Calculate the Enthalpy of Vaporization (∆Hvap) 001

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How much energy would it take to boil 36.0 g of water at 100 °C? ∆Hvap = +40.7 kJ/mol
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1) Revell, K. (November 16, 2016) “An Interview with Heath Giesbrecht, Part I” The Macmillan Community community.macmillan.com/group...
2) Revell, K. (November 16, 2016) “An Interview with Heath Giesbrecht, Part II” The Macmillan Community community.macmillan.com/group...

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7 ноя 2012

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Комментарии : 11

@michaelarango 10 месяцев назад

super simple and straight to the point. Thanks!

@Joey-yo8mw 6 лет назад

great video! super helpful. Thank you!

@wejdanwaheeb8964 5 лет назад

So helpful, Thankyou.

@joshhowsmon9799 9 лет назад

thank you!

@SuhaibAl-ym3xd Год назад

not all heroes wear caps, man saved my life :)

@ShanaDiggs 10 лет назад

Can these same steps be used if you looking for the the energy to vaporize water instead of boiling it?

@simonegabellini6382 2 года назад

This is how to calculate heat of vaporization, not enthalpy of vaporization

@morganisles4222 Год назад

They are two names for the same thing, as far as I'm aware. The reason for this may be that enthalpy is the heat absorbed or produced during any process that occurs at constant pressure.

@simonegabellini6382 Год назад

@Morgan Isles yeah, i probably wanted to say that this is how you calculate the heat produced by the reaction, not the enthalpy, that is the initial dH=40,7 KJ/Mol in this case.