I have seen various videos in order to understand the topic .....got that into my mind after seeing the elaborate explanation in video......thankyou sir
When you reach the time period of {2 ≤ t ≤3} wouldn't the function in your integral be just 1? Since the area of convergence/overlapping occuring is just up to the amplitude (or just a square decreasing) of x(t) = 1?
At 20:20, your integration is incorrect. I did it many times and got the same answer, but different than yours. I also checked it with online calculators.
Please someone clearly tell me how we are getting (t-2)on the left hand side after time reversal, I can not get that. In my sense it would be (t+2) but. Please clearly tell someone shifting process after time reversal.
Dear Jamila, After flipping, as the current axis is t (the point on right) so anything to the left of it would be t minus something. As the width of the signal is 2, the point on left will be t-2. Consider t as some value say 5 so t-2 will be less than that, say 3 and so on.
I'm sorry to say there are a lot of mistakes in the explanations and even in the equations you gave at the end the function y(t) exists only between 0 and 1.
