahed6900
@abdullahbinjahed6900 5 лет назад
me too
@supriya1423
@supriya1423 4 года назад
You got it ,me too
@亨亨-y5v
@亨亨-y5v 7 лет назад
K 歌之王?
@blackpenredpen
@blackpenredpen 7 лет назад
Isaac TNT yes
@__-rs8kr
@__-rs8kr 4 года назад
blackpenredpen man of culture
@mathnezmike
@mathnezmike 4 года назад
Wow. At the begining the integral with the exponential function looks more complicated, but that function allows to have a closed form and the Leibniz theorem is fundamental. Great work!
@NazriB
@NazriB 2 года назад
Lies again? So fat
@proofofalifetime488
@proofofalifetime488 7 лет назад
Hi, I just learned this technique over the summer. I was amazed. I used it to solve a problem from American Mathematical Monthly. It was fun, not only sending in a solution, but learning this amazing technique used by Feynman!
@nk4634
@nk4634 5 лет назад
Using laplace transform and fubini's theorem this integral reduces to a simple trig substitution problem.
@charliearcaro208
@charliearcaro208 4 года назад
Great video using Feynman's technique but would never tackle this integral in this way. Once you've applied the Laplace transform it's much easier to use Euler's formula and substitute sin(x) with Im (e^ix). Haven't read all of the comments but I'm sure this has already been mentioned
@Sugarman96
@Sugarman96 2 года назад
I'm familiar with using the Fourier transform to find the integral, but I don't quite see how you'd use the Laplace transform.
@charliearcaro208
@charliearcaro208 2 года назад
@@Sugarman96 - the Laplace transform is what the above video uses when creating his function I (b)
@mrocto329
@mrocto329 2 года назад
​@@Sugarman96 I'(b) is the same negative laplace transform of sin(x) which you can use to easily find I'(b) instead of doing whatever he did.
@WildSeven19
@WildSeven19 7 лет назад
Thanks for reminding me what I enjoyed about maths! It really is good fun to play around with calculus like this.
@bigjosh2517
@bigjosh2517 7 лет назад
This integral's easy. Just pretend that all angles are small, replace sin(x) = x, the x's cancel so you're left with the integral of 1 :D
@NoActuallyGo-KCUF-Yourself
@NoActuallyGo-KCUF-Yourself 7 лет назад
Hard to justify with those zero to infy limits. ;-)
@AndDiracisHisProphet
@AndDiracisHisProphet 7 лет назад
so, pi/2 \approx inf?
@kikones34
@kikones34 7 лет назад
How can you pretend all angles are small? The angle goes to infinity o_O
@mike4ty4
@mike4ty4 7 лет назад
@kikones34 : Yeah, that's the joke (note the ":D" grin at the end.). But it _does_ work for the _variable_-bound integral int_{0...x} sin(t)/t dt which, by the way, defines the standard mathematical function Si(x), the "sine integral" function, because you can then consider when all angles in the integration are small. If you take sin(t) ~ t then you say for _small_ x that int_{0...x} sin(t)/t dt ~ int_{0...x} t/t dt = int_{0...x} dt = x so Si(x) ~ x when x is small. And a Taylor expansion will show you that that makes sense, too: Si(x) = x - x^3/(3.3!) + x^5/(5.5!) - x^7/(7.7!) + x^9/(9.9!) - x^11/(11.11!) + ... so the first (lowest-order) term is x, thus at small x, Si(x) = x + O(x^3), meaning the rest vanishes like x^3.
@kikones34
@kikones34 7 лет назад
@mike4ty4 Oh, sorry, I totally didn't get you were joking. I've been on a RU-vid trip of flat earther videos before watching this, so I was in a mindset in which I assumed nonsensical statements are actually serious and not jokes xD.. D:
@Zonnymaka
@Zonnymaka 7 лет назад
Wow, that was an heavy load! I never saw anything like that before...it'll take me a few days to digest the technique. Well done!
@michaeljohnston3038
@michaeljohnston3038 3 года назад
That's what she said
@yuchenwang679
@yuchenwang679 5 лет назад
Correct me if I'm wrong, I'm a bit rusty, but don't you need to prove uniform convergence before bringing the differentiation sign inside the integral?
@MsMaciekk
@MsMaciekk 5 лет назад
I think you're right. I was thinking the same
@andreisecuiu6491
@andreisecuiu6491 5 лет назад
Does it help? I am not an expert in the field (yet): en.wikipedia.org/wiki/Leibniz_integral_rule
@sharmisthaghosh9017
@sharmisthaghosh9017 4 года назад
Please do some putnam integrals They are really tricky and also few tough integrals like these. I love watching your integration videos.
@NoActuallyGo-KCUF-Yourself
@NoActuallyGo-KCUF-Yourself 7 лет назад
Can you recommend a good proof of Liebniz Rule to follow? It seems like one of those simple/obvious things that would actually have an interesting/ instructive proof.
@stephenmontes349
@stephenmontes349 7 лет назад
make video on the squeze theorem, I bet you can make it interesting and to show all techniques
@blackpenredpen
@blackpenredpen 7 лет назад
Paul Montes dr. Peyam is actually going to do that soon
@S1nwar
@S1nwar 7 лет назад
the world needs more of this....
@ClumpypooCP
@ClumpypooCP 7 лет назад
Lmao the "isn't it" in the thumbnail
@benjaminbrady2385
@benjaminbrady2385 7 лет назад
These are so addicting to watch and I don't know why
@JoseDiaz-gp1bn
@JoseDiaz-gp1bn 7 лет назад
You always manage to make me click to watch you do integrals I've already done long ago!, but this integral of sinc(x) was really gorgeous. It's kinda the method for obtaining the the moments of x with the gaußian. I hope to see more of this kind.
@PackSciences
@PackSciences 7 лет назад
At 14:18 : You say that since e^-bx matters, the integral converges for all values of b >= 0. Well it's true for b > 0. The reasoning cannot work for b = 0 because it's slightly more complicated than that (but it converges too). Counter example : Integral from 0 to infinity of e^-bx/x dx doesn't converge for b = 0.
@footskills4953
@footskills4953 7 лет назад
Hi, this is Zachary Lee. You are absolutely right to be concerned about the convergence at b=0. What you want to do is let b approach 0 from the right. If you want a rigorous explanation, check out Appendix A, on page 21 of this document: www.math.uconn.edu/~kconrad/blurbs/analysis/diffunderint.pdf
@blackpenredpen
@blackpenredpen 7 лет назад
Footskills here's the man!!!
@Cannongabang
@Cannongabang 7 лет назад
Yeah that was a brief explanation haahahhahaha
@footskills4953
@footskills4953 7 лет назад
And here I am again!!! Btw, great explanation!
@Tyns19
@Tyns19 7 лет назад
PackSciences your counter example should be rearranged as (e^(-b x)-1)/x Btw e^(-b x)/x diverges for all values of "b"
@bruno-tt
@bruno-tt 7 лет назад
Beautiful proof, thank you.
@restitutororbis964
@restitutororbis964 6 лет назад
bruno edwards Yup, leibniz rule is very powerful.
@franciscoabusleme9085
@franciscoabusleme9085 7 лет назад
I knew this, but it is still awesome. More stuff like this pls!
@הראלישי-ר1מ
@הראלישי-ר1מ 4 года назад
Your claim that the expression inside the integral is going to 0 when x approcheing to infinity is very problematic when you understand that we considering the case when b=0. Then, the integral wouldn't be convergent, so how can you explain that?
@fabianpascalabt6353
@fabianpascalabt6353 4 года назад
x approaches 0 from the right. With a weapon. Also discussed later in the comments
@icenarsin5283
@icenarsin5283 Год назад
Best math teacher ever !!!
@wontpower
@wontpower 7 лет назад
You said "isn't it" correctly :')
@blackpenredpen
@blackpenredpen 7 лет назад
I did, isn't it! hehehe
@SanjeevKumar-js4mu
@SanjeevKumar-js4mu 5 лет назад
@@blackpenredpen didn't I
@adi-sngh
@adi-sngh 4 года назад
@@SanjeevKumar-js4mu lol
@MrQwefty
@MrQwefty 7 лет назад
Wow dude.. I thought I've seen it all, and then you FOUND C!! XDDD
@nikitakipriyanov7260
@nikitakipriyanov7260 4 года назад
You have to admit you've never solved differential equations before. This is very usual and boring thing, finding out these constants.
@FilipeOliveira-ir1hb
@FilipeOliveira-ir1hb 3 года назад
All the computations are only valid for b>0, because you need the exponencial to derive inside the integral under Lebesgue's domination Theorem. But at the end you do b=0. One further step is needed to show that I is continuous at 0. Note that this os not easy because |sin(x)/x| is not integrable, and therefore you cannot use standard continuity theorems as they require a domination hypothesis.
@FilipeOliveira-ir1hb
@FilipeOliveira-ir1hb 3 года назад
Hello Alejo. Yes, I agree, but that is exacly my point. You need a more demanding theory (such as Denjoy integrability, among other possibilities) to justify the calculus presented in the video.
@nathsmath2871
@nathsmath2871 7 лет назад
00:00-00:23 K歌之王 :D
@blackpenredpen
@blackpenredpen 7 лет назад
LoSir MATH yea! I was waiting for someone to comment on that hahaha
@穿第
@穿第 5 лет назад
@@blackpenredpen 你係香港人?
@鄧啃
@鄧啃 5 лет назад
穿第 佢應該係大陸人,生活在國外(在美國?)的數學髙手。
@generalsnicky3219
@generalsnicky3219 4 года назад
@@穿第 可能是台湾人
@sanketgupta7662
@sanketgupta7662 4 года назад
This comes under differential under integration sign....
@EpicUnderscoreJdog
@EpicUnderscoreJdog 7 лет назад
just noticed that his shirt is the partial derivative of asics
@markigolnikov6175
@markigolnikov6175 6 лет назад
When he reversed derivative on I(b) by integrating (14:45 min ) and evaluated result as b went to infinity and got zero for that limit-his argument failed. You only get zero if b>0, not if b=0. If b=0 you don't get zero as x goes to infinity-you get divergence
@usdescartes
@usdescartes 4 года назад
You can recover it, however, with just a little more rigor. Instead of evaluating I(0), find limb->0 I(b). Then, just keep using the limit notation until the end. The original integral is actually equal to limb->0 I(b) = Pi/2, so no real harm done.
@fidgetspinner1050
@fidgetspinner1050 6 лет назад
*I S N T I T ?*
@me_hanics
@me_hanics 4 года назад
There seem to be a few questionable parts about the video. The most important one is at 20:41, it's understandable that as b goes to infinite and x does too, the value is 0, but if x=0 and b is infinity, then you have e^(0*infinity) which is questionable what it equals? Another thing is that how can you assume that b=0 "works the same way" as positive b values, when negative b values don't give a convergent value, and mess up the whole thing? How can you say that 0 which is "on the border" works like positive values. But this probably can be answered easily, but the e^infinity*0 seems to me like no
@thomasg6830
@thomasg6830 7 лет назад
The cut at 14:02 is kind of confusing.
@dhvsheabdh
@dhvsheabdh 6 лет назад
thomas g Just got to it, I reckon he's solved it already, then started talking about his steps and realised it'd fit better with the part where he was previously (in his timeline) talking about it.
@xxsamperrinxx3993
@xxsamperrinxx3993 5 лет назад
It's so he can outline that b has to be positive, and it probably makes the most sense to put the clip here
@adi-sngh
@adi-sngh 4 года назад
When u sleep on class
@user-en5vj6vr2u
@user-en5vj6vr2u 4 года назад
it spoiled the rest of the video
@user-wf3oj2vv2w
@user-wf3oj2vv2w 7 лет назад
Can you do the Gaussian integral -integral of e^-(x^2) from -inf to +inf
@suhaimimazed1136
@suhaimimazed1136 7 лет назад
The kids' laugh made me forget the stress of trying to understanding how you solve it. 😂😂😂😂😂😂😂😂😂
@blackpenredpen
@blackpenredpen 7 лет назад
Mazed Suhaimi yay!!!!
@nin10dorox
@nin10dorox 4 года назад
14:30 How can b be >= 0, shouldn't it be just > 0? If it is 0, then the cosine in the solved integral will not converge.
@antred9157
@antred9157 4 года назад
I'm late, but I'll try to explain (sorry I'm french). Here you're using a theorem (with hypothesis he's isn't precising) to be able to differentiate in the integral. This theorem also tells u thats I and I' are continuous on there interval of definition. This means that ye, b>0 for I' but when you get the expression of I, since I is continuous on [0,+inf[, u can say that I(0)=lim I(b) when b->0 and thats it
@davidkeys3962
@davidkeys3962 4 года назад
@@antred9157 Yes, b must be positive for the calculation. And one still needs to show that the function I is continuous at 0. This is in fact not easy to do, since the absolute value |sin(x)/x| is not integrable on [0,+inf]. One usually proceeds as follows: Instead of integrating over [0,+inf], define I_n(b), for positive b, to be the integral over [0,n]. Now use Feynman's trick. Proceed as in the video, and finally show that I_n(n) goes to 0 as n goes to infinity to complete the proof.
@cheunghoksum
@cheunghoksum 7 лет назад
K歌之王wwww 0:00
@blackpenredpen
@blackpenredpen 7 лет назад
yup!!!!!!!!!
@liahsheep
@liahsheep 7 лет назад
香港人路過⋯
@not_vinkami
@not_vinkami 6 лет назад
香港人表示路過 Hongkongers was here
@bhavna6565
@bhavna6565 6 лет назад
What is it??
@stevenschelling8452
@stevenschelling8452 6 лет назад
13:14 fuck that IS so cool
@blackpenredpen
@blackpenredpen 6 лет назад
Thanks
@8796205190
@8796205190 5 лет назад
Hi professor, You are doing great...
@blackpenredpen
@blackpenredpen 5 лет назад
Thank you!
@k_wl
@k_wl Год назад
small question, why cant the integral of -1/1 + b^2 be arccot(b) + c
@k_wl
@k_wl Год назад
ok nvm some things change but i end up getting pi/2 answer anyway so ig it can be it
@mohammadaminsarabi6207
@mohammadaminsarabi6207 5 лет назад
Feynman was a mathematician, physician and philosopher... super geniuce
@juanpiedrahita-garcia5138
@juanpiedrahita-garcia5138 5 лет назад
Physicist*
@adityaekbote8498
@adityaekbote8498 3 года назад
@@juanpiedrahita-garcia5138 lol
@clarenceauerbach7934
@clarenceauerbach7934 Месяц назад
genius , even as a joke it hurts my eyes
@abedbob4046
@abedbob4046 4 года назад
Hey Natural Born Improper Integrals Crusher can you please help me integrate [t*e(-sqrt(t)]÷(1+t^2). I used all the methods, except Feynman method and all those online integral calculators, but all of them bumped on it.
@mohanadou
@mohanadou 4 года назад
The best ever demonstration i've seen. I always thought this integral to be done by an algorithm based on the sum of trapezium areas which gives approximatively the same result as pi/2. Really amazing demo. The next question would be what is the primary function of integral of sin(x)/x dx ?
@alifa8903
@alifa8903 Год назад
You said b is greater than or equal to zero. But if b is equal to zero, then the limit when x goes to infinity e^(-bx) will become 1 and in cos(infinity) there no limit.
@kakan147
@kakan147 7 лет назад
Love Feynman and this trick was cool and useful. You now have another subscriber :)
@blackpenredpen
@blackpenredpen 7 лет назад
Wonderful!!!!!!!!
@louisrobitaille5810
@louisrobitaille5810 Год назад
14:06 How did that right part magically appear 🥲? Edit 14:54: Ah, post explanation cut 😅…
@jackchai5808
@jackchai5808 7 лет назад
Please do more video about the Feynman Techniques Thanks a lot
@blackpenredpen
@blackpenredpen 7 лет назад
Jack Chai ok
@roy1660
@roy1660 Год назад
Instead use Fourier transform method, inverse Fourier transform of sampling function is gating function with parameters A and T
@sainathreddyvarikuti4835
@sainathreddyvarikuti4835 5 лет назад
Love u darling 😘
@aakashkhamaru9403
@aakashkhamaru9403 2 года назад
I still remember my first year in college. It was filled with so many wonderful moments. This was not one of them.
@venkatramana4414
@venkatramana4414 4 года назад
We can not take derivative into integral when limit is infinite.
@leandrokeenzapa2217
@leandrokeenzapa2217 4 года назад
any reference pls?
@nostradamus9132
@nostradamus9132 Год назад
But if you allow b to be 0 the integral does not converge... b>=0 does not work, you need b>0.
@ersin486
@ersin486 4 года назад
20:35 Dont you get, if you integrate 0, another constant? Because the derivative of an Constant is 0 too
@blackpenredpen
@blackpenredpen 4 года назад
elp 486 It’s a definite integral of 0 from a to b, so there’s no area. : )
@poissonsumac7922
@poissonsumac7922 3 года назад
Holy frick, I never saw that in Calc 3! That's NIFTY! Could you extend this technique to solve the integral sin(x)/x^2 by taking two partial derivatives?
@executorarktanis2323
@executorarktanis2323 4 года назад
13:19 that is cool
@aintaintaword666
@aintaintaword666 4 года назад
I wouldn't mind more explanations at 10:00... I mean, all the rest is more or less technicalities, but that was the crucial part of the whole thing
@sandeepjha-iitkgp
@sandeepjha-iitkgp 5 лет назад
Great video. Least I can do is thank you for a great explanation!
@blackpenredpen
@blackpenredpen 5 лет назад
Thank you!!!
@mustafamalik4211
@mustafamalik4211 4 года назад
Solve it by using Laplace Transform?
@dyer308
@dyer308 7 лет назад
Yay i was waiting for this!
@Benderulas
@Benderulas 5 лет назад
why -e^bx * (cosx +bsinx) / (b^2 + 1) = 0? (if x goes to infinity) what if b = 0?
@tharunmahesh7279
@tharunmahesh7279 4 года назад
Hey, great video! Loved your explanation. I still have one doubt, however . when we solve for I'(b) and we get an e^-bx in the numerator, the fact that lim(x--->infinity)e^-bx =0 holds only for positive b values, not for b=0. But the issue is, to solve the original integral, we are inputting the value of b as 0, even after taking the above limit. but certainly, the value is matching, so how do we resolve the above anomaly?
@riccardopuca9310
@riccardopuca9310 2 года назад
I also had this question. Anyone can help?
@asirpagabriella5327
@asirpagabriella5327 2 года назад
@@riccardopuca9310 Maybe you have to set b>0, but when going back to the original, you let b approaches 0+?
@stephenchurch1784
@stephenchurch1784 2 года назад
The last step where he solves I(b) for b = 0 is a clever trick to avoid putting 0 into e^-bx. If you've taken diffeq, you can confirm for yourself by solving the original integral with a laplace transform. It'll also answer where the e^-bx came from in the first place
@kalimachios
@kalimachios Год назад
had the same problem - i guess one can make b > 0, and then take the lim as b -> 0 from above on the I'(b) or I(b).. and would still be fine .. but how is presented, has that small issue
@NMClasses-e5i
@NMClasses-e5i 3 месяца назад
Sir wonderful explanation Thank u sir
@NoNameAtAll2
@NoNameAtAll2 7 лет назад
Red T-shirt? Are you Tom Scott?
@blackpenredpen
@blackpenredpen 7 лет назад
NoName who's that?
@NoNameAtAll2
@NoNameAtAll2 7 лет назад
blackpenredpen Really good youtuber Talks about interesting places to visit and interesting concepts to discuss
@blackpenredpen
@blackpenredpen 7 лет назад
does he always wear red tee?
@haarithio1621
@haarithio1621 7 лет назад
blackpenredpen yep
@blackpenredpen
@blackpenredpen 7 лет назад
Ah! I see
@executorarktanis2323
@executorarktanis2323 4 года назад
Why didn't the intregal change when it's limit to minus
@damianmatma708
@damianmatma708 4 года назад
What's also very Interesting, we could also use *Lobachevsky's integral formula* : *integral from 0 to +∞ of [ f(x) * (sin(x) / x) ] = integral from 0 to (π/2) of [ f(x) ]* So our example: integral from 0 to +∞ of [ (sin(x) / x) ] has *f(x)=1* :) Now we use Lobachevsky's integral formula: *integral from 0 to +∞ of [ f(x) * (sin(x) / x) ] = integral from 0 to (π/2) of [ f(x) ]* integral from 0 to +∞ of [ 1 * (sin(x) / x) ] = integral from 0 to (π/2) of [ 1 ] integral from 0 to +∞ of [ (sin(x) / x) ] = integral from 0 to (π/2) of [ 1 ] = x | computed from 0 to (π/2) = (π/2) - 0 = (π/2) *Answer:* integral from 0 to +∞ of [ (sin(x) / x) ] = *(π/2)* Mr Michael Penn made a video (entitled ) where he calculates that example using Lobachevsky's integral formula: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-m0o6pAeCcJs.html "Lobachevsky's integral formula and a nice application." Michael Penn
@atrumluminarium
@atrumluminarium 7 лет назад
The "db" in "d/db" looks funny :p
@Czeckie
@Czeckie 7 лет назад
the only problem is that the computation is not justified. Leibniz rule is not stated for improper integrals. If you want it to use for improper integrals, you have to justify all the exchanges of limits that arise.
@Czeckie
@Czeckie 7 лет назад
No. It's more complicated. If you want to use Leibniz rule for improper integrals, the integral has to be absolutely convergent, but int sin(x)/x is not. You need to do more work, see Lang's Undergraduate analysis for example, this case is treated there (but the last part left as an exercise).
@jadegrace1312
@jadegrace1312 6 лет назад
Czeckie isnt integral sinx/x absolutely convergent for all values except x=0 and x=infinity/negative infinity, and we know it converges for int [0,inf] sin(x)/x because of the graph, you could use the infinite sum for the integral
@martinepstein9826
@martinepstein9826 6 лет назад
Joshua you're talking about whether limiting values of the function f(x) = (sin x)/x exist, not whether the integral of the function is convergent. Czeckie is referring to the convergence of a sequence like [int f(x) from 0 to pi, int f(x) from 0 to 2pi, int f(x) from 0 to 3pi, ...] which is conditionally convergent but not absolutely convergent.
@reu.mathematicsacademy8566
@reu.mathematicsacademy8566 2 года назад
Wonderful mathematics there sir
@alczhou
@alczhou 7 лет назад
谢谢
@andywinslow6631
@andywinslow6631 4 года назад
I'm curious about the very last step. Evaluating atan(0) should yield multiple solutions. How do you reconcile this? What justification do you have for selecting only the principal value?
@Lee-rp7vx
@Lee-rp7vx 2 года назад
The defined range of arctan(x) is arctan (x)∈[-π/2, π/2]. So therefore there is only one value!
@harrystuart7455
@harrystuart7455 6 лет назад
Isn't I'(b) undefined for b=0? It confuses me how you can make deductions about I(b) at b=0 from its differential when its differential is undefined at that point. Forgive me if this may sound dumb, the furthest I've been taught in school so far is integrating polynomials, but is there a way to justify this in a more rigorous sense or is it actually fine and I'm nit-picking over something irrelevant?
@martinepstein9826
@martinepstein9826 6 лет назад
He is using the limit as x -> 0 of sin(x)/x which equals 1.
@chopcooey
@chopcooey 6 лет назад
the function is undefined, but the derivative isn't
@michelkhoury1470
@michelkhoury1470 5 лет назад
I(b) is defined in 0 but I'(b) isn't defined in 0
@michelkhoury1470
@michelkhoury1470 5 лет назад
For example the function f(x)=sqrt(x) is defined in 0 but its derivate is not defined in 0 because f'(x)= 1/(2*sqrt(x))
@estuardodiaz2720
@estuardodiaz2720 7 лет назад
Wow! Great video, amaizing technique. This was an intense integral xD
@blackpenredpen
@blackpenredpen 7 лет назад
thanks!
@beaming_sparkling_trash261
@beaming_sparkling_trash261 Год назад
For the ones that want to dive into the details, I think we have to justify that the differential equation is defined for b in (R+*) in order for e^(-bx) to actually tend towards 0, then use the continuity of parameter integrals so that I(b) -> I(0) when b->0. Finally, the dominated convergence theorem gives us that I(b) -> 0 when b->inf. We conclude with the fact that arctan + pi/2 -> pi/2 when b->0, and uniqueness of the limit : both limits I(0) and pi/2 are equal ♡
@leif1075
@leif1075 Год назад
Why would anyone think to add e^x thiugh this COMES OUT OF NOWHERE..what I thought to do was replace sinex with e^ix from Eulers formula..isn't thst smarter and more intuitive? I think he needs to justify where e^x cones from if anything it should be ln x he is adding nkt e^× since 1/× is the derivative of ln x not e^×..
@यशराज-ढ3ग
@यशराज-ढ3ग 2 года назад
Me, who is solving frm primitive method and getting the answer 0
@nayutaito9421
@nayutaito9421 7 лет назад
My mind was blown infinitely away
@blackpenredpen
@blackpenredpen 7 лет назад
伊藤那由多 loll
@theomars1433
@theomars1433 Год назад
I don't get the 13:07 part, if b = 0, x doesn't matter anymore, coz bx is always 0, which makes e^(-bx) = 1, right? And I(0) is exactly what we're trying to solve.
@nostradamus9132
@nostradamus9132 Год назад
Yes
@alkankondo89
@alkankondo89 7 лет назад
The content on your page is always so informative, and your excitement for the math you show is contagious. By the way, have you considered making a Patreon page? I would gladly support! Also, how sneaky of you to wear the "Basic" shirt that has the lowercase-delta on it, foreshadowing the partial derivatives you use in the video.
@blackpenredpen
@blackpenredpen 7 лет назад
LOL! Thanks! In fact, that wasn't planned. lolllll
@jadegrace1312
@jadegrace1312 7 лет назад
Thats not a lowercase Delta
@rv1111
@rv1111 6 лет назад
Here comes the paid publishing
@yanzhenhuang9820
@yanzhenhuang9820 Год назад
博主听上去会中文❤❤bgm是陈奕迅的K歌之王~
@GusTheWolfgang
@GusTheWolfgang 7 лет назад
This was great!!!!!
@blackpenredpen
@blackpenredpen 7 лет назад
AugustoDRA thank you!
@uyangapuujee4508
@uyangapuujee4508 6 месяцев назад
⁠@@blackpenredpen what’s the concept of this Feynman’s method? I studied calculus but I don’t think I’ve seen this method and I wasn’t taught this. How do I know when to use and for what integrals? Please, I’m trying to understand it. I’m studying A-level maths in the Uk, if that’s helpful. Thank you 😁 also I love your videos! So good
@yu_gen47.
@yu_gen47. 5 месяцев назад
Me watching in 12th class Damn....🙂
@randompasserby4575
@randompasserby4575 7 лет назад
is there an integration bee where you teach? i think you'd be the guy to create a lot of fun (and probably cruel) integrals for students x)
@PatidarVivek
@PatidarVivek 3 года назад
I am a jee student can JEE ask that question please tell . I am shocked I cannot think it.
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