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Add the Fractions 7/323 + 2/27=? Fastest way is THIS! 

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How to add fractions without finding the LCD - fraction short cut.
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27 июл 2024

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Комментарии : 27   
@MrMousley
@MrMousley 6 месяцев назад
This was quite a straightfoward one for my 65 year old brain, and I am pleased that I was able to do the multiplications without a calculator .. which we were not allowed to use at school.
@tomtke7351
@tomtke7351 6 месяцев назад
when they talk about algebra they frequently talk about "apples and oranges." Fractions are same as denominators gotta agree; cannot add apples and oranges. In this case we have some "323's" and some "27's" that we want to combine. The surest way is to multiply 323 × 27.. (I'd guess this is easiest way too??) Next might be finding common multiples between 323 and 27 to attempt to find LCD .. lowest (least) common denominator. Thanks to John, I just recently learned that a number is divisible by 3 if its digits added are divisible by 3. Example; 27 => 2+7 = 9 and 9 ÷ 3 = 3✔️✔️. However... 323 => 3+2+3= 8 and 8/÷ by 3. Since 27 = 3×3×3 so there's no common factors between 323 and 27. So no choice but to multiply 323 by 27 and 27 by 323 i.e ((7/323) +(2/27)) => or ( (27/27)(7/323) + (323/323)(2/27) ) or ( (27×7)/(27×323) + ( (323×2)/(323×27) ) or ( ((27×7)+(323×2))/(323×27) ) or ( (189+646)/(8721) ) or 835/8721 The method John will detail is the "X" method of: (-1-) multiply left numerator by right denominator and add to (-2-) multiply right numerator by left denominator (-3-) divide that sum by both denominators multiplied together. SUMMARY: ((N.L×D.R)+(N.R×D.L))/(D.L×D.R) v e r i f y (7/323) + (2/27) 0.02167 + 0.07407 =0.09574 835/8721 = 0.09574 0 09574 =❤ 0.99574✔️ FINAL ANSWER 835/8721 DISCUSSION: I the world of electronics and electricity the resistor is a basic element.... the very simple law/rule for electricity is called Ohm's Law. Simply voltage across the resistor, current thru the resistor and the resistance of the resistor are related: V = I × R maniplulated R = V ÷ I R// ohms V// volta I// amps if two resistors are in parallel, their combined resistance is: (1) / [ (1/R1) + (1/R2) ] so, if R1 =1000 and R2 = 5000 in parallel they form a circuit of = (1)/[(1/1000)+(1/5000)] = (1)/[(5/5000)+(1/5000)] = (1)/[(6/5000)] = 5000/6 = 833.33 Ohms manipulating fractions becomes a well known method when dealing with Ohm's law. Electronics gets REAL interesting when considering inductors and capacitors. These two devices result in a.c. current becoming 90° offset from their driving a.c. voltage. Recall sine and cosine are offset by 90°. In an inductor the a.c. current lags applied a.c. voltage by 90°. Because there's 90° offsets the use of the imaginary "i" is used but in electronics "j" is used instead. In a capacitor the a.c. current leads the a.c. voltage by 90°. to distinguish leading and lagging current the term used instead of RESISTANCE is REACTANCE. How an inductor reacts to (impedes current) from changing voltage is inductive-reactance. A capacitor is capacitive reactance. XL - inductive reactance XC - capacitive reactance Revise ohms's law V = I R to. V = I × XL (for inductor) V = I × XC (for capacitor) sidebar: a pure inductor is a SHORT for d.c. voltages a pure capacitor is infinite for d.c. voltages specifically XL = 2(pi)FL XL increases with F F = frequency L = inductance XC = (1)/[2(pi)FC] XC decreases with F F = frequency C = capacitance Ohm's Law Still applies: V = I × R V = I × XL V = I × XC OLD AS NOAH is the learning aid: ELI the ICE man. E (voltage) in L inductor leads I I in C capacitor leads E (volts) always by 90°
@user-ri6rn7ti5h
@user-ri6rn7ti5h 6 месяцев назад
I got the same answer to
@saberconstruction7224
@saberconstruction7224 6 месяцев назад
Great way to do it. Thanks.
@ChaosPod
@ChaosPod 6 месяцев назад
You don't need to know the prime factors of 323, once you know it's not divisible by 3, you know it shares no common factors with 27, so the only thing you can do is multiply the 2 denominators.
@Patrik6920
@Patrik6920 6 месяцев назад
..well thers a trick for that too... u can always write numbers as a sum of two numbers.. even fractions say u have 323/27 -> (321+2)/27 -> (107/9) + (2/27) = (105 + 2)/9 + 2/27 -> 35/3 + 2/9 + 2/27 = (33 + 2)/3 + 2/9 + 2/27 -> 11/1 + 2/3 + 2/9 + 2/27, LCD = 3 note: a/b + c/d is equal to (a/b)+(c/d) .. parenthesises r omitted (a/b and c/d are grouped) + is plus not obelus
@quigonkenny
@quigonkenny 6 месяцев назад
​​@@Patrik6920Don't really understand the point of this. You can tell that 323 isn't divisible by 3 just by adding its digits together. If they don't sum to a number divisible by 3, then the number isn't divisible by 3. (Same works for 6 and for 9.) Once you know the numbers share no factors, you can just use the bowtie method. You don't even need to check whether you need to reduce once you get your sum or difference, because since the two denominators share no factors, then as long as the fractions were reduced to begin with, there are no multiples of their respective numerators that when summed or subtracted will result in a number that has the same factors as either of the denominators. You can see this later point fairly simply with the above example. Your first numerator after bowtie, 7×27 = 189 is only divisible by 3, 7, 9, and 27. Your second, 2×323 = 646 is only divisible by 2, 17, 19, and 323. Neither of your numerators share any factors with the other. If you're adding or subtracting a number that is divisible by x to a number that is not, it is impossible to then result in a number divisible by x. It's probably most obvious to see with 2. If you add any odd number (a number without 2 as a factor) to an even number (a number with 2 as a factor), you can't then end up with another even number. Note that this may not be the case if adding or subtracting more than two values. Tl;dr: simplify/reduce _before_ you do the bowtie method and you won't have to do any further simplification/reduction.
@Patrik6920
@Patrik6920 6 месяцев назад
@@quigonkenny yup... was just adding wider perspective ... in the example it would be usless...
@GaryBricaultLive
@GaryBricaultLive 4 месяца назад
The word "sum" means adding together. And sum is a noun and not a verb. You should say, if the sum is not divisible by 3, the the number is not divisible by 3.@@quigonkenny
@robinblanc8208
@robinblanc8208 6 месяцев назад
Thank you!!!
@danieloblinger1199
@danieloblinger1199 6 месяцев назад
Your method is no easier than the one I learned 75 years ago.
@russelllomando8460
@russelllomando8460 6 месяцев назад
got it cross multiply - thanks for the fun
@KateSuhrgirlPlays
@KateSuhrgirlPlays 6 месяцев назад
189/646 after cross multiplying. If you take that fraction is ends up becoming a decimal of .2925 and so on which is 29 percent. Wait cross multiply is only when the plus is a division symbol I think. So i was close i just need to take what i have as my numerator and denominator and add them together and make it the new nominator and then do the last step of bowtie to flget correct dominator.
@rodrodrigues5402
@rodrodrigues5402 6 месяцев назад
Much better when it does not say that many will get it wrong
@aryusure1943
@aryusure1943 6 месяцев назад
Since we were allowed to use our calculator it was not that impressive IF we know the bow tie method. But I'll take the compliment anyway because I need all the encouragement I can get in my maths adventures. :)
@terry_willis
@terry_willis 6 месяцев назад
835/8721
@panlomito
@panlomito 6 месяцев назад
No way to simplify these fractions so let's BOWTIE them: Denominator = 323 . 27 = 8721 and numerator = 7 . 27 + 2 . 323 = 189 + 646 = 835 So the answer is 835/8721
@GaryBricaultLive
@GaryBricaultLive 4 месяца назад
The fastest way to do this problem is not waste over 15 minutes on extraneous examples and get right to the point. The quickest explanation is to cross multiply since there is no simple LCD for these two fractions. And then you are done.
@georgemalkin6546
@georgemalkin6546 5 месяцев назад
Cross multiply, never heard it called bow tie method, you live and learn . Guess that's the difference between math and maths.
@allentiska9338
@allentiska9338 6 месяцев назад
Stop saying Ok!
@tomtke7351
@tomtke7351 6 месяцев назад
ok
@saberconstruction7224
@saberconstruction7224 6 месяцев назад
South Park OK!
@margritkaminsky1470
@margritkaminsky1470 6 месяцев назад
All his seemingly unnecessary babble gives me time to work.
@tomtke7351
@tomtke7351 6 месяцев назад
@@margritkaminsky1470 babble is for those who don't already know. If you already know then either (-1-) increase playback to 2x, (-2-) fast forward to skip unneeded, (-3-) both (-1-) & (-2-)
@user-gd9vc3wq2h
@user-gd9vc3wq2h 6 месяцев назад
18 minutes about "the fastest way"... 😂
@user-ri6rn7ti5h
@user-ri6rn7ti5h 6 месяцев назад
7/323×2/27 189/646
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