Can you beat Super Meat Boys Dark World with randomized characters? (2/2) 

Yes he got his redemption arc, such a reliable guy

He really is, Flywrench makes part of the salt factory dark world levels easier

THATS MY BOY RIGHT THERE!

10:22

​​@@Jenb1317110:59

10:55

10:40

Lads you don’t need the time stamp three times

Mr. Iceberg!?!?!?

Actually considering the fact that he completed 100 levels (and ~100 rolls) the odds are more like 40% Here's my maths, I hope it works out bc it's 04.30 and I'm tired. 1-0.0051=0.9949 (find probably of it not happening) 0.9949^100=0.60 (raise to the power of the rolls) 1-0.60=40=40% (find the probably of it happening)

@@theunholybanana4745 yea, if you consider that he did 100 tries, then your even more right. But as a little correction, there more like 98 rolls, bc he needs 3 rolls to be same, and 99 and 100 roll are already impossible to get 3 in a row, but still yea, everything else good i think

@@Happy_Flappy_ I added the 2 rerolls back tho so it goes back up to 100

In another comment, I wrote that I made a computer simulation and reached the conclusion that there is a more than 90% chance of getting the same character 3 times in a row.

@@Tumbolisu i think you mean that there is a more than 90% chance of NOT getting the same character 3 times in a row

Was looking for comment like that. Completely agree. Also funnily enough, there are exactly 196 possible 3-level streaks in light and dark challenges combined, so 3-hero-streak would happen 1 time on average if someone were to repeat such challenge. Meaning odds weren't quite lottery winning here. It was pretty likely to happen. (not guaranteed, but likely)

ALSO ITS OUT, YOU’RE SUCH A GOOD RU-vidR

I don't think so, given how Steve can cheese every level. Unless Steve was banned, or you started from a fresh file. Then it would be interesting

@@TheGamingLegendsOfficial true

@@ultraflanfancan you provide a link? I don’t see it in this RU-vidrs channel, if so thanks

@@ultraflanfanwait is it the one by chonney24? If so then I think I found it

💀

24:54 mans last words more bullets than in a classroom

You are close, but not really correct - you are forgetting that probability of 3 equal characters in consecutive triplets is NOT independent. You can check it for 4 levels: your logic gives probability of 391/14^4 when the correct answer is 378/14^4. To get the correct value, we need to solve some recurrent equations: let P(n,1) be the probability of n levels without a triple and different characters in last 2 levels and P(n,2) the same but with equal characters in last 2 levels. Then P(2,1)=13/14 and P(2,2)=1/14. Those recursive equations hold: P(n+1,1)=13/14*(P(n,1)+P(n,2)) P(n+1,2)=1/14*P(n,1) After a lot of linear algebra we get a crazy precise result of P(n,1)=((13-14B)*A^(n-1)-(13-14A)*B^(n-1))/(14*(A-B)) P(n,2)=P(n,1)=((13-14B)*A^(n-2)-(13-14A)*B^(n-2))/(196*(A-B)), where A=(13+√221)/28 and B=(13-√221)/28. Precise probability of at least 1 triple in n levels is therefore 1-P(n,1)-P(n,2)=1-((14A+1)*(13-14B)*A^(n-2)-(14B+1)*(13-14A)*B^(n-2))/(196*(A-B)). B is actually almost 0 so for higher number of levels (5 or more is OK) the second part of the numerator is negligible and we can very precisely approximate the probability of at least 1 triple in n levels as 1-0,9997*0,9952167^(n-2). For 100 levels this gives ~37,5%. But do not forget that he has actually played 200 levels, so it should be ~61,3%. So it is more likely that you get at least 1 triple than not! 😀

Yes yes yes!

It's not "newer" versions but instead console versions, Xbox 360 was the first version to release and had those characters

Gish is exclusive to Xbox version