Most Common Chemistry Final Exam Question: Limiting Reactants Review

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This Chemistry review covers a common final exam question/ topic. We'll go over how to find the limiting reactant, excess reactant, theoretical yield, percent yield, actual yield and how to find the amount of excess left over.
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8 май 2019

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Комментарии : 85

@sanaajennings6285 5 лет назад

I haven't even finished chem 1 but I went from exam 1- 65% 2nd -80% to the 3rd 92% because of your videos ❤ as soon as I can i will be visiting your patreon

@sanaajennings6285 5 лет назад

I'm going to bust my butt to do well on the final

@spider-mancantsee5875 4 года назад

What I should’ve done now I have a 59 and need to do well on the final so watching this and writing facts down to study till then

@nonjabulomacu9277 5 лет назад

Amazing how your videos taught me all the chemistry I know and am loving the smile that stays on my face when I write chemistry exams/tests. THANK YOU!!!!!!!!!!

@paoloalejandrino2523 5 лет назад

Still managed to get a C in my chem 1 final. I would've fluked the course if not for your videos! Will make a comeback on chem 2!!

@btw3344 4 года назад

Why take chem 2? Is it part of your major I thought you only need one science lab

@MATTicall 3 года назад

@@btw3344 must be premed

@aidan2849 2 года назад

@@btw3344 do biology majors need to take the ACS final for chem. Im in biology but still take chem courses and apparently we do. Can we opt out or something?

@zeldaloops6941 5 лет назад

Seriously thank you thank you! I appreciate your videos so much and the time that you put into it. You are really making a difference and I’m so glad I came across your channel! ❤️ please keep doing what you are doing, it is making a difference for sure!

@simranc7690 4 года назад

My Chemistry 101 final is on Wednesday (it's Monday...) and I only had like three days to prepare for it so binging your youtube channel has been a bigger help than my own professor. I'm finally understanding all these concepts without spending like four hours on one topic! Thank you SO much for including practice problems you're the reason I might not fail.

@melissamaribel 4 года назад

You are so welcome!!

@L0CV5T Год назад

Exactly the same situation here, but today is the final, in 30min. Wooo i love chem…

@jenny030916 4 года назад

This is AMAZING! Thank you so much Melissa😊

@ernestoyounes2946 4 года назад

thank you mrs melissa, i hope i can boost my chem from 70% to 100% on the final exam and get over with it

@adriennejengmanato2259 5 лет назад

Thank you for this Melissa!😍 I now slightly understand stoichiometry👏

@kimmypaz2208 3 года назад

I have a final today and this cleared SO MUCH for me omggg 😭 thank you Melissa! 💗

@alexandrakwasnik5868 3 года назад

I have a chemistry final exam tomorrow for Gen Chem 1. I didn't know stoichiometry or limiting reactant, however, from watching your videos, I not understand both! a MASSIVE thank you! I feel way more confident going into my exam and I am definitely going to keep watching your videos!

@toastom 3 года назад

How did it go?

@heavenlyrelaxations101 3 года назад

So helpful thank you for all that you do!

@quinnobrien8602 3 года назад

These videos are the best!

@ansri24 4 года назад

my finals are less than a week and ur videos are saving me, thanks a lot

@mimimo6223 3 года назад

This really took a long time for me to understand the limiting reactants and finding each yield and excess reactants to percentages lol but thank you so much this really helped me greatly.

@briannamainolfi4704 3 года назад

I have my gen chem 1 final tomorrow morning and your videos have been super helpful thank you!!! Update: I just took my final and this helped me so much!!

@namasteayla 3 года назад

Thank you soooo much

@jacobseo3578 2 года назад

OMG... Just OMG. She saved me from the Chem test. Thx!!!

@michelleescalera485 5 лет назад

You’re amazing ! God Bless you!!!

@melissamaribel 5 лет назад

Thanks Michelle 😊💕

@medea4724 Год назад

love this channel

@jhanelljacks9932 4 года назад

I’ve watched all most every video on youtube for this and still not completely understanding it THANK YOU my test is today hopefully I pass !!!!

@rahulrathod170 4 года назад

hope you're test went well. Writing mine tomorrow. All the best for the future

@glompxme 4 года назад

My professor hasn't taught a class since the pandemic, so you're saving me! I hope to at least get a C. She yeeted stuff from the hw so she wouldn't have to grade it but it'll be on the final.

@trishaawate4030 3 месяца назад

I LOVE YOU THANK YOU FOR SAVING ME IN CHEM!!!

@NadiaSambolin Год назад

You are amazing!!!

@aquarxus4894 5 лет назад

Hi sorry this is unrelated but in regards to chemistry if we wanted to investigate the affect of concentration of rate reaction how will we do so with: HCL and Antacid in this case we have to do a prac where we need to put our results in a graph where we vary the concentrations of the HCL from 0.1 m 0.5 m 1m but maintain the antacid so far I have plotted just the times of when the reaction is done but I don’t know how to record the rest in order to make a graph?

@mido92i19 4 года назад

you're a teaching genius

@melissamaribel 4 года назад

Aw thanks!

@konstantinrebrov675 4 года назад

Theoretical yield is the quantity of a product obtained from the complete conversion of the limiting reactant in a chemical reaction. It is the amount of product resulting from a perfect (theoretical) chemical reaction, and thus not the same as the amount you'll actually get from a reaction in the lab. Theoretical yield is commonly expressed in terms of grams or moles. In contrast to theoretical yield, the actual yield is the amount of product actually produced by a reaction. Actual yield is usually a smaller quantity because few chemical reactions proceed with 100% efficiency because of loss recovering the product and because other reactions may be occurring that reduce the product. Sometimes an actual yield is more than a theoretical yield, possibly because of a secondary reaction that yields additional product or because the recovered product contains impurities.

@jeanalik6978 4 года назад

There is an easier way of working out the limiting reactant. Just find the moles of both reactants and use the molar ratio to compare both reactants. The reactant with fewer moles is gonna be your limiting reactant.

@melissamaribel 4 года назад

Yep that works too, I just like getting to the grams because most questions ask for the theoretical yield and students forget how to get there. So I like showing you one way that answers two questions.

@jeanalik6978 4 года назад

Melissa Maribel Ahh I understand. However wouldn’t finding the limiting reactant by moles be more effective as you exclude the other reactant for the second part of the question.

@melissamaribel 4 года назад

Both are effective, if you prefer stopping at moles then do that. The important part is that you understand how to get there 👍

@chandrapriyan5972 5 лет назад

I am so much inspired by you mam

@melissamaribel 5 лет назад

Thank you!

@theifking1 3 года назад

How did you get 163g Fe2O3 for the used? I keep getting 653g

@mohammadschool1968 2 года назад

how do you know what product to choose from if u have 2 of em

@Flaystray 3 месяца назад

Knowing what percent yield actually is solidifed my faith in chemistry

@Chembynlsir 2 года назад

Thanks mam

@4JUVIE 4 года назад

This is the same as igcse cambridge right?

@user-le3xf3hi6u Год назад

What if it says mixed with ? the wording is tripping me up because I don't know if I have to add the two given numbers in grams and then set the problem up or am I still solving for one? In the reaction given below, 35.2 g of bromine (Br2) is MIXED with 23.1 g of phosphorus (P) to produce phosphorus tribromide (PBr3). What are the limiting reactant and the theoretical yield, in grams, of phosphorus tribromide?

@phoenixjohnson3149 9 месяцев назад

When I did this on my own for some reason my brain said find the molar mass of 2Fe because on the product side the coefficient was 2.. its like throwing me off a bit and i don't understand why

@nonjabulomacu9277 5 лет назад

So...is percentage yield accuracy, how close you were to achieving the perfect scenario or compound? Edit: Nevermind, asked too soon.

@Lana-dn2kq 5 лет назад

Love and BigThankyou from India 🙌🙌

@melissamaribel 5 лет назад

Thanks!

@juanmartin7902 3 года назад

my final is tomorrow lol goodluck to all!

@WOG18 4 года назад

Can you please explain how you got 116.8g

@courtneyminnoe7619 2 года назад

So if you start with finding Fe instead of CO2 the first time you would have to continue finding Fe in the second one?

@user-gw8qg7rm5i 5 лет назад

Amazing!

@melissamaribel 5 лет назад

Thanks!

@user-gw8qg7rm5i 5 лет назад

Can you please make videos on organic chemistry?

@melissamaribel 5 лет назад

I'll get on that right away!...... Ok all done..... here's my second channel...ru-vid.com/show-UCSzvQG5seY5dA59RIkZlicg 😂

@sanaajennings6285 5 лет назад

@@melissamaribel 😭

@whowas1203 2 года назад

OH my god i really thought i was going to wing it because i could not save my life doing these problems. I understand it a little bit more and i think I'm buying the notes chem 2 if i pass

@emily6869 4 года назад

I am not sure why, but on the conversion os CO to Fe, why is the grams of Fe only 55.85g? In the reactants it is 2Fe, so why was the molar mass not done 2Fe, only 1Fe? Is it because that is just converting it back to grams? So the Fe is only one because that is the conversion done? The rest totally helped me. Before, I didn't even know where to start. This clarifies limiting reactant problems so much.

@melissamaribel 4 года назад

For molar mass it's only 1 mole of that element or that compound, so for Fe we are not looking at the mole to mole ratio or the balanced equation instead we only want 1 mole of Fe = molar mass of just 1 Fe.

@emily6869 4 года назад

@@melissamaribel Thanks!

@stellalee2946 3 года назад

girl is so relatable

@kelvinksimwawa4138 2 года назад

I have exams in August 😥😥😥i have never been so good in che 110 I really need ur help Madam and this videos is so helping

@lsnickysfiso4580 5 лет назад

Someone please help would appreciate If magnessium burns in the air to form magnessium oxide accordingly to the following balanced equation 2 Mg +O2->2Mg If the percentage yield of this reaction is only 80% calculate the mass of magnessium that needs to be burned to produce 30g of magnessium oxide

@melissamaribel 5 лет назад

Hey there, did you still need help with this question?

@lsnickysfiso4580 5 лет назад

@@melissamaribel yes please i would appreciate ♡

@lsnickysfiso4580 5 лет назад

@@melissamaribel please

@melissamaribel 5 лет назад

You are a given the percent yield of 80% and the actual yield of 30 g MgO 1)Start with finding the theoretical yield by plugging the percent yield and actual yield into the percent yield formula shown at 23:29. 2) After you found your theoretical yield of MgO you will work your way back to grams of Mg. So you'll go from grams of MgO to mol MgO to mol Mg to grams of Mg and you are done. Make sense?

@lsnickysfiso4580 5 лет назад

@@melissamaribel thanks i truly understand 😄 thanks melissa you are a star 🙆🙌