Thank you sooo much for explaining how to deduce the unknown variable mathematically...my professor is excellent but conveniently skips over these parts so I either have to go in for tutoring or am stuck. This really helped, as usual. You rock!
I just wasted 30 minutes trying to read and figure out how to do this and here you come again saving me with epic 20 second explanation, Thank you so much!!!
Hi, I just wondering how did you get p2= p1.e^(-dh/R).(1/t2-1/t1)? if ln(p2/p1) = lnp2- lnp1. how is it possible when P1 changed the side has multiplied by e^(-dH/R).(1/t2-17t1)? . Thanks very much Sir.
Here in the equation, we have an enthalpy of vapourisation and we have two state 1 and 2. So which latent heat should we need to consider state 1 enthaply or state 2 enthalpy. Please help me in this doubt.
So question... How to know whether to use the very first (base equation) and when to use the other equation to find another pressure. The questions look the same when I looked it up.
So when using the equation to find P2, the exponents to "e" are all divided by R? He found T2-T1, then multiplied by 24000 (Hvap), THEN divided by R. However, the equation was written as Hvap/R * (1/T2-1/T1)... Our tutor found 1/T2-1/T1, multiplied by Hvap, then divided by R, which would be (Hvap*(1/T2-1/T1)) / R as the exponent to e ... if someone can clarify that would be super helpful! Thx!
The molar heat of vapourisation of water is 9700cal/mol, what's the vapour pressure of 5 moles of water at 90°C (given that vapour pressure of 1 mole of water at 100°C is 78mmHg and the gas constant is 1.987cal/mol. Someone should please help with this question.
Isn't the enthalpy of vaporization changes depending on the temperature? How come there is just one value of enthalpy of vaporization between two different temperatures?
P1 is the pressure at the start with T1. When you change either P1 or T1 it becomes the second parameter of its kind. If you cange the temperature, the temp. you change it to becomes T2 with its own pressure P2
The 10^-3 is how many places the decimal goes to the left. The 0.003225 is the same number as 3.2*10^-3. It’s just in scientific notation instead of standard form. If, for example, the number were 3225.00 then the scientific notation would be 3.225*10^3.
Hi I've watched your videos and I've a question. I've examination in physics about a vacuum boiling water experiment by manipulating the pressure to a low point so the water in the bowl starts boiling at a low temperature. I've tryed to find some table or calculator that can somehow demonstrate that the result I've found is close to what we can see in tables eg. Are there any calculators (tryed to find some but they didn't work) or law that I can refer to? I hope that you can help? Best regards Mowaddat
It'd have been smarter to show the passages from the first formula to the others, and not giving all the formulas like they are different. What's the sense of learning all of them, you just need the first and you need to know how to reverse it. but yeah, just my opinion