My online class on behavioral research statistics did not explain this process nearly as well as this video does. Thank you so much for the help. This is a great resource and I will recommend this to be used by my classmates as well.
I would really really want to thank you from the bottom of my heart that your tutorial is really helpful, definitely the best thing ever I have found, very easy to understand the whole concept, better than my professor, I attended all his lectures but could never been better to see this clip for less than 15 minutes! Thanks! : )
very clearly!!! oh how clear it is? Punky! think to some teachers at my school just sit there and click click click the slides!!!! thanks a lot for your teaching sir!
I haven't even taking statistics yet I'm just trying to teach myself but your videos basically teches me everything and your so good with detail thanks man your realy helping me out!
Professor, Could you please comment: When finding the p-value, you stated 1.83 is ".4664"? I see the z-score at ".9664" on the table & if you do 1-.9664, the answer is 0.0336, just the same as when you used ".5-.4664=0.0336". Is there a reason you subtracted .5 initially from .9664 to use ".4664"? Thank you in advance.
+Rwanda Reyes Your z-table is different from the one he is using. His table calculates areas less between the 0 and z. Your table calculates areas below z.
Did anyone else notice he took the mean in 1.83 on z table, as .4664 but my table said 46.64. What's the difference you ask? two decimal places. How can I calculate the right answer if he's jumping around making conversions and not telling us why? If this is a blooper, let me know peeps. It's about at 10:25
very very helpful video but could you please explain to me how you calculate or see the critical value on the z-table. I didn't really understand the 0,45... and with a 5% confidence is the critical value still 1,645?if not, how do you calculate that?thaanks
+FrostPulse the sample is greater than 30, the standard deviation is just the square root of the variance. other words put variance at 9000 and it fulfilled all the conditions at using the Z, not the t-test. Besides, professor Kaplan is PROFESSOR KAPLAN enough to not make such child trick "errors" . Thanks!