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Even and Odd Decomposition of a Signal 

Adam Panagos
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We know that any continuous-time signal can always be decomposed into a sum of even and odd components, e.g. it can always be written as x(t) = xe(t) + xo(t) where xe(t) is an even signal and xo(t) is an odd signal.
A specific continuous-time signal x(t) is sketched in this video example, and then the equations for xe(t) and xo(t) are used to find the even and odd signal components of the signal.
The previous video in this playlist is:
Signal Operations Example #3 - • Signal Operations Exam...
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11 янв 2016

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Комментарии : 57   
@getsetdesign3333
@getsetdesign3333 7 лет назад
thank you adam, you are the best teacher. i had given up on this subject until i saw this video
@AdamPanagos
@AdamPanagos 7 лет назад
Don't give up, this entire area of information is very fascinating. Once you start figuring things out it's a lot of fun. Glad to help.
@ibrahimh.2828
@ibrahimh.2828 5 лет назад
Stumbling across your channel just saved my semester. Thank you!
@AdamPanagos
@AdamPanagos 5 лет назад
Thanks for the kind words! If you found the video useful make sure to check out my website adampanagos.org where I have a lot of other resources available and consider supporting development of new videos through www.patreon.com/agpanagos. Thanks! Adam
@vaikh8450
@vaikh8450 4 года назад
Thanks sir, glad to see a teacher like you . Doing a group work .
@360xi
@360xi 7 лет назад
I love your video!!!! Thank you for breaking everything down step by step!!!!
@AhmadTalkss
@AhmadTalkss 5 лет назад
Props to u man, it takes so much determination and effort to make these videos.!!
@Diaryofaninja
@Diaryofaninja 5 лет назад
Thank you sir. You're a valuable educator. I don't know how the kids before me grew up reading from textbooks, I understand much better with pictures and a "one-on-one" feel like these youtube videos provide that textbooks can't provide. I pretty much owe all my academic success to youtube haha.
@AdamPanagos
@AdamPanagos 5 лет назад
Thanks for the kind words. Glad I could help!
@AbhishekKumar-wm6nn
@AbhishekKumar-wm6nn 3 года назад
A very good explanation for a complex problem
@AdamPanagos
@AdamPanagos 3 года назад
Glad I could help, thanks for watching. Make sure to check out my website adampanagos.org for additional content (540+ videos) you might find helpful. Thanks, Adam
@leolorenzo52raylewis
@leolorenzo52raylewis 5 лет назад
your step process was clear and simple thank you!!
@ahmedbadia1485
@ahmedbadia1485 7 лет назад
Great Video, much thanks!
@jazminmosqueda8263
@jazminmosqueda8263 6 лет назад
thank you!!!! it's totally clicked just now!
@AdamPanagos
@AdamPanagos 6 лет назад
Glad to hear that; thanks for watching!
@ruibarbosa24
@ruibarbosa24 2 года назад
came looking for copper, and struck gold
@AdamPanagos
@AdamPanagos 2 года назад
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content (600+ videos) you might find helpful. Thanks much, Adam
@sriranganayakulugadey202
@sriranganayakulugadey202 6 лет назад
Thanks Adam sir best explanation that was from you
@AdamPanagos
@AdamPanagos 6 лет назад
Thanks for the kind words! If you found the video useful make sure to check out my website (adampanagos.org) where I have a ton of other resources available and it's easier to watch my videos in a more organized fashion. Thanks, Adam.
@h3avyw3ight9
@h3avyw3ight9 2 месяца назад
You just earned s subscriber
@swarupsarangi734
@swarupsarangi734 6 лет назад
very well explained ! thanks
@AdamPanagos
@AdamPanagos 6 лет назад
Thanks!
@mohammedirfanuddin4274
@mohammedirfanuddin4274 5 лет назад
Thanks alot, I was learning Fourier series representation , but i was so confused about even and odd compunent, as in terms of even bn=0 and in terms of odd an=0, Your video did clear my confusion for even and odd signel.Thank you so much.
@AdamPanagos
@AdamPanagos 5 лет назад
You're welcome, glad I could help. Thanks for watching!
@mohammedirfanuddin4274
@mohammedirfanuddin4274 5 лет назад
@@AdamPanagos my pleasure
@zak11elevenstudentaccount80
@zak11elevenstudentaccount80 3 года назад
i love you man, just save my a$$ with this video
@Kerozen911
@Kerozen911 7 лет назад
Excellent video :)
@AdamPanagos
@AdamPanagos 7 лет назад
Thanks!
@hycesar
@hycesar 7 лет назад
Hi there, when we have a imaginary part, like e^ix? Have we two decompositions for each part (Real and Imaginary)?
@varunsingh9432
@varunsingh9432 7 лет назад
please explain how to decrease this rectangle and triangle from 1 to 0 ,i am little confuse here in order to get after dividing from 2
@telugubudds1975
@telugubudds1975 6 лет назад
gud lectures ever seen
@zahirshah8748
@zahirshah8748 6 лет назад
Sir i want to ask that from which book u took this example ,plz must reply
@mohsenssalem9661
@mohsenssalem9661 6 лет назад
Hi Adam I am really interested in this video and it is very helpful. May I ask you a question? I am confused. How did you draw the signal and divided by 2 I don't understand it? Thank you.
@lpjtechno4612
@lpjtechno4612 Год назад
did you get an answer? I am also a bit lost
@Taucioks
@Taucioks 4 года назад
thank you
@AdamPanagos
@AdamPanagos 4 года назад
You're very welcome, thanks for watching. Make sure to check out my website adampanagos.org for additional content (435+ videos) you might find helpful. Thanks, Adam.
@thegreatworld5460
@thegreatworld5460 5 лет назад
Great 👍
@oshin7132
@oshin7132 5 месяцев назад
THANK YOU
@kaursingh637
@kaursingh637 4 года назад
excellent -excellent
@AdamPanagos
@AdamPanagos 4 года назад
Thanks for the kind words, I’m glad you enjoyed the video! Make sure to check out my website adampanagos.org for additional content you might find helpful. Thanks much, Adam
@divakarkeshri564
@divakarkeshri564 4 года назад
NICE
@pkboy546
@pkboy546 8 лет назад
adding the ramp to the rectangle is a bit confusing. can't complain though this is a thousand times better than my book...
@AdamPanagos
@AdamPanagos 8 лет назад
Just try to picture the rectangle being "boosted" by the rectangle. Just shift everything up by the height of the rectangle. Just takes some practice......
@pkboy546
@pkboy546 8 лет назад
yeah it took me a while but i think i see it now. thank you!
@nurhassen8191
@nurhassen8191 5 лет назад
thank you!
@AdamPanagos
@AdamPanagos 5 лет назад
You’re welcome, thanks for watching. If you found the video useful make sure to check out my website adampanagos.org where I have a variety of other resources available that you might find helpful. Thanks, Adam.
@md.muhibullahshah646
@md.muhibullahshah646 Год назад
bangali?
@shubhampatil.6861
@shubhampatil.6861 5 лет назад
Thanks
@AdamPanagos
@AdamPanagos 5 лет назад
You're welcome, thanks for watching.
@OmarChida
@OmarChida 3 года назад
Thanks
@souravuh4965
@souravuh4965 7 лет назад
very nice :)
@AdamPanagos
@AdamPanagos 7 лет назад
Thanks!
@TheWweweeklyshow
@TheWweweeklyshow 8 лет назад
I did not understand how you added the signals, also did not understand how you subtracted them, you did not really explain what you were doing well.
@AdamPanagos
@AdamPanagos 8 лет назад
+nabil samy I'm sorry you weren't able to follow the descriptions provided. Practically the entire video is dedicated to explaining how to add/subtract the two signals on a per-time-interval basis. I don't know any other way to explain addition/subtraction in a more detailed manner.
@TheWweweeklyshow
@TheWweweeklyshow 8 лет назад
It's OK, I'm just frustrated because I can't seem to understand anything today, but your lectures really are very helpful thank you!
@AdamPanagos
@AdamPanagos 8 лет назад
+nabil samy Maybe it would be easier to think of it terms of equations instead of the pictures I drew. If we have xe(t) = 0.5*(x(t) + x(-t)) we can compute the signal xe(t) one point at a time. For example, let t = -0.5. Then we have xe(-0.5) = 0.5*(x(-0.5) + x(0.5)) = 0.5*(1 + 0.5) =0.5*1.5 = 0.75. The values of x(-0.5) = 1 and x(0.5) = 0.5 I got by just looking at their plots. See how this value of xe(-0.5) = 0.75 is what we have in the plot for xe(t)? You could repeat similar computations for any value of t you wish (e.g. t = -1.5, 0, 0.25, etc.). Once you do this a few times maybe that will help things "click".
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