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Lec 3 | MIT 6.450 Principles of Digital Communications I, Fall 2006 

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Комментарии : 11   
@siasabora
@siasabora 15 лет назад
wish my teachers were as honest and as simple as this MIT guy...
@jomareyd.parreno5112
@jomareyd.parreno5112 2 месяца назад
Im IT and why i am taking this engineering level math HELLLPP!!!!
@ApplianceRepairOfTucson
@ApplianceRepairOfTucson 14 лет назад
why dont you support your theory with more examples? that would help a lot.........thx
@danalex2991
@danalex2991 3 года назад
Its really so dry.
@5209582045
@5209582045 7 лет назад
I guess @ 33:05, Lmin = H(X) iff each pi is integer power of 2 is invalid statement. Lmin = H(X) iff each pi = 1/length symbol space. For bainary symbol space, it is 1/2.
@atchutram9894
@atchutram9894 7 лет назад
rama chandra I am afraid you didn't get it right. Try to understand Lmin meaning. It is achievable average L such that all l's are integers. If X has 3 possible symbols in alphabet, as per your suggestion the h(x) is log(3) while lmin(achievable) is between log3 and log3+1. To be specific it is 2. lets say {a b c} are letters in alphabet and their probabilities are{1/2 1/4 1/4} h(x) is 1.5 while lmin(achievable) can be 1.5 because we can choose lengths{1 2 2}
@5209582045
@5209582045 7 лет назад
atchut ram thanks for pointing it out. It should actually be H(x) = Lmin iff the sameple space is a power of 2 and each pi is 1/sample space. In that Prof probably meant to say integers are exclusively negative numbers. All hail the Prof
@atchutram9894
@atchutram9894 7 лет назад
rama chandra no length of the alphabet is not important. I suggest to rethink and look at my previous comment (latest edited) once again.
@atchutram9894
@atchutram9894 7 лет назад
rama chandra yes those integers cannot be positive. They are probabilities.
@pin3appel
@pin3appel 15 лет назад
MIT is 1 cool dude
@LionionKR
@LionionKR 15 лет назад
What the Hell?
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