Yeah (2x-3/(x-2)(X+1)) is the fully simpldyed expression, with V.As being X=2,-1, no slant, and H.A being Y=0, with an x-int of ((3/2,)0), a y-int of (0,(3/2)), and a hole coordinate of (1,(1/2))
Yo, why the frick is this man's smarter than my whole math department, my math center didn't know what they were doing, and when she said give me a sec to figure this out, I SAW HER LOOKING AT YOUR VIDEO!!!! u the real g Brian 😤💯🤜🤛
You do the public a great service with your videos. I've watched many. They're even on Amazon Prime! My only frustration is how FAST you go. I hit pause and back up a lot. I wonder if you teach AP kids. I really wish you'd slow down just a little... You're a very good teacher!
Yes,the first thing we got to do is to check if there are break points,or say to check if there are common factors of the numerator and the denominator
What is done at 3:59 is absolutely wrong. You cannot multiply and cancel the denominator function since the denominator function can take the value 0 (for x=2 or 1 or -1).