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Find position or velocity when given acceleration as a function of time 

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Dynamics Tutorial: Find position or velocity when given acceleration as a function of time.
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20 окт 2024

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Комментарии : 13   
@techwithtonny9837
@techwithtonny9837 Год назад
My friend you have done a wonderful job. I have been having a problem with the differentiation of those equations when I came across your content. Thank you soo much
@BoZhaoengineering
@BoZhaoengineering 5 лет назад
Very good videos! You set a quality criteria that the other engineering course can compare with and follow up. As an practicing engineer, I should refresh my knowledge by frequently visiting these video. I hate to hear that my colleague says I forget about them though I learnt them.
@Engineer4Free
@Engineer4Free 5 лет назад
Thanks so much Bo, I'm really happy to get this type of feedback =) =)
@viniciuscmeng
@viniciuscmeng 6 лет назад
Great channel, congratulations! Please keep up with the work!
@Engineer4Free
@Engineer4Free 6 лет назад
Thanks Vinícius! =)
@captainaryan26
@captainaryan26 Год назад
I have a vector ā = (4t)I - (10t²)j So at t=2 seconds, What will be the velocity ? 😣
@thebelieverkhan3741
@thebelieverkhan3741 5 лет назад
VERY good explaination man.
@Engineer4Free
@Engineer4Free 5 лет назад
Thanks!!! 🤩
@liaqatali1397
@liaqatali1397 6 лет назад
Kindly complete the dynamics course me and my friends are waiting for it. Thanks. Kindly reply when you are planning for it. Thanks.
@grizzzee
@grizzzee 2 года назад
This makes absolutely no sense to me. I even read your explanation to answer one question. What i dont understand that even if there is a negative acceleration, how would velocity still be increasing.
@captainaryan26
@captainaryan26 Год назад
Suppose I push an object and accelerate it with 2 m/s² in right direction. It is in motion now that I have pushed it. Well, during it's motion if I push it to the left direction with 2 m/s² acceleration. Then I gave it an acceleration of *-2 m/s²* Hence, the negative sign just indicates the opposite direction. The velocity was there when I pushed it in left direction. If acceleration is zero, then velocity is zero.
@COULGHOULLADY
@COULGHOULLADY 7 лет назад
this is really helpful
@Engineer4Free
@Engineer4Free 7 лет назад
Thanks for watching, glad to hear it!
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