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Regioselective Enolization and Thermodynamic vs. Kinetic Control

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We know how to make enolates, but when two structurally different enolates are possible, how do we get the one we want? It has to do with selecting the right base. In explaining this, we will also discuss the difference between thermodynamic vs. kinetic control during a reaction.
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Опубликовано:

22 авг 2024

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Комментарии : 30

@ShahinAhmed-tl7tw 3 года назад

Man you are the coolest chemistry teacher I have seen in my 4 years of bachelor degree

@ponnusamisaravanan4673 4 года назад

Outstanding explanation

@Nicole-on3qt 3 года назад

Thank you so much for your content! Due to Corona virus there were no lectures in organic chemistry at my university and you're helping so much to learn the basics! Thank you!

@Merciless204 3 года назад

I'm in graduation and watching his channel I've been watching him for years now

@Textbook000 5 лет назад

Truly incredible

@thechemistlife 5 лет назад

You are awesome. I'm from India and your language is so clear..one more reason to love Chemistry ☺

@Alchemist_171 4 года назад

Lol

@Alchemist_171 4 года назад

go home

@valentingallier6147 5 лет назад

Thank you professor !

@abdulhaif9112 4 года назад

A brilliant explanation. Thank you so much 😊,

@Morfeucomvoce 4 года назад

Excellent video.

@sniperammow4865 5 лет назад

Lol we are doing this is class today, I am ahead boi!

@EpmMaxim 4 года назад

thank you!

@indrathapa1752 5 лет назад

thanks🙏🙏

@safwanhassan8076 5 лет назад

highly appreciated

@sniperammow4865 5 лет назад

Safwan Hassan lol

@edonSG 4 года назад

Why is the thermodynamic enolate more stable? What are the effects of the methyl group, what are they actually stabilizing?

@ProfessorDaveExplains 4 года назад

more substituted alkenes are more stable in general, hyperconjugation

@edonSG 4 года назад

@@ProfessorDaveExplains thanks for your quick answer. I still dont get it, as far as i know hyperconjugation means the alkyl Groups are able to push electrones to a carbon that has electrone deficite, but in this case the negative oxygen is already pushing negative charge to the double bound that has a high electrone density. So why should that be stable? If it was a carbocation then it would make sense, propably im not getting where a carbocation is being formed here?

@ProfessorDaveExplains 4 года назад

No carbocation, the same principle applies to any sp2 carbon.

@rassimsimou1594 2 месяца назад

Good

@giuliascalzo512 2 года назад

Hi! What would happen if we formed a double enolate? Which site would react?

@sciencenerd7639 2 года назад

amazing

@nirvikpaul9603 3 года назад

Sir in case for thermodynamically controlled reaction the two possible enolates have approximately the same free energy of activation as you said , so if the free energy of activation is same then both have equal rates . And if both have equal rates then there is no way that one is major and the other is minor.

@dang.5258 2 года назад

Theoretically yes, but you are missing the Alkene stability. Hydroxide can de-protonate forming an Alkene that has 4 groups and the other 3. Therefore the one with four groups will form in higher percent.