Cracking an Olympiad Algebra Problem | No Calculator Challenge

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Cracking an Olympiad Algebra Problem | No Calculator Challenge
In this video, we dive into the fascinating world of math Olympiads with a challenging algebra problem that we solve step-by-step-without using a calculator! Join us as we break down the problem, explore various solving techniques, and provide clear explanations to help you master complex algebraic concepts. Whether you're preparing for a math competition or simply love solving difficult problems, this video is perfect for you. Let's crack this Olympiad algebra problem together!
Topics covered:
Math Olympiad
Algebra
Algebraic identities
Algebraic manipulations
Expressions
Simplification
Exponents
Exponent laws/properties/rules
Long division method
Math Tutorial
Problem solving
Olympiad question
Math Olympiad Preparation
Factorization
Timestamps:
0:00 Introduction
0:28 Method-2
0:40 Substitution
1:05 Exponent laws
3:45 Algebraic identities
4:54 Factorization
6:35 Method-2
7:15 Long division
9:08 Method-3
11:10 Answer
#matholympiad #simplification #problemsolving #mathematics #challenge #mathskills #math #algebra #education #expression
📚 Additional Resources:
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Опубликовано:

30 июн 2024

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Комментарии : 10

@woobjun2582 12 дней назад

Thanks a lot for letting me know various ways of simplification, Sir ^.^

@mohammedsaysrashid3587 12 дней назад

Wonderful introduction clearly explained...

@piyathilakamuthunayaka7291 3 дня назад

I solved it .thanks

@user-ny6jf9is3t 12 дней назад

(5^15)+1

@stepankravchenko3235 12 дней назад

5^15+1

@woobjun2582 12 дней назад

Let t = 5^15, and the given E = N/D where N = t^5 +t +2, D = t^4 -t^3 +t^2 -t +2. Then, manipulating N N = t^5 +t^2 -t^2 -t +2t +2; N = (t^2)(t^3 +1) -t(t +1) +2(t+1); N = (t^2)(t+1)(t^2 -t +1) -t(t +1) +2(t+1); N = (t +1)[(t^2)(t^2 -t +1) -t +2]; N = (t +1)[t^4 -t^3 +t^2 -t +2]; that is, N = (t +1)[D] Therefore E = N/D = (t +1)D/D = t +1 E = (5^15) +1

@RealQuInnMallory 12 дней назад

( x ➖ 3x+2)

@lawrencehmurcik8905 11 дней назад

If we let N be 5^75 remain and ignore the remainder of N, and if we let D be 5^60 and ignore the remainder of D, then our answer is 5^75/5^60 = 5^15 which is wrong by 1/5^15 OR too small to care -- I am an engineer first and a mathematician second