Your the best chemistry teacher ever! And I hate chemistry but the way you explain makes it all so easier and simplerYour a genius, thanks for uploading this!!
oooooh my. Im up all night preparing for my chem finals. While in class i just didnt understand the concept. And you worked different types of questions. It was clear. You're a life saver. Thank you. ^_^
Thank you for clarifying the molarity bit. Of the ~100 videos I've watched this is the first one that specifically mentions that only M's should be in the ICE table.
Fantastic method. However I prefer to think of out logically and use ratios to work this out. I kind of wish I knew this method in the first place, I suppose thinking of it logically is the superior way as it shows your understanding of equilibria.
I got something quite odd when redoing the question at 14:30 myself, with another technic. What I did was when we were at the 64 = [HI]2 / [H2] * [I2]. I simply placed the 2 réactants (the 0.2 * 0.2) on the side of 64. So I have 64 * 0.2 * 0.2 = [HI]2. So i square root the result of 64 * 0.2 * 0.2 and get the answer 1.6. How come the equilibrium for 2HI, when calculated (as I just did), is equal to 1.6 rather than the 0 that is expected?
Do you do it the same same if your two starting moles of H2 O2 were different? say instead of them both being .200M, H2 = .033 and O2= .0081 what would you do?
+Jamie Coleman The reactants (which I assume you meant H2 and I2, not that it matters) would have to change by the same amount so they still would change by "-x". 2HI would still increase by "2x". Therefore you would plug in these new values instead of .2. From there you would simplify the "64=" equation until you reached 60x2−2.6304x+0.017107=0. After that plug in the quadratic formula(If you don't know what that is go to this site here www.purplemath.com/modules/quadform.htm ). That should give you your answer for x. You will get two answers (.0359 and .0079) and it must be .0079 because .035 is greater than your H2 value. then just apply this to your ICE table giving you an HI value of .158. That is as far as my understanding is of this topic.
