dictionary in python | Lec-14 

x = {'A': 10, 'B': 20, 'C': 20} abs = {'A':2,'B':3} tot={} total=50 for key,value in x.items(): if key in abs: days = total-abs[key] tot[key] = days*x[key] else: tot[key]=total*x[key] print(tot)

manish can u make vdo for interview question for 2 year experience in data engineer

I was about to ask for the video and here you're with another one👏🏻

totalCost = [] for i in labour: if i == "Mahesh": Cost = 47 * labour["Mahesh"] elif i == "Sumesh": Cost = 43 * labour["Sumesh"] else: Cost = 50 * labour[i] totalCost.append(Cost) print(sum(totalCost))

labour_cost = {"Mahesh": 500, "Ramesh": 400 , "Mithilesh": 400, "Suresh": 300, "Jagmohan": 1000, "Rampyare": 800} total_working_day = 50 labour_absent_day = {"Mahesh": 3,'Jagmohan' : 7} total_bill = {} for key1,value1 in labour_cost.items(): for key2,value2 in labour_absent_day.items(): if key1 == key2: total_bill[key2] = (total_working_day - value2) * value1 break else: total_bill[key1] = total_working_day * value1 print("Total Labour Cost:",sum(total_bill.values())) print("Individual Cost:") for key in total_bill: print(key,total_bill[key])

l_w_cost={"mahesh":500,"Ramesh":400,"Mithilesh":400,"Jagmohan":1000,"Rampyare":800} total_cost=0 for i in range(0,50): for j in l_w_cost: total_cost=total_cost+l_w_cost[j] print(total_cost) #sub Jagmohan for 7 days for i in range(0,7): total_cost=total_cost-l_w_cost["Jagmohan"] print(total_cost) #sub Mahesh for 3 days for i in range(0,3): total_cost=total_cost-l_w_cost["Ramesh"] print(total_cost) 155000 148000 146800

labour_with_cost = {'Mahesh': 500, 'Ramesh': 400, 'Mithilesh': 400, 'Sumesh': 300, 'Jagmohan': 1000, 'Rampyare': 800} days_labour_worked = [47,50,50,50,43,50] price_list = [] for i in labour_with_cost.values(): price_list.append(i) total_cost = 0 for i in range(min(len(days_labour_worked),len(price_list))): total_cost += days_labour_worked[i]*price_list[i] print(total_cost)

Hi Manish, my solution: labour_with_cost = {"Mahesh":500,"Ramesh":400,"Mithlesh":400,"Sumesh":300,"Jagmohan":1000,"Ram":800} # print(labour_with_cost) labour_absent = {"Mahesh":3,"Jagmohan":7} for name in labour_absent: labour_absent[name] = -labour_absent[name] * labour_with_cost[name] print(labour_absent) Total_days = 50 for name in labour_with_cost: labour_with_cost[name] = labour_with_cost[name] * Total_days print(labour_with_cost) print(f"Total labour cost is {sum(labour_with_cost.values())+sum(labour_absent.values())}") Pls reply if we have better solution, Thanks.

hours_worked = 50 total = 0 labour_with_cost = {"Mahesh":500, "Ramesh":400, "Mithilesh":400, "Sumesh":300, "Jagmohan":1000, "Rampyare":800} hours_absent = {"Mahesh":3, "Jagmohan":7} for k in labour_with_cost: if k in hours_absent.keys(): total += labour_with_cost[k] * (hours_worked - hours_absent[k]) else: total += labour_with_cost[k]* hours_worked print(total)

My Solution of the Assignment labour_with_cost={"Mahesh":500,"Ramesh":400,"Mithilesh":400,"Samesh":300,"Jagmohan":1000,"Rampyare":800} total=(labour_with_cost["Mahesh"])*47+labour_with_cost["Ramesh"]*50+labour_with_cost["Mithilesh"]*50+labour_with_cost["Samesh"]*50+(labour_with_cost["Jagmohan"])*43+labour_with_cost["Rampyare"]*50 print("Total Labour_cost",total)

Manish Bhai, i am also working in Reliance Jio at RCP Ghansoli. I want to switch into data side roles but not getting calls. Please make a video on how to get data engineering interview calls. I am very very frustrated with my current job.

bhai can i get the json data list which you shown as example for nested dictionary

# Assignment - Total Labour cost if the total working days was 50 out of which Mahesh was absent for 3 days and Jagmohan was abesnt for 7 days. Find out the total labour cost. #I have tried this out without using for loop labourer_with_cost= {"Mahesh":500,"Ramesh":400,"Mithlesh":400,"Sumesh":300} print(labourer_with_cost) labourer_with_cost["Jagmohan"]=1000 labourer_with_cost["Rampyare"]=800 print(labourer_with_cost) print(" A: Total Labour cost for a day: ",sum(labourer_with_cost.values())) print(" B: Total Labour cost for 50 day: ",50*sum(labourer_with_cost.values())) print(" C: Total labour cost for Mahesh for 3 days: ",3*labourer_with_cost['Mahesh']) print(" D: Total labour cost for Rampyare for 7 days: ", 7*labourer_with_cost['Jagmohan']) print("Total Labour cost if the total working days was 50 and Mahesh and Jagmohan was absent for 3 and 7 Days respectively would be A*50 which is B minus (C + D) : ",50*sum(labourer_with_cost.values())- 3*labourer_with_cost['Mahesh'] - 7*labourer_with_cost['Jagmohan']) Output - {'Mahesh': 500, 'Ramesh': 400, 'Mithlesh': 400, 'Sumesh': 300} {'Mahesh': 500, 'Ramesh': 400, 'Mithlesh': 400, 'Sumesh': 300, 'Jagmohan': 1000, 'Rampyare': 800} A: Total Labour cost for a day: 3400 B: Total Labour cost for 50 days: 170000 C: Total labour cost for Mahesh for 3 days: 1500 D: Total labour cost for Rampyare for 7 days: 7000 Total Labour cost if the total working days was 50 and Mahesh and Jagmohan was absent for 3 and 7 Days respectively would be A*50 which is B minus (C + D) : 161500

Manish can you do a video on decorators. Thanks

from where to download this zomato data used in this video ?

bhaiya next time se thoda zoom karke code ka video banaoo na.Baki Best Video

Manish bhai nahi aara hai likhna.

Bhai tum Kaun se application pr pen tab use karte hai