If you need more help with this topic, I highly recommend my step by step Chemistry notes. You can purchase the complete guide here ➡️ melissa.help/acidbase1notes
why am i only learning about this the night before my final. oh my god. this is so amazing. she's better than my chem teacher at explaining things. thank you so much.
Thanks for putting the formulas up! You're really good at filtering the extra info that might give context for more advanced students but easily confuses beginner students. I come to your channel to get a fundamental breakdown of my 2 hour lectures lol. So thank you!!
oh my gosh. THANK YOU. I've been staring at my textbook for hours over this and haven't been able to sort out which formula gives you what- the summary at the end was a LIFESAVER!
You are a wonderful human being, thank you so much for making them! :D You're editing skills are amazing plus you explain everything so well! I love how colourful and fun your videos are, you make chem fun. I hope you get tons of subscribers in the future, like this channel is great! :DDD
I don't know why you don't have 50 mil subscribers because you are actually the best tutor out there. All the other tutors are so complex and you just get right to the point.
This woman is amazing!!!!!! Been stuck on a question like this for over an hours and pithing 2 mins of watching this I actually get it!!!! Thank you so much :)
i love you thank you so much, i hate online school so much because we have to read everything from the textbook and i can't understand it. you made it really simple and easy to understand thank you so so so much
We are not subscribers... we're students 💁🏾♀️ 😅 Thank you Melissa 😊 you are officially added to my college A team! I'm On my way to finally get my bachelor's degree 🙌🏾 😌
Thank you so much for thiss, I was literally crying cause I can't understand anything, but with the help of your video, I immediately understand it and can answer it in a piece of cake, thaank youuu
I got the same result. If you have the pH already, to find pOH just substract the pH=8.5 to 14 (pOH = 14 - 8.5 = 5.5). Once you found pOH= 5.5, you can find OH. To find OH use this formula [OH-]= 10 ^- pOH. [OH] = 10^-5.5 = 3 x 10^- 9 or 3.1 x10^-9. The sig fig will depend on your professor really.
you. are. a. life. saver. Thank you so much! I barely understood the lesson in my chemistry class, but you explained it in a much detailed and better way. This will be on my final so this definitely helped!
Thanks, I haven't made a video on this yet, and I needed to share one with my students. Going through all the youtube pH videos, this was the only one that was both correct and understandable.
they are making us do this for 7th grade online school and don’t explain it well enough and i’m coming to this video after a mental breakdown from it 😎
Finals are coming up and your videos, along with the step by step notes I purchased, have definitely helped me feel more confident about these exams! Going to put all of this to use tomorrow, Thanks Melissa! Hopefully I pass because I need to graduate in 2 1/2 weeks lol
i have zero interest in chemistry which is probably why it’s so hard for me to learn, but 4 minutes from your vid made more sense then all the notes I had to look through😂thanks
This is not fair! Some people wrote in the comments that they watched this video before they entered the university finals. And the problem is that I have to learn this as a high school student in Turkey. Moreover, this is known as one of the easiest subjects! It wears me out that I can't even go to university without knowing these chemical calculations.
I have not done calculations like this in a number of years and it would be really helpful if someone would step through exactly what you select on your graphing calculator and also going the reverse; if I have the [OH-], then what do I plug in to get to [H+].
minute 2:36, How do you do the division of 1x10-14/3.1x10-9? I thought yo had to subtract the coefficients? I must be doing something wrong I get -5 not -6. Please help Melissa. PS thank you so much for all this work. Wait a second I got it, it is the rounding, I was using 3.1 not 3. Got it
Hello! This was a really helpful video. I'm currently in chemistry Higher Level in the IB system and we are learning about weak acid and base dissociation constants (ka, kb, pKa, pKb) and their calculations and I was wondering if you had a video about that or if you can make one as I'm finding them rather difficult.
Perfect timing on my next Live session this Sunday at 12PM PST, I will be going over how to find the Ka and Kb. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-8ZLifdOOzqA.html
May I ask some question, Suppose if we have hydrolysis ammonia NH4+ NH3 + H+ Kh = [NH3][H+]/[NH4] = 10^-9 mol/L To 1 liter of pure water, 1mmol of ammonium chloride was dissolved, and pH was adjusted to 9 using sodium hydroxide. What will be the concentrations of ammonium ion and free ammonia?
