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Clinical refraction 4 │How to start performing retinoscopy 

AP's Ophthalmology pearls
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16 июл 2024

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Комментарии : 17   
@psh_yo
@psh_yo 24 дня назад
Excellent video... Very easy to understand..
@manchikantivijayakumari9906
@manchikantivijayakumari9906 2 года назад
Thank you so much mam for teaching us refraction procedure. I follow your videos they are very helpful.
@RR-sv7gz
@RR-sv7gz Год назад
Excellent video
@Hasan-pt9wr
@Hasan-pt9wr 8 месяцев назад
This was really very helpful
@i.g.304
@i.g.304 3 месяца назад
incredible video.. thanks a lot
@ansarma659
@ansarma659 7 месяцев назад
Thank you so much mam💘
@user-nf1vx2rh8b
@user-nf1vx2rh8b 5 месяцев назад
Good and easily catching method
@dmdyahiya214
@dmdyahiya214 Год назад
Thank you mam
@sudhirdhyanidhyani9262
@sudhirdhyanidhyani9262 9 месяцев назад
Best
@abhijitha4604
@abhijitha4604 11 месяцев назад
Is rectinoscopy accurate maam?
@user-xn5mh5vr5q
@user-xn5mh5vr5q Месяц назад
🌹💚
@ARAV-bd4rh
@ARAV-bd4rh 2 года назад
Ma'am , can you make video about subjective refraction.
@ophthalmologypearls
@ophthalmologypearls 2 года назад
Sure thing
@Traveller530
@Traveller530 Год назад
If we are moving streak up & down , we are correcting 90 meridian?
@ophthalmologypearls
@ophthalmologypearls Год назад
By moving the streak up and down (in vertical meridian), we are determining the refraction in the vertical meridian
@Traveller530
@Traveller530 Год назад
@@ophthalmologypearls thank you for your response, got it. I have another question. When we do ret on model eye with dummy lens. Let’s say I got reversal in 90 meridian which mean I got reversal at vertical and aganist in horizontal 180 meridian. My ques is that when adding negative cyl in which position do I need to put axis of cyl?
@ophthalmologypearls
@ophthalmologypearls Год назад
Let me get this straight. I think you mean - After reversal and subtracting for distance and cycloplegic drug, you get a plus power in the vertical meridian & a minus power in the horizontal meridian. So if you want to put a negative cylinder (minus cylinder), we want that minus power in the horizontal meridian. We know that cylindrical lenses have their power perpendicular to their axis. So a negative cylinder has to be placed with its axis at 90°, for the effective minus power to be available horizontally
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