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Example for Finding Edge of Pavement Elevation | Horizontal and Vertical Alignment for Highways 

Daniel Findley
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CORRECTION: At 1:51 and 2:25, -0.183 should be -0.0183. The answer is correct, but the number is shown in the equation incorrectly (i.e., -1.83% is equal to -0.0183, NOT -0.183).
Determine the outside edge of pavement elevation at station 41+00 and the inside edge of pavement elevation at station 51+50. The curve has a design superelevation of 6.6%. The highway has a constant -1.83% longitudinal grade throughout this two-lane section with 12’ lanes, and the centerline of the highway has an elevation of 1,984.61 ft at station 38+00.
#HighwayDesign #DanielFindley #HorizontalCurve #VerticalAlignment #Superelevation

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21 сен 2024

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Комментарии : 4   
@2010bassmaster2010
@2010bassmaster2010 Год назад
Great example, but the problem statement should have made clear this way a SCS curve and that it was in 2% normal crown at each tangent. Keep up the awesome examples!
@FindleyDaniel
@FindleyDaniel Год назад
Thanks, I was trying to replicate the ways assumptions may need to be made - the image shows the spiral transitions and it's a common assumption for the normal crown to be 2%.
@layapannikottu996
@layapannikottu996 Месяц назад
Is there a material that I can refer to for understanding the basics of cross slopes. Is it mentioned in AASHTO Green book that the normal crown is assumed to be 2%. Why is the elevation and the cross slopes differently placed in the inner pavement when compared to the outer pavement? What is eRC in the diagram?
@FindleyDaniel
@FindleyDaniel Месяц назад
Yes, the Green Book has information on the basics of cross slopes and various jurisdictions have their own guidance as well. I have a series of playlists that might be helpful for you on this webpage: sites.google.com/ncsu.edu/daniel-findley/educational-resources Specifically, I have one dedicated to cross slopes that might be useful: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-uxUEwUMPXGw.html
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