Calculating pH from [OH-] hydroxide Concentration - CLEAR & SIMPLE 

Please don't ever stop making videos I spent hours today trying to comprehend my teachers powerpoint and almost gave up on my exam tomorrow. I immediately understood EVERYTHING just from watching your video just one time. Thank you!!!!!

This video just washed away all the confusion in my head. Thank you 😊

I should link this video to my chem teacher so they could learn a few things from you xD. Thanks for the great informative video.

OMG after several weeks I understand this thing in a 9 minute video!! You are really really awesome

thank you very much :) I got it after just 9 minutes watching this.

I think at 4:47 sir. Think the power of 10 should be -13? I tried 10 to the power of -14 it gave me 13.5

Thnq so much, have been surfing online for a long time, I wished I found this video long back 😊

Absolutely genius! RU-vid videos are the best learning tools. Thanks for this teaching video, finally, I've got this yaaay:-))

Chemistry in plain English! Awesome Dude!!

On the 3rd example I do not know why I can't get the concentration correct. Not doing it right on my calculator?

Thank you soo much it is great 👍 explanation easy to understand first time

Thankyou! Perfectly explained

thank you for great explanation.

i tried two different calculators and still ended up with 2.86x10^20 after dividing.......so confused

I think you meant to put a -13 in the last step because then you come out with 12.5. -14 gives you 13.5

I found a short cut to this. Use the simple formula from the beginning of the video pH= -log [the given concentration] then solve. Then subtract your answer from 14 and you will only be about .1 or .2 off it i is a lot quicker, try it! :D

Hello,in the first problem i kept trying to calculate the 2 times 5.7 X 10 to the -7th a couple of times and i kept coming up with 1.14 x 10 to the -6th. I put it in like this: (5.7 X shift log-7(2)) =1.14 X 10 to the -6th. I cant see how you got 1.14 X 10 to the -9th,can you plz explain.Thanks!

How is it possible that a base have acid character, third one has ph value 5.95

Thnx dude..... it was super helpful!!!🔥🔥

Thanks...This vid helped a lot :D

You Are The Man, Great Job

You are very cool, thanks

Great video

So the 10^-9M Mg(OH)2 solution is in fact *acidic*???

What is the value of log?

Nice video. Next time, could you use sig. figs?

If you want to know, how to properly and *correctly* calculate the last example with dilution of base, go to this link: www.researchgate dot net/post/What_is_the_pH_of_very_diluted_for_example_hydroxide#view=5dfc383f2ba3a1661305ce8c Because obviously base cannot have pH lower than 7.

THANK YOU!

Thanks this helped so much! :D

thank you so much

this is literally basic algebra

Thanks boss!

hey dude

you rock!

Example 3 is conceptually incorrect. With a concentration that low of a base how did you end up with a pH of below 7. Makes no sense. There is a another calculation that must be used when concentration is that small. Educate yourself.

Mistake!!!!!!

awesome video