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Kinematics of particles- rectilinear motion (motion curves) | problem 1 | Engineering Mechanics 

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In this video we have solved a problem based om motion curves from the topic kinematics of particles.
Real Life Applications:
When we study any object in motion then we need equations to describe the motion at every instant. These equations are based on some assumptions and in real life there are very fewer chances that these equations will be valid. Moreover, it becomes very difficult to describe the complete motion with few equations and that is the reason Motion Curves are very important to study. All the motion in the universe can be plotted on a graph and we can fetch useful information out of it.
Explanation:
This video tutorial provides a basic introduction into position time graphs, velocity time graphs and acceleration time graphs - graphical analysis of linear motion. The slope of a position-time graph is equivalent to the velocity and the slope of a velocity-time graph is the acceleration. The area under the curve for a velocity-time graph is equal to the change in position which is the displacement of an object. The area under the curve for an acceleration-time graph is equal to the change in velocity. for a velocity time graph - the slope of the secant line (2 points) is equal to the average acceleration and the slope of the tangent line (1 point) is equal to the instantaneous acceleration. For a position time graph - the slope of the secant line is equal to the average velocity and the slope of the tangent line is equal to the instantaneous velocity. This video contains plenty of examples and practice problems.
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if you have any doubts related to the topic, please put your comments down in the comment section. We will surely get back to you.
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6 окт 2024

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Комментарии : 2   
@godsson7613
@godsson7613 4 года назад
Thanks mam its good but my English is not very good can you make it in hindi or common language
@blessedtobehere
@blessedtobehere 3 года назад
area under the increasing parabola= area of rectangle - 1/3*height*base......small mistake
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