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Calculate the pH of a Strong Acid and pOH, [H+] & [OH-] 

Anne Schmidt
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Learn how to QUICKLY calculate the pH, pOH, [H+] and [OH-] of strong acids. A list of strong acids will be given as well as molecular modeling of the dissociation reaction for strong acids. Practice problems will be completed and formulas to solve these problems will be explained.

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4 сен 2024

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Комментарии : 32   
@salmaaosman2829
@salmaaosman2829 4 года назад
I haven't seen anyone explain this as simply as you have so THANK YOU
@AnneSchmidt
@AnneSchmidt 4 года назад
Thanks! Glad the video helped you 👍🏻
@soniahshankoti6245
@soniahshankoti6245 3 года назад
Simple and straightforward Easy to understand
@AnneSchmidt
@AnneSchmidt 3 года назад
Thank you 😊
@KumoGhum
@KumoGhum 2 года назад
Thank you so much, your so good at explaining i wish my teacher was as good as u
@AnneSchmidt
@AnneSchmidt 2 года назад
Awww 🥰 thank you! Glad you are finding my videos helpful.
@angeleerivera1690
@angeleerivera1690 2 года назад
Super helpful! Loved the visuals, thank you so much!
@AnneSchmidt
@AnneSchmidt 2 года назад
Thanks 😊 Great to hear the video was helpful
@lallal7528
@lallal7528 10 месяцев назад
Leaving a comment to appreciate the work and the creativity. Helped out
@AnneSchmidt
@AnneSchmidt 10 месяцев назад
Much appreciated!
@asifulalamc
@asifulalamc Год назад
Great video! Merry Christmas and Happy Holidays!
@AnneSchmidt
@AnneSchmidt Год назад
Thanks! Have a wonderful holiday season.
@lightdi-gw6gn
@lightdi-gw6gn 11 месяцев назад
You're so talented! Thx for this video :) 🥰
@AnneSchmidt
@AnneSchmidt 11 месяцев назад
Aww ☺️ thank you for that!
@martinakubuo3398
@martinakubuo3398 3 месяца назад
Thanks a bunch.
@AnneSchmidt
@AnneSchmidt 3 месяца назад
You're welcome! ☺️
@ltac8194
@ltac8194 Год назад
Your videos are a god send. Thank you so much. My question is for # 2 . I got log(2.51) = .399673721 and doesn't the ph=-.400 because 3 sig fig and the 9 rounds up?
@AnneSchmidt
@AnneSchmidt Год назад
Thanks! Log calcs have different sig fig rules I discuss in the video.
@m.veyselakin
@m.veyselakin 4 года назад
thank you very much ! i liked the video
@AnneSchmidt
@AnneSchmidt 4 года назад
Glad you liked the video!
@Dodo-ym8cc
@Dodo-ym8cc 3 года назад
I have a question for Anne Schmidt: What happens to the Kw water equilibrium when a strong acid fully dissociates and you get loads of H+, does it disturb the water Kw equilibrium, if so in what way? Thank you for your time.
@AnneSchmidt
@AnneSchmidt 3 года назад
Typically only a change in temperature alters the Kw value.
@Dodo-ym8cc
@Dodo-ym8cc 3 года назад
@@AnneSchmidt Could there perhaps be an implicit heat component in the Kw equilibrium like for example Kw= [H+] [OH-] / Heat? If you get an abundance of H+ which depletes OH- to the extent that there is "practically" no more OH- left for the abundant H+ to react with, could that increase the heat component thus increase the temperature thus change the Kw constant itself? I never took chemistry that is why i am asking. Thank you Anne for your reply.
@dnyyyyyx1036
@dnyyyyyx1036 3 года назад
thankkk u so much!!
@AnneSchmidt
@AnneSchmidt 3 года назад
Great to hear the video was helpful ☺️
@user-ql6eu2gl2j
@user-ql6eu2gl2j 4 месяца назад
Thanks anne
@AnneSchmidt
@AnneSchmidt 4 месяца назад
Thank you for the comment. Happy to hear the video helped!
@selwyntiongson70
@selwyntiongson70 4 года назад
How about pkw pka ma'am and the general formula, how to derive it
@AnneSchmidt
@AnneSchmidt 4 года назад
pKa = - log Ka 10^-pKa = Ka pKw = - log Kw 10^-pKw = Kw
@selwyntiongson70
@selwyntiongson70 4 года назад
Pink calcu
@shikamarunara2034
@shikamarunara2034 2 года назад
?
@charlieropesocks5793
@charlieropesocks5793 4 года назад
mister green
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