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I don't undestand in the first part of the video why the kinetic products would be formed in low temperature. In my logic as an increase of temperature is an kinetic factor, the reaction would be faster and the product formed should be the one formed quicker. Right? If anyon ecould help I would appreciate it very much
never mind, I just got it. For anyone wondering: the increase of temperature often leads to an increase of the reaction rate constant which enables the thermodynamic equilibrum to be reached faster. which means that the longer one waits, the more we form the thermodynamic product. At the end this product will be in majority.
@@hazeld8016 less stable doesn't mean that they would be more reactive. Go through the reaction mechanism and you would see that in the first step alkene will give it's electron to Hydrogen of hbr to form a carbocation and the most stable carbocation would be formed from more substituted alkene isn't it
@@nikhilpundir1433 pleaseeee help im so confused about which resonance structure to use. the positive charge and double bond can just be chasing each other around the structure. im currently working with cyclic compounds and i really don’t understand how my teacher is picking which structure to use, im probably just dumb and missing something but i can’t find any good answers online
am I correct? so at 4:02. so because its low -40c its always going to be 1,2 addition and b/c its high 60c its always going to 1,4 addition? they are not going to change position ?
I dont understand how the kinetic product is mono substituted versus the thermodynamic product being disubstituted. I can't visual the two versus one R groups
@@eobardrush2112 I was wondering why many of his videos (I made a playlist last semester for ochem 1) appeared as non existent. I thought I was imagining it.
I may be wrong, but because the thermodynamic reaction is the slower product formation, it has time to select for the more stable product (the di-substituted alkene). In the kinetic reaction, it happens so quickly that the Br- reacts with whatever reactant is closest and more immediately stable.
