This video on acids and bases shows you how to calculate the pH, pOH, [H+], [OH-] of acid and base solutions. Acids and bases can be measured by their strength of pH and pOH. Tune in on this awesome acid base video.
just wasted 2 hours of my life in lectures listening to my teacher and i cant make out what they on about, 11mins with you just cleared it up to my understanding. thanks sir
honestly we need more people like you in the school systems. You get to how to go about doing the problems in a very direct and expect manor, thank you so much!
I have to thank you SO much for teaching the acid/base equations this way. It was incredibly helpful. With so many formulas to learn, this method puts everything into perspective and so much easier to understand. FINALLY the pH formulas make sense and are clicking! Thank you thank you!!
KhaoticKlitoris Thanks for the kind words. I actually tried really hard to make that vid simple and thorough, which is not easy. Check these out for extra practice ru-vid.com/group/PLNc_BreVXbmoXmonRH7IJAR2RqzKJcZM-
I know this is late, but I noticed there were SEVERAL of you that didn't understand Mr. Post's Step 4. I am right along with you. Seeing that he didn't answer any of the other posts, I took it upon myself to look it up and figure it out. Thought I would share because I know there will be others that are just as confused. Okay, so on step 4 we are also solving for the inverse, or antilog of 10x -11.6 (or maybe just 11.6) Still just a little confused....sigh... Hope this helps. Follow these steps. I have a TI30XIIS scientific calculator and solved it in this manner. 1. Press (2nd) 2. Press (Log) 3. Press (-) 4. Press 11.6 5. Press " ) " to close the parenthesis. 6. Press (=) or (Enter) That gives you the inverse or antilog of -11.6 which gives you 2.51 x10-12. The number of H+.
THANK YOU SO MUCH! My professor didn't explain this very well even though it will be a major portion of our final exam. I'm so grateful for this easy explanation. I just have to memorize the formulas and I will be golden for the exam. Thank you, thank you, thank you!
Dear SciencePost: You have to emphasize that those Equations/Formulas are only valid IF and ONLY IF the Temperature is 25-degrees Celsius / Room Temperature, and those equations are not valid if the temperature of Water or Aqueous Solutions is not at 25 Celcius. Thanks for the Video, Sir !
Chelseay Helka Thanks for the kind words. Honestly, it takes a lot of practice and self reflection, to be able to figure out how to break this stuff down. I'm glad my method worked for you! Best wishes!
Thank you very much,you know I was just trying to understand what I wanted to and go offline but then something touched my heart to say thank you to the person who did this video,because it really helped. Thank you very much May God continue to bless you as you continue doing what you are doing to help others💕😊
thank god... i was trying to calculate pH as per my online lecture describes it: pH= -log10(H+) I didn't understand that I didn't need to put in the "10". I spent 30 minutes trying to figure this out before finding you and seeing my error in 5 seconds.
Hi, I was just wondering about your answer for [OH-] in the question "Calculate the pOH, [H+] and the [OH-] of a HCl solution with a pH of 3.2?" What I was wondering about, because I am taught to be very specific, is your final answer to [OH-], which you got as 1.58x10^-11 which shouldn't it have been 1.587301587x10^-11 => 1.59x10^-11 (3sf) ?
how did you get 2.51 x 10-12 on the inverse log? I cant figure out how you calculated this. Can someone please explain this to me? This makes no sense. ;(
You did a great job on this video. I'm not always sure how to use my T1-84 C Silver Plus calculator. So, why not buy one and do a whole video just on using that? I'm sure you would do an awesome job. Considering there isn't much out there on using the calculator, but you did a better job than most! Thanks. :) BTW, you cleared it all up on this topic. So thanks so much! M.
Mallory Durrick Merlino LOL. Great idea on the video, but I'm not familiar with that one. I literally use one like the screen showed. Check out my other vidson this topic if you need more help. Thanks for tuning in :)
Well, you got me there anyway. Also, the next day, the teacher showed everyone how to find the -log and antilog on their calculators but I learned from you so I didn't need the help. Passed the test too! Final is tomorrow.
Thank you. This is better than my Science Teacher. Also watching your last video. You said "Dude" so much, I facepalmed everytime near the end of the video XD
I wish you would have explained how you calculated step 4. makes no sense to me. im super confused and you dont explain how you calculated that number. i cant get that on my calculator. maybe you calculated wrong?