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Discrete Math 9.5.1 Equivalence Relations 

Kimberly Brehm
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Please see the updated video at • Discrete Math - 9.5.1 ...
The full playlist for Discrete Math I (Rosen, Discrete Mathematics and Its Applications, 7e) can be found at • Discrete Math I (Entir...

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21 июл 2024

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Комментарии : 30   
@TheStillalivee
@TheStillalivee 5 лет назад
Even though I am a Turkish guy who studies in Turkey. Your videos are much more understandable than the Turkish tutorials. Thanks for keeping the topics this simple and easy to understand by giving relatable examples.
@ansonthedev
@ansonthedev 4 года назад
Amazing video. Wish I found your channel sooner.
@Ashley-ep2qm
@Ashley-ep2qm 3 года назад
Bless your heart ! Your videos are so helpful
@LuciaSilva-gw9ri
@LuciaSilva-gw9ri 4 года назад
Perfect, thank you so much!
@maryamali1818
@maryamali1818 4 года назад
if I pass this course, I will thank god and you.
@SawFinMath
@SawFinMath 4 года назад
Maryam Ali Be sure to use the new playlist instead. The videos are updated and I fixed any mistakes.
@maryamali1818
@maryamali1818 4 года назад
@@SawFinMath I will, thank you from the bottom of my heart
@medicalbommerbre
@medicalbommerbre Год назад
@@maryamali1818 did u pass
@OmKumar-js7jd
@OmKumar-js7jd 4 года назад
(Badiya) best classes 🇮🇳
@shreypatel9379
@shreypatel9379 3 года назад
Thank you for delievering such great quality lectures
@SawFinMath
@SawFinMath 3 года назад
So nice of you
@chaunguyenhuynhbao3472
@chaunguyenhuynhbao3472 4 года назад
Thank you so much !
@abdullahmoiz8151
@abdullahmoiz8151 4 года назад
excellent explanation than you very much
@antojosu
@antojosu 5 лет назад
Awesome Class
@mubarakahmed2488
@mubarakahmed2488 2 года назад
For mod 4 [1] - how's 7 a congruent when if you divide 7 by 4 the remainder is 3 I thought we were to look for number who remainder was [1]
@sabirkhosa1586
@sabirkhosa1586 4 года назад
thanks you so much mam its helping course because these are book example that are more understanable.
@noon8681
@noon8681 5 лет назад
Thanks bro
@leozhang1340
@leozhang1340 5 лет назад
for the last problem, P1 should also be a "yes", right? because every set contains an implicit empty set
@BenBrawn
@BenBrawn 4 года назад
no. Every set has the empty set as a SUBSET, but not as an element.
@franciscoribeiro2462
@franciscoribeiro2462 4 года назад
@@BenBrawn shouldn't there be brackets for it to be considered an element of the original set? For instance the empty set is a subset of all sets, but {empty set} is not a subset of all sets. Isn't it the same case here?
@BenBrawn
@BenBrawn 4 года назад
Kiko Ribeiro brackets or no brackets, nether is an element of the set given. Yes what you say is correct, the empty set {} is a subset of every set but {{}} need not be a subset.
@stephanewamba9610
@stephanewamba9610 4 года назад
at 3:01 it should be (a-b)+(b-c) is in Z
@SawFinMath
@SawFinMath 4 года назад
Stephane Wamba I fixed the example in the updated video.
@microlegions3101
@microlegions3101 4 года назад
Ma'am I have a doubt - is equivalence classes and partitions are exactly one and the same thing or they're different?
@SawFinMath
@SawFinMath 4 года назад
They are different. However some partitions are examples of equivalence classes, as shown in the video.
@microlegions3101
@microlegions3101 4 года назад
@@SawFinMath Thanks, Ma'am! You're such a blessing!
@mevlutkelle4083
@mevlutkelle4083 4 года назад
i love you kimberly
@dt615
@dt615 3 года назад
thank you maam, I wish you were my professor :((
@Mr_cheekz
@Mr_cheekz 3 года назад
GOAT
@sifisoleema2074
@sifisoleema2074 3 года назад
Hi pls help with this question (decide for each of the following relation whether or not it is an equivalence relation. Give full reasons. If it is an equivalence relation, give the equivalence classes. (a) let a. b be integers. Define aRb if and only if a 3 devises ( a-b) in other words R is the congruence modulo 3 relation....... Pls help
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