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How Boost Converters Work (DC-DC Step-Up) - Electronics Intermediate 1 

Simply Electronics
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A look into how boost converters work in a very visual format. Try this circuit: goo.gl/nkHq9H
Boost Converter Wiki: en.wikipedia.o...
Software: Everycircuit.com
If you would like to support me to keep Simply Electronics going, you can become a Patron at / simplyelectronics

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28 сен 2024

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Комментарии : 759   
@billysunerson
@billysunerson 5 лет назад
It is SO hard to find videos that clearly explain the step by step function of a circuit. Thank you!
@cortez31
@cortez31 4 года назад
Thanks a lot, I'm studying mechanical engineering and whenever I come across electronics I tend to understand very little, but I've fully understood this circuit thanks to your video. Will definitely subscribe and try to learn more about electronics :)
@freeenergytransformer5842
@freeenergytransformer5842 2 года назад
Many electronic devices need more power than can be supplied by a battery or power supply. This is where a boost converter comes in. It takes the input voltage and steps it up to a higher voltage, supplying the necessary power to the device.
@organicfarm5524
@organicfarm5524 Год назад
Contrary to that, electrical engineering students understand mechanisms/machinery easily. I think it's because of that fact that mechanical engineering is physically more relatable than electrical engineering.
@bungle6334
@bungle6334 5 месяцев назад
​@organicfarm5524 Back when I was an engineering technician, I was more talented/interested with electronics. I did a lot of prototyping, including populating PCBs. When I was moving on from the company, the owners told me that I should have more confidence when it comes to the mechanical side of engineering. One of the owners, a mech engineer, said that mechanical engineering is mostly just "common sense." I still think about that. I think the thing about mechanical engineering, is that it's much more applicable and intuitive. You can look at bicycle and easily observe how the pedals turn the rear wheel without needing measurement tools or prior knowledge. You can't really look at a board or circuit and understand it's purpose without prior knowledge or measurement tools.
@epiendless1128
@epiendless1128 5 лет назад
Simple way to make one of these - 4093 Schmitt NAND gate. Make the first gate into a Schmitt RC oscillator. Use other 3 NAND gates as inverters connected in parallel, to buffer the oscillator into the MOSFET. Use an NPN transisor to pull one input of the NAND oscillator low, stopping the oscillator when the transistor is on. (Because of the inverters between the oscillator and the MOSFET, the MOSFET will stop OFF - very important). Tap off a small proportion of the output voltage using a resistive divider and use this to turn the NPN on when the output reaches the desired voltage. Use high value resistors to avoid loading the output. I first saw that circuit as a TENS machine. Since used it very successfully as an LCD backlight driver. Make sure the diode is a fast switching diode or schottky rectifier. Ordinary rectifiers line 1N4001 are too slow to turn off, and drain the output capacitor when the MOSFET turns on. Even when just breadboarding, I found a slow rectifier is rubbish.
@TampaTec
@TampaTec 7 лет назад
your channel should have more subs.
@SimplyElectronicsOfficial
@SimplyElectronicsOfficial 7 лет назад
Thanks :) I am sure it will grow over time.
@DaniyalX
@DaniyalX 7 лет назад
i agree!!
@mrawesome6239
@mrawesome6239 7 лет назад
Tampatec ikr it should have way more than yours. ;)
@straceycalloway4833
@straceycalloway4833 6 лет назад
What power supply is he using to the base of the mosfet?
@rursus8354
@rursus8354 5 лет назад
114K
@shahedulislam94
@shahedulislam94 7 лет назад
This intermediate series is really useful, thanks and I hope you continue to make them.
@freeenergytransformer5842
@freeenergytransformer5842 2 года назад
Boost converters are a type of DC-DC step-up converter. They are used to increase the voltage of a DC supply. Boost converters are often used to power devices that require a higher voltage than can be obtained from a battery or other DC source. There are many factors to consider when selecting a boost converter. The most important factors are the input and output voltages, and the current requirements of the load. Other factors include efficiency, size, and cost. Boost converters can be divided into two main categories: linear and switching. Linear boost converters are simpler but less efficient than switching boost converters.
@coolbionicle
@coolbionicle 7 лет назад
Holy shit! A boost converter is the same as a ram pump!
@markspc1
@markspc1 7 лет назад
Hydraulics and electronics have lots in common !
@kushfromhandsworth6601
@kushfromhandsworth6601 6 лет назад
Angel Gonzalez Physics enit I'm guessing
@evananderson8452
@evananderson8452 5 лет назад
Just like the great Pyramid
@erwinconxepts
@erwinconxepts 5 лет назад
that is exactly what i'm thinking too and it got me here
@justinsampler5506
@justinsampler5506 5 лет назад
Read a guys comment on ram pump video
@liminal-m3g
@liminal-m3g 6 лет назад
Very clearly explained - which is a real skill when dealing with complex topics such as these - thanks!
@teachertechnology1
@teachertechnology1 4 года назад
One of the best explications I have ever seen. Period.
@bascelik91
@bascelik91 7 лет назад
awesome buddy! I am preparing an exam and had a lot of trouble understanding this, now it is easy! well done!
@WhatsUpWithSix
@WhatsUpWithSix 6 лет назад
I am loving the tool you used to show the circuit graphically. What software or service did you use?
@martinjrgensen6744
@martinjrgensen6744 2 года назад
everycircuit
@Eduardo_Espinoza
@Eduardo_Espinoza Год назад
@martinjrgensen6744 Thank you 😊
@AyushKumarSingh-tm6bp
@AyushKumarSingh-tm6bp 9 месяцев назад
Proto, gentleman
@davebutler3905
@davebutler3905 Год назад
Well explained. One thing to help remember inductor behaviour is they attempt to keep the current going in the same direction, when they "collapse".
@freeenergytransformer5842
@freeenergytransformer5842 2 года назад
A boost converter is a DC-DC step-up converter. It takes in a low voltage and outputs a higher voltage. The boost converter is a popular choice for powering microcontrollers, sensors, and other electronics. There are many different types of boost converters on the market. Some are simple, while others have more features. When choosing a boost converter, you'll need to consider the voltage requirements of your project, as well as the size and weight of the converter. Boost converters can be used to power projects that require 5 volts or more. They're also a good choice for systems that need higher voltages, such as 12 volts or 24 volts.
@deankay4434
@deankay4434 4 года назад
Thank you having clear voice and reasonable speeds of explanation. I would think some call this a "Buck to Buck" convertor. I understand automotive electrical systems and a few components plus using a lab scope. As a dealer tech since the mid 70's, I am trying hard to make a simple HVAC actuator control circuit. It is a low current dc motor, plastic gear reduction to drive a door to direct air into or around the heater core. The dash controls are mechanical but I am handy in fabrication. It could be "Heat" but with a linear potentiometer. Since actuators can be simple, this on is as it drives a pot for feed back. Move the dash lever, the motor turns on and moves to new location and stops. Yet, it has to change directions. I was thinking of an OP Amp, the 2 pots as voltage dividers for input. To make it easy, use mosfets in "H" bridge. Just working out on paper, then test and build. Actuator are $10 and I can make a 5 Vdc circuit for mosfet control. Like you, I am into motorcycles but started on lawnmowers to make the $1 it paid in 67 and better than mower with wheel driven blades. Self taught as Yamahas where metric and metric tools fit standards, but not the other way. In the county, word of mouth found Datsuns, Opels and everything else coming to me to fix. It didn't hurt growing 7" to 6'3" at 11 and had tools w/unused machine shed on the farm. I just want to built this as I am updating a 67 C10 PU and auto trans where manual is. Plus updating the engine on the cheap. This way I can have my vehicle to drive to Dr. or store. My wife has a 96 Corolla w/160k so need backup vehicle she can drive and operate. Just simple but reliable. Sad to say she had medical issues and I will have my 4th fusion at L3-L2 and hopes it the last. I don't have a Facebook or cell phone, but get by. If you have an idea for a new video using two op amps to drive H bridge, I will be watching your channel. Thanks again for very good just job on the videos. Subscribed! Omaha.
@igbandautala6039
@igbandautala6039 5 лет назад
For the first time I actually understand this. Great explanation.
@sk.samiulreza6205
@sk.samiulreza6205 2 года назад
This channel deserves million subs.
@russelibrahim4045
@russelibrahim4045 5 лет назад
This is cool. I knew what a boost converter is but I never realized how easy it is to build one
@DrDope164
@DrDope164 6 лет назад
This is a great channel, you should really have more subs. Will recommend to my fellow ET students.
@freeenergytransformer5842
@freeenergytransformer5842 2 года назад
DC-DC step-up or boost converters are a type of electronic converter that are used to increase the voltage of a DC power supply. They are commonly used to power devices that require a higher voltage than what can be supplied by a battery or other power source. Boost converters work by taking in a low voltage input and converting it to a higher voltage output. This makes them a really useful tool for powering devices like Arduino boards, motors, and LED lights.
@aasthapandey888
@aasthapandey888 3 года назад
the explaination is so smooth & simple, really worth it watching
@Kenshindegozaru
@Kenshindegozaru 5 лет назад
Thanks for your channel. Im really stupid, but I love electronics. Your videos help me a lot to learn. Thanks.
@ebeb9156
@ebeb9156 4 года назад
Very nice explanation. Author should be proud of himself, wish i had doctor like this in my EE study. Ps-how out voltage control implemented practicly in this circuit? As well as clock for MOS (bet it isnt opAmps and crystals)
@iPsychlops
@iPsychlops Месяц назад
This is such an easy to follow explanation. Thanks!
@137bob3d
@137bob3d 7 лет назад
good of you to make this video showing how an L works. esp. the part about the V across the L reversing and the current flowing in the same direction.
@benhardi2179
@benhardi2179 7 лет назад
This is the one of the best video ever that explains about this in very short video.
@ducpham2896
@ducpham2896 7 лет назад
Can you explain me why When the switch if off, the polarity of the inductor changes, and the circuit uses inductor as a source instead of the 9v voltage source ?
@SimplyElectronicsOfficial
@SimplyElectronicsOfficial 7 лет назад
+Duc Pham because when the switch is off, there is now energy trapped within the inductor in the form of a magnetic field. It wants to get rid of this magnetic field, and the only way it can do that is to get rid of the excess energy in the form of electrical current. Therefore the only path it can go to is through the diode and capacitor. It has to change its own polarity to allow its current to flow to the capacitor.
@JackJackie-xk7pl
@JackJackie-xk7pl Год назад
You are always just showing us how they work we also need to know how to design them
@thamerali9697
@thamerali9697 4 года назад
Great great great channel. I have been looking for you for centuries.
@extrememod_ahu
@extrememod_ahu 3 года назад
Great video. The only thing that's missing is the loss of amperage mechanics. As voltage goes up, the amps go down dramatically.
@brentkelly5445
@brentkelly5445 2 года назад
just learning this stuff so 2 questions if u have time? 1) if the switching is so fast that the inductor never fully discharges and discharging is faster?, then it would be the same on the charge side? it would never fully charge on the 9 V. 2) what is doing that crazy amount of switching on the transistor? what is firing it? 3) what is the determining factor of that output voltage? the size of the capacitor? 4) the on duration and off duration are not the same correct? inductor and capacitor both discharge quicker than charge
@rsedsrahi8794
@rsedsrahi8794 4 года назад
Thanks.... you have just made it easier to understand the working principle clearly.
@wakefieldyorkshire
@wakefieldyorkshire 3 года назад
This reminds me of the old fashioned coil/points system used on cars and motor bikes to produce the high voltage spark to the spark plugs, way back when long time ago.
@anthonyvolkman2338
@anthonyvolkman2338 7 лет назад
Excellent excellent excellent! I have been building these things for quite a while now, and you are spot on!
@loverandjoy
@loverandjoy 6 лет назад
Question. Can this circuit be used to boost power from let us say a 22 volt battery to heat a heating coil resistor to heat 6dl water in a 1 litre volume for a duration of time?
@markbeukers221
@markbeukers221 2 года назад
Thanks a lot, this movie is very useful! It describes the operation of the boost converter in a really clear way.
@DrHarryT
@DrHarryT 7 лет назад
Use two of these circuits paralleling the inputs and outputs. Have the mosfet hi speed switches alternate so that one o0f the inductor coils is always collapsing generating current, thus a more stable and higher current output potential.
@sanssans341
@sanssans341 7 лет назад
DrHarryT what current will u get?
@abhisekrout8522
@abhisekrout8522 4 года назад
What will make the output voltage settle at 100V?? As far as I know, here the output voltage will keep on increasing till the capacitor bursts. Someone..... Please correct me if wrong. Thank You.
@kacperfilipek8461
@kacperfilipek8461 3 года назад
I'm probably late but, no, it will not. Notice that the voltage source charging the capacitor is a series of consisted of a coil and a battery. The voltage induced by the coil is relatively the same, because the current flowing through the coil when the switch is closed is also the same over time. And the capacitor charges because the sum of voltages on the coil and battery is bigger than the voltage on the capacitor. As the capacitor charges and it's voltage rises, the difference between left part of the circuit and the capacitor will lower, so the current flowing to the capacitor will be lower as well until it is balanced
@DD1316
@DD1316 3 года назад
Brilliant! Do you plan on providing actual components/values for something common like Input 5-9V 6A, Output 6-30V? Thanks for this vid!
@VictorRivarola007
@VictorRivarola007 6 лет назад
Thank you for your explanation of the boost converter. Unfortunately, I still have a question on their working. When the mosfet is off, the capacitor is charged by the circuitry. However, when the mosfet is on, there is a direct path from the input power source to the ground. That means that power is still being used, unlike the boost converter. It also means that the boost converter should short circuit. But it doesn't, so there has to be something I cannot figure out... Do you know what is It?
@andrasszasz4373
@andrasszasz4373 6 лет назад
It's actually the inductor, when the mosfet is on the inductor act's as a load and starts converting the electric charge into magnetic field, when the inductor saturates ( reaches the maximum magnetic field it can store, measured in henry) it will be a direct path and the mosfet will get shorted. This is the reason why high frequency converters can use smaller inductor like 10uH because the "on" time is shorter and it will not saturate. Low frequency converters need bigger inductor, if not it will saturate and short out. Most dedicated dc/dc uC controllers have a current feedback as soon the current starts rising because the inductor starts saturating the mosfet will be close to prevent short circuit.
@nejiniisan1265
@nejiniisan1265 5 лет назад
Since you are working with AC, there won't be a short. If the mosfet would be on steadly, then yes, a short would happen. But think as an AC circuit. A 500 uH inductor switched at 100 kHz would act as a 315 ohms impedance. Since you are driving the inductor with a pulse train, the back emf is the responsible for stepping up the voltage. Remembering that V_backemf = -L di/dt Where di/dt is related to the duty cycle and the switching frequency.
@anandsivathanu8517
@anandsivathanu8517 5 лет назад
@@andrasszasz4373 If inductor is saturated, mosfet will get shorted. shorted means what? mosfet become faulty?
@andrasszasz4373
@andrasszasz4373 5 лет назад
@@anandsivathanu8517 Shorted means that the power supply's positive and negative rail will be shorted (same thing as if you take the powers supply positive and negative wire and touch them together), this will cause excess current through the mosfet which will result in excess heat and the mosfet will burn out.
@anandsivathanu8517
@anandsivathanu8517 5 лет назад
@@andrasszasz4373 Thanks for Your Kindly Reply Mr.Andras Szasz. I understand your reply.
@engineer1075
@engineer1075 4 года назад
sir you are doing really good job using every circuit....please do more videos on power electronic converters thank you
@abegailvino3111
@abegailvino3111 3 года назад
Hi your video was amazing, may I know what simulator you've used? :)
@MMarkur
@MMarkur 3 года назад
It’s called Everycircuit.
@NateEngle
@NateEngle 5 лет назад
Boost converters are more efficient now than they used to be but it's worth bearing in mind that a considerable amount of current gets ditched to ground when you're charging the coil and that can be an issue if you're looking to source much current from your boosted voltage., Buck (stepdown) converters are a LOT more efficient. Back in the day when phones actually had real bells in them I built a simulator box that needed to supply the base tip-ring on-hook voltage of -48VDC which wasn't that hard, but the ringer voltage to make a princess desktop phone's bell ring was more like 80-100VAC at about 20Hz and that part required some serious attention to the breakdown voltages on everything in that part of the circuit. It was fun and I learned a lot but I never got shocked as much by any other construction project as I did by that thing. I think I still have it in the basement somewhere.
@rajeshsaha3446
@rajeshsaha3446 4 года назад
At DC voltage, inductor gets short(V=L(dI/dt) or ()Reactance offered by L, XL=JWL, W=0, XL=0)....so how does it boost the voltage
@sadeqsadeq7128
@sadeqsadeq7128 3 года назад
I think it depends on the voltage across the capacitor
@mateimarin8190
@mateimarin8190 2 года назад
As soon as current passes through an inductor, the inductor generates a magnetic field (simply said). So now we have energy stored in the magnetic field of the inductor. And now as soon as the transistor closes, current doesn't flow through the coil anymore and the magnetic field collapses (because it's not being maintained by the flow of electrons) and pushes electrons through the diode and then into the capacitor. The diode makes sure that electrons can't get back to ground (negative) as soon the transistor is closed (so they are therefor forced to stay in the capacitor). This process repeats many many times until the capacitor is fully charged up. (Make sure that the diode can handle that high voltage so it doesn't break) the capacitor should also not be charged over it's rating. Correct me if I'm wrong with anything. Hope I could help
@arjandehaas6304
@arjandehaas6304 8 месяцев назад
This is great, thank you. But what happens when we put a load on it? How do V and A relate to each other? 9V1A becomes 100V0.0001A?
@tonyavito208
@tonyavito208 5 лет назад
Hello, nice explanation! What is the software you are using for simulation?
@guywhoknows
@guywhoknows 2 года назад
If you had included the current change (draws) over the circuit ... Doesn't the inductor voltage spike to around 3+400? Is the current divided by the voltage when it spikes. You had not included the series of the inductor to the cap as a voltage . Using batteries as a analogue would have helped support what was occurring.
@Freepalestineforever23
@Freepalestineforever23 Год назад
really helpful! if you ever do continue the series can you post a video on buck converters?
@amal717
@amal717 7 лет назад
If the magnetic field is going to accumulate each time the switch closes , then that means the voltage will increase into infinity!!!,actually what limits the voltage to stabilize at 100 volt??
@julioalvar
@julioalvar 7 лет назад
This is usually used with a resistor as load, so this helps the voltage to stabilize somewhere higher than the input voltage. On the other side, in real life, nothing can stop it. The voltage circuit is prone to infinite, but the components can't endure such voltages. Each component has a limit, and when the limit is reached, thing would systematically start to blow up.
@amal717
@amal717 7 лет назад
Julio Cesar Alvarez Gomez thanks for reply . but that is so strange that it will stabalize due to load because the load is constant
@julioalvar
@julioalvar 7 лет назад
No problem Mosab. You are right, the load is constant, so the load won't allow the capacitor to just increase its charge. While the Mosfet is ON, the load will get the energy stored in the capacitor, when OFF the load will get the energy from the inductor meanwhile the capacitor also reloads again. From another perspective, when the Mosfet is ON, the charge in the capacitor will decrease depending on the load value, and it will increase as the Mosfet goes Off. With that on mind, the output voltage during a cycle (i.e. Mosfet goes ON , then Off and finally ON again) will oscillate around an average value that remains equal if the ON and OFF Times of the Mosfet also remains equal. That is what I called stable voltage in the output.
@amal717
@amal717 7 лет назад
Julio Cesar Alvarez Gomez thank you alot. i got it .
@gamalmothersil6943
@gamalmothersil6943 6 лет назад
The capacitor has a limit so it will saturate after the maximum voltage is reached.
@jan-zumwalt
@jan-zumwalt 8 лет назад
Very good clear audio.
@xiaohe8594
@xiaohe8594 3 года назад
i havent seen a such clear video ever ! thank you so much
@briant1550
@briant1550 4 года назад
I have such an appreciation for this video. Thank you
@wb5rue
@wb5rue 8 лет назад
Great video with an excellent simplified explanation.
@barrykery1175
@barrykery1175 2 года назад
What a great video. That was very interesting. It's the same principal as an ignition coil works in a point type ignition system in a car. Thanks for posting. I get a simple yet great education. Barry, KU3X
@panagdimi
@panagdimi 4 года назад
To make this even more helpful please explain how to control the output voltage. E.g. how to get from a 9V battery up to 48V output to drive a phantom power audio circuit with a current of no more than 20-25 mA. Thank you!
@kalamatagames2631
@kalamatagames2631 5 лет назад
plz don't forget to explaine about curcuit amperage and voltage changes, at the same time . it is more easy to understand. And thnks about the video
@bouaradameriem5868
@bouaradameriem5868 2 года назад
Thank you for the video but I have question Why the current doesn't flow through the diode when the switch is on? Normally the diode is reversed to ensure that the current will not flow through it
@karljacobs794
@karljacobs794 2 года назад
So what i think ive learned is that your better off connecting capacitors in parallel with a booster to get better capacitance and desired voltage...??? Correct me if im wrong anybody... Good explanation on boosters very use full information for my next project thanks
@alhafed11
@alhafed11 2 года назад
Good explanation. Where’s the mosfet gate connected to pls? Thanks
@tomavent2283
@tomavent2283 3 года назад
Just a quick question. Why doesn't current constantly flow through the diode even when the switch is open, as the power supply is connected in such a way that you would expect it to.
@leeorshimhoni8949
@leeorshimhoni8949 4 года назад
simply brilliant. easy to understand. explicit .
@girlmore4484
@girlmore4484 7 лет назад
The subscribe circult won't work, which means that you are NOT allowed to subscribe
@nicolasraimbaud3947
@nicolasraimbaud3947 6 лет назад
Amazing, really useful for students man. Thanks ;)
@miguelcolon4690
@miguelcolon4690 4 года назад
Excellent, can I convert a battery TRIMMER to a wired one with this circuitry?It's 40v 2ah. Thanks for your answer, Shubham.
@dkdias1
@dkdias1 Год назад
I went to the link provided to "play" with the circuit, but the page said that there was no circuit? Please help....
@dreamfly555
@dreamfly555 5 лет назад
The fact the voltage across the capacitor got increased every time is due to the increasing incoming voltage of the inductor , does that mean the spike's voltage is infinite when the mosfet is off? If so, why will it settle eventually at about 100v instead of even higher than that over time?
@tombouie
@tombouie 5 лет назад
Very impressive, ?How much power output can I get out of a boost converter? For example could I get enough power out to run most DC appliances?
@PepperDeVillle
@PepperDeVillle 5 лет назад
You get the same amount of power out of it as you put into it. You will boost the voltage, but the current will decrease, so at the output, the power will remain the same.
@PepperDeVillle
@PepperDeVillle 5 лет назад
To actually answer your question, it depends on what power supply you are starting with. For example, if you tried to use a 9V battery to supply your computer, it would probably work but the battery would get really hot and probably only last 15min before losing all its charge. If you start with wall power, used a rectifier to supply DC voltage, then used a boost converter to get the right DC voltage, then yes, you can totally power DC appliances with this. It's not free energy though. It's used more to fine-tune the power to specifications for your device. Think of the power supply attached to your computer cable or a cell phone charger. A boost converter is the sort of thing you might find in one of those. A boost converter just gets the power from 120VAC to whatever DC voltage your device needs.
@tombouie
@tombouie 5 лет назад
@@PepperDeVillle Yes power in = power out. I was concerned with any other limitations. Oh, great pair of hats.
@tombouie
@tombouie 5 лет назад
@@PepperDeVillle Thelonia, I must apologize because I didn't read your whole reply (only the 1st to lines). You're right every appliance has electrical input/output tolerances (ex: floor/ceiling power, current, voltage, inductance, capacitance, etc). More generally, it seems we're close to pragmatic conversion between any level of ACorDC. Maybe I should focus on the electrical input/output performance & tolerances of ACorDC conversion units whether than that of applicances. It's too bad we don't produce electrons in the US anymore though. You are very smart & good looking. Thks for the help. ACtoAC transformer & DCtoDC converter ACtoDC rectifier & DCtoAC inverter DCorAC to mechanical output electric motor FueltoACorDC electric generator
@JustinPeach-f6w
@JustinPeach-f6w 8 месяцев назад
What is the voltage source controlling the base of the transistor. I tried building the circuit from scratch on every circuit but I can’t find it the parts bar and it doesn’t function without it
@krishna2133
@krishna2133 7 лет назад
Very good explanation and the animation is on point. Thank you very much!!
@sakibhasan7682
@sakibhasan7682 3 года назад
Very Very Good Undarstanding Way for beginner
@gordonfrohman250
@gordonfrohman250 6 лет назад
You explain things very well, thank you
@ElectroRestore
@ElectroRestore 5 месяцев назад
At 100 v out, what would the current capability be? Could you get 10 amps at 100 v from a DC low votage?
@alexeykokh8240
@alexeykokh8240 6 лет назад
Hello. Very good video. I realized that I am looking for a similar boost converter, maybe you could recommend me a chip?
@heathercurtis1354
@heathercurtis1354 6 месяцев назад
I want to use a 9 VDC source to produce exactly 90 VDC output. Also, I want to use this to power an AM tube radio without creating RF interference. Can you provide the circuit design and a Mouser parts list? Thanks so much.
@fuelban
@fuelban 2 года назад
Good understandable video, thanks, can I ask I ask, if and where within the circuit board would you have an earth connected, if at all, this might. Seem a daft question, but not so coming from me... Lol ... Thanks, Thom in Scotland
@edselnarvaez9667
@edselnarvaez9667 Год назад
I loved it, thank you !!!! Very insightful
@fredparkinson1289
@fredparkinson1289 4 года назад
At 5:15 you say that when the switch is opened polarity of the inductor switches so that negative is on the left and positive is on the right. Then you go on to say that current flows from left to right. But current flows from a higher potential to a lower potential, so why isn't it flowing from right to left?
@FireSymphoney
@FireSymphoney 6 лет назад
Basically, you charge a capacitor that has a high output voltage (high capacitance) and cause it to rapidly charge and discharge, the discharging is the output voltage.
@ZSilver55
@ZSilver55 4 года назад
by having the meter on the end of the circuit wouldnt it discharge the capacitor?????, nice vid
@francou61
@francou61 4 года назад
That's a very good point. Any load you put in parallel to the capacitor will draw current from it and discharge it until an equilibrium between the charges coming in (from the inductor) and out is reached. The higher the current going through your load, the lower the voltage will be. Voltmeters have very high internal resistance so the current going through them is minimal. The measured voltage will therefore be very close to the theoretical maximum.
@westinritter233
@westinritter233 3 года назад
That's a voltemeter no current flows through voltemeters
@Eduardo_Espinoza
@Eduardo_Espinoza Год назад
How did you figure out the values for the resisters, capacitors, transistor?
@boog567
@boog567 10 месяцев назад
This is intriguing. Normally in a purely inductive circuit with a sinusoidal wave the voltage and current are always 90 degrees out of phase. In this type of pulsed circuit the inductor voltage and current are 180 degrees out of phase when the switch is open and the field is collapsing. That really confused me at first.
@simonhollad5511
@simonhollad5511 5 лет назад
when does the voltage stop raising and why?
@zdrux
@zdrux 4 года назад
There's a point where the capacitor is fully saturated and can no longer store any more charge.
@russelibrahim4045
@russelibrahim4045 4 года назад
If the system is conservative, Vout = Vin * (1/(1-D)) where D is the duty cycle of the switching.
@ginebro1930
@ginebro1930 4 года назад
I never was explained why but heres my thoght, the inductor can saturate (when every magnetic domain is polarized in the same direction) after this the main principle wich generates the voltage won't increase. Other reason could be that the capacitor exceeds it's maximun admisible voltage, then a internal discharge occurs, for this reason you must take care to use a well insulated capacitor or don't use a extreme conmutation frecuency. The first of the 2 reason that happens first will stop the voltage grow, in the second case it will also destroy the capacitor.
@eltunene
@eltunene 4 года назад
Excellent explanation!!
@diegomestrecam7674
@diegomestrecam7674 2 года назад
It could be nice to hace a resistor in the output so that we could play with the load. P.D greate video!
@saberline152
@saberline152 3 года назад
if you stopped opening and closing would it stay on that voltage or would it just stop? also does the speed of switching on and of influence the output voltage? I've heard on another video that the output is almost entirely a function of the duty cycle for a given circuit.
@BaljeetSingh-nm8hu
@BaljeetSingh-nm8hu 7 месяцев назад
So nice description, so hard to find. Great fellow regards.
@adamchelchowski
@adamchelchowski 3 года назад
Fantastic explanation
@moneyaccount9775
@moneyaccount9775 6 лет назад
What type of transistor can we use(N, P, NPN, PNP)? Great video
@wiltanschannel82
@wiltanschannel82 Год назад
How do you configure or set the parameter of the MOSFET to work correctly simulate? Can you explain. I'm using same app.
@qsdrfghgujfddyffguff
@qsdrfghgujfddyffguff 5 лет назад
Superb basic knowledge of converters
@gabsmit
@gabsmit 6 лет назад
WoW. This i such a clear explanation. Thanks man. Awsome.
@eddy8928
@eddy8928 7 лет назад
Hello! I'm doing a project on a solar bike with boost converter. I like your idea and very simple. I could apply it in my project with minor modifications. But, I wonder what kind of software did you use?
@juniorsport5880
@juniorsport5880 3 года назад
So whats gonna happen if V out is set eg to 30V, and the input voltage will be 40V? Is it gonna step the 40V down to 30V?
@ewanharrison4721
@ewanharrison4721 6 лет назад
I'm a bit confused as to why when the switch is closed, there is no current flowing across the diode to the capacitor? Surely there would be some without a resistor there?
@schloumf
@schloumf 5 лет назад
Hello, could you tell me please, what timer 100µs you put at the bottom of the circuit--- and the way you have connected it ?Thank's !
@risingedgeindustries7229
@risingedgeindustries7229 6 лет назад
Great video!! Clear and concise!
@UsedToBeConsumer
@UsedToBeConsumer 4 года назад
Question : so the Henri value of the inductor is what decides how large is the magnetic field built around it, and by the same occasion decides the maximum voltage output ! am i right ?
@democracyforall
@democracyforall 4 года назад
If I got 15 amps and only one volt supply, how can that be used for the circuit you got?
@cyndifrisby5933
@cyndifrisby5933 6 лет назад
Would the batteries still last the same time as normal?
@anujkumarsingh3191
@anujkumarsingh3191 5 лет назад
Please explain switching of the mosfet
@warunachathuranga3339
@warunachathuranga3339 3 года назад
Can i know what's name of this software?. Good teaching. Thanks buddy
@freezees
@freezees 4 года назад
really good explanation
@altuber99_athlete
@altuber99_athlete 5 лет назад
Great teaching. What's the difference between a boost converter and a voltage multiplier (doubler/quadrupler)?
@marceloalvarocoronelcastro3463
A voltage multiplier is based on an AC source
@altuber99_athlete
@altuber99_athlete 5 лет назад
@@marceloalvarocoronelcastro3463 Oh, true, hehe. Thanks.
@jimadams2473
@jimadams2473 7 лет назад
Nice video. Great demonstration. Thanks!!!
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