Card At ANY Number - Impossible Card Trick Performance/Tutorial 

Thanks sm for the like Nathan🥰 Would love to be friends🥰

Damn bro 💀

Billy are you still a fan of the Gaffer? I have not seen your comments on peters channel in a long time. Just wondered. Hope everything id going fine for you!! Take care. My friend. Gary in dreamland. Have a nice dream!!🙂🌟🌟🌟🌟🌟🌟🌟🌟🌟🌟🌟🌟🌟

I use iMovie to edit and Snappa for thumbnails

@@AMillionCardTricks Thanks

I appreciate your thinking, but I’m afraid your idea simply makes no sense lol. Imagine if a spectator typed in 3x6x9x7x4x5 and hit equals and saw the answer was 27. Anyone who passed 3rd grade level math would know that’s completely incorrect. Even if you limit them to choosing any two numbers, most people know their times tables memorized. If they typed in 7x8 = 27, most people would agree that looks odd.

​@@AMillionCardTricksI was trying to see the rationality in his explanation but with all due respect it would only work on small children like 6 or younger 😅

Yes I forgot to mention! You can briefly show the spectator the faces of the cards, the bottom 20 cards that are not in the setup you can show freely

@@AMillionCardTricks thank- you for reply!! Excellent content;one of my favorite channels!! Gary in dreamland.Have a nice dream!🙂☁️☁️☁️⛅💫🌟🌟🌟🌟🌟🌟🌟🌟☁️⏰☁️ dream!!

A very bold false shuffle that I intend to start using. Just not on camera lol.

I've been watching since he was 14

Yes. Just came to read the comments to see if someone would suggest that idea. Good one.

@@tomi71 I would advise against that for two reasons. One, it adds an extra mathematical step which can tire the spectators attention span (I know its just simple addition, but its just more streamlined if you have them total the initial answer's digits and stop there.) And the second reason is that method would literally reveal the trick. If the spectators were curious and wanted to test the trick out again for themselves on a calculator, they would reveal the fact that 9 will always be a forced outcome and the trick is ruined. The fact that I leave at least 3 options in my version makes it more difficult for them to backtrack (even if they find out its always 3 numbers, then how could it have been a direct hit...?)

That outcome will never happen if you simply tell the spectator to type in a random assortment of numbers.

We know

Wasn’t including the card control in that statement. All I meant was the mathematics are self working

I understand the distinction BUT "it's honestly a self-working card trick" were the words you used.

What do you mean

Hey bozzo, what a stupid comment. Obviously when performing this to an actual crowd, you would use misdirection and different angles to make sure they wouldn’t see. The spectator would roughly see the shuffle in their peripheral, and more importantly hear the sound. This would be very convincing. I suggest you change your world view and give people chances. This kind of outlook will get you nowhere in life. I wish you the best of luck as you get the help you need.

@@ImSamKnight I just said that I saw that he doesn't mix the cards. I don't know what problem you have with your ego that it affected you personally. 😄

Are you a magician?