AS Level PHYS 9702 PAPER 2 | May/June 2023 | Paper 23 | 9702/23/M/J/23 | Full and Detailed Solution 

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Glad it helped!

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Thanks for the sub!

Amplitude = 2.8 cm *(0.20 V/cm)=0.56 V , cm in the numerator is cancelled with cm in the denominator so no need to convert .

sin(theta)= Cos(theta ), if we divide both sides by cos(theta ) then sin(theta)/cos(theta) =1 and sin(theta)/cos(theta) = tan( theta) , Hence , tan(theta) =1 or Theta=arctan(1)=45 degrees . In short , if sin(theta) = Cos( theta ) , then Theta should be equal to 45 degrees . Hope it helps , feel free to ask if you have more questions .

Upthrust = roe(w)V(w)g= density of fluid * volume of fluid displaced * g , as in this case sphere is fully submerged so volume of fluid displaced = volume of sphere that's reason V(w)=V(s) . Hope it makes better sense now , let me know if you have any questions .

In the question statement , it's mentioned that initially there is a minimum ( node) at the position of microphone and then as microphone is moved it passes through 3 antinodes ( maxima ) and at the final position of microphone there is also node (minimum ) i.e Initially Node - Antinode -Node -Antinode -Node -Antinode - Node . In short we need to draw a stationary wave which starts at node and ends up at node as well and between first and last node there must be three antinodes . In the video , i have sketched the wave containing 4 nodes and 3 antinodes . Please watch video again , it should be clear to you . Feel free to ask if you still have questions .

First of all , just imagine if an object is moving upwards in the air the direction of air resistance will be downwards ( coz object will push air particles in upwards direction and air particles will push object in downwards ( action and reaction forces ) . In the question , sphere is moving upwards in the water so sphere will push water particles upwards ( action ) and as a reaction particles will push sphere downwards ( reaction ) . Hence , sphere will experience downward force ( drag ) . Air resistance = Drag ( resistive fluid in liquids ) . Hope it helps , feel free to ask if you still have questions .

It depends on question but in order to find angle we divide vsin(angle) / vcos(angle ) .

Voltmeter measures the potential change/differece across any components ( resistor , LDR , thermistor battery,and heater etc) .

generally sine , cosine and tan are enough .

Speed of stone is not constant so if you want to use t= s/v then v should be average speed and for contant acceleration 'average velocity' =v+u/2 = v/2 .If you use t=36/v/2 =2*36/v =2.70 s

Nope coz it has charge =(-2/3e-1/3e-1/3e=-4/3 e . uss can be a possible composition .

Sir wait... isn't antiparticle of upquark -2/3e?...and antiparticle of downquark is -1/3e...then can antiupquark+antidownquark+antidownquark be a combination?...i meant this on my previous reply... it's hard to write on keyboard

It's a possible combination@@farhanshah5966

I am assuming you are asking for b(ii) , Original length =1.9980 and total length after extension =2.003 so change in length =2.003-1.9980 =0.005 m .Strain =change in length / original length =0.005/1.9980 =0.0025 =2.5x10^-3 .

Let me know if you still have any questions .

Hello again! I’m sorry, I did mean b)ii). But I think my question was, how come for the stress question, the answer is 3.2x10^7 and not 3.2x10^6. Because I’m getting 3.2x10^6 in my calculator when i divide 30 by 9.5x10^-6. I’m sorry if this is a silly question 😅

Cross-sectional area =0.95 mm^2 =9.5 x10^-7 m^2 . @@caavery

@@alevelandapphysics-ali ohhhhhh okok I understand now. Thank you very much for your help! ☺️

It's a good practice and try to improve understanding of challenging concepts .

We are calculating total energy , total energy = Chemical energy = Total KE of all fragments

Thanks for pointing out , i'll adjust accordingly .

@@alevelandapphysics-ali thank you for the hard work, also in need of prayers. I got p2 and p5 today :)

All the best for your today's exams . @@wasiqszn9691