A Nice Square Root Math Simplification | How to solve!!! 

Задание решается устно!

In method 1, after cancelling √25 and obtaining (√3 + 1)(√3 - 1), here's one more option. Rewrite the 1 in the numerator as -1 + 2. "Distribute" division by the denominator. (√3 - 1 + 2) / (√3 - 1) = 1 + 2 / (√3 - 1) = 1 + 2(√3 + 1) / ((√3)^2 - 1)l^2) = 1 + 2(√3 + 1) / 2 = 1 + √3 + 1 = 2 + √3.

My solution: Num= 5*(sqrt(3)+1) Den= 5*(sqrt(3)-1) by multiplying both num and den by (sqrt(3)+1) one obtains (4+2*sqrt(3))/2=2+sqrt(3).

2+V3. Устно.

2+√3

3:01 You say it's in the form of a "perfect square" here, but that's the wrong term. It's a "difference of two squares". A perfect square is an integer that has an integer square root. (√75+√25)/(√75-√25) √25(√3+1)/√25(√3-1) (√3+1)(√3+1)/(√3-1)(√3+1) (3+1+2√3)/(3-1) (4+2√3)/2 = 2 + √3

My answer: 2+ sqrt3

Mine solution: 1+1=3

2 is the answer

i ❤ Mathematics

Underoot3

75+25=100

2+\/3!

(√3 + 2) /(√3 - 2) = 5 + 4 √3

УСТНО😂

籠統

Примитив

I got 10. What did I do wrong.

My answer is 1/(1+ 3^0.5)

That's 0.