A lot of my work revolves around L/L extraction yet I just learned something new watching this video! I have never had any instructor who could explain the fundamentals this well in less than 30min!
Okay, I'm watching this and loving it because I understand what the speaker is saying, only to realize this is same voice that helped me through organic chemistry vis-a-vis Great Courses! Thank you Prof Davis. Can you do a full series on analytical chemistry?lol.
Hi Emily! I'm so glad you discovered my Great Courses project and my well-hidden channel that I use for my courses at Georgetown. I suggest you also check out my other channel ru-vid.com for many more short explanations and animations. Analytical chemistry would be a fun challenge to adapt for a Great Courses product. Maybe someday.... :-)
Ronald Davis you always explain very well! literally,now i have started liking experimental techniques in chemistry,my second chapter of Fsc part 1,just coz of ur videos. :*
This is a really good video with clear explanations behind the liquid-liquid extraction. Thank you for taking the time to explain and upload. Thank you.
I am doing an experiment on this the day after tomorrow. And honestly I was very stressed about how this whole extraction worked. We always get tested on our knowledge before we can participate on the actual experiment. I am very glad to fine this video. Hope that you have the other analytical methods on your channel as well~
Awesome!!! It saves my considerable amount of time and looking at other ways to extract the solute from a solvent with controlling and levelling the pH. Thank you, sir.
Thank you for the helpful video! Well explained! Just some things i picked up on: - 7:08 states K= 1.25, when I do the calculation I get a1.324..not sure if i am doing something wrong - to work out how much phenol we can get, i did (8.83/1000)250 and (6.67/1000)*250 and divded the concentration of solute in benzene and water to see if K is constant. Which means I get 2.0775g of phenol. So I am slightly confused with the (x/250)/(1-x/250)=1.25 part...not sure how that was obtained I am sorry in advance if I have made an error!
I'll take a stab at an answer for you. In answer to your last comment, the 1.25 comes from comparing the solubility of phenol in benzene vs phenol in water. Where the terms x and (1-x) come into the equation is that the any phenol molecules that is dissolved in the benzene (x) will inherently not be dissolved in the water (1-x). It's sort of implicitly stated that x is the partition, and can only be between 0 and 1. As for the value 0.56, that comes from the following: 1. Take the original equation: (x/250)/( (1-x)/250 ) = 1.25 2. The 250's cancel out, leaving: x/(1-x) = 1.25 3. Multiply both sides by (1-x): x = 1.25(1-x) = x = 1.25 - 1.25x 4. Bring the x term to the left by adding 1.25x to both sides: x+1.25x = 1.25 5. Combine the x terms together: 2.25x = 1.25 6. Divide both sides by 2.25 to obtain x: x = 1.25/2.25 = 0.555... = 0.56
Good to know that Aquasant offers a tube probe with a free passage for liquid / liquid batch separation after extraction or continuous separation layer measurement with a bar probe. #interface #measurement #phase #separation #pipeprobe #ringprobe #sensor #aquasant #liquidphase #extraction #separation
hats off sir! your lectures are really helpful. :) my concepts have been cleared so well.i used to have a great prob in understanding these techniques,unless i watched this videos .
May u live long..v amiable video .plz cover the whole solvent extraction n its all types like countercurrent ,solid phase, metal extraction, batch extraction e t c
Can you tell me the absolute cheapest fastest way to treat and purify pyrolytic oils made from distilled waste motor oil something like an acid base reduction precipitation I have used sulfuric acid aqueous and lie methanol and lye ethanol and lie I have also used just methanol inline just ethanol and lye and water and lye all of these take a very long time to drop to the bottom almost 2 weeks usually work good but sometimes the diesel fuel is left hazy not clear has to be water washed some people use strong hydrogen peroxide well past 50% but I'm not able to acquire this chemical
Can you do this for most compounds? Do you just find the PKA and go from there? For example, I want to do this with myclobutanil, and also separately, malathion. Myclobutanil pka is 2.3
Sir...U are god ...Super...Rocked the video...Sir I have question for u...Sometimes after separation by using separating agent and ether ..The ether layer doesn't evaporate even on boiling...Why? Is there is any reason
Hi Manas. If I understand you correctly, you are suggesting that after extracting a compound into ether, the ether can be difficult to remove so as to collect the non-volatile solute. Assuming this is the basis of your question, it is possible for even high volatility solvents like ether and methylene chloride to be very slow to evaporate if they have high concentrations of solute. If you think back to introductory chemistry and colligative properties, you will no-doubt remember that high concentrations of non-volatile solute can reduce the vapor pressure of the solution to levels far below that of the pure solvent. I suggest rotary evaporation as a means of removing stubborn solvents to recover non-volatile solutes.
venting upside down is dangerous, why not just remove the stopper. what if you are working with something that can dissolve the stopper or something really toxic that can wet past the stopper.
the "higher polarity solvent" in liquid-liquid extraction is usually (but not always) water. Water has a potent molecular dipole and is a good hydrogen bonder. This makes it a good solvent for dissolving other polar molecules. In liquid-liquid extraction, there is always one solvent of very high polarity and one of very low polarity (otherwise the two solvents would mix together!).
Partition rate. Say its 0,5 for this example; If you were to extract once, you'd get half of your desired compound. you do it again to obtain another 50% of the 50% that remained in the beginning phase in order to get 75%. third step gives you 87,5,... Note that this is an example to show the reason you do it multiple times, i only took 0,5 to make ti easier to show
Im Australian and ive completed about 9 years of chemistry/pharmacy at university. I don't recall ever hearing anyone pronounce phenol as "f'Nol". I say, and have always heard, "fEe-noL". Accents and regional pronunciation are weird.
