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Sizing a Heat Exchanger: Parallel Flow 

LearnChemE
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Organized by textbook: learncheme.com/
Finds the length of a concentric, parallel flow heat exchanger using an overall heat transfer coefficient and the log mean temperature.
Made by faculty at the University of Colorado Boulder Department of Chemical and Biological Engineering.
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5 мар 2013

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Комментарии : 12   
@prohabetamu
@prohabetamu 5 лет назад
please can you tell me what kind of software did you use to do this educational vedio? i love it, thank you.
@mahmoudadel961
@mahmoudadel961 3 года назад
Thanks a lot.. That was very helpful
@orlandosalazarsermeno9630
@orlandosalazarsermeno9630 10 лет назад
I like the way you explain is very clear, thank you for your input!!, I am trying to calculate the length of a inmerse evaporator to produce 1 ton of ice, like iceblock through a brine but would like to know the dimensions to use, I would appreciate if you can give me an idea if the same formula applies
@calvinla5641
@calvinla5641 9 лет назад
shouldn't the overall heat transfer coefficient be U = (1/h_oil + (radius_oil / radius_water) * 1/h_water) ^ -1? Since we're in cylindrical coordinates there has to be the ratio of pipe radii to account for a constant heat flux in the varying pipes diameters?
@norbertdrage
@norbertdrage 4 года назад
You're correct about needing the pipe radii ratio, but your equation is back to front (done w.r.t. to h_inner, not h_outer); U = (1/h_oil * [r_water / r_oil] + 1/h_water) ^ -1
@kas.10th
@kas.10th 2 года назад
No. That is why in the beginning of the problem she assumes "thin walled" so she can throw out that term.
@janithkonara6621
@janithkonara6621 2 года назад
Can you tell h values of water and oil,how it take
@hariharan2321
@hariharan2321 6 лет назад
thanks alot u have help
@wiwidsetyo7086
@wiwidsetyo7086 7 лет назад
Why in the design equation there is no conductivity coefficient since using different material for heat transfer will have different conductivity
@norbertdrage
@norbertdrage 4 года назад
Only convection is needed; pipe wall is described as thin (r_pipe_inner-wall ≈ r_pipe_outer-wall), therefore resistance through pipe wall is negligible (but yes, presenter didn't include pipe ratios).
@DKTPAirsoft
@DKTPAirsoft 4 года назад
i love you
@haroonibrahim2620
@haroonibrahim2620 4 года назад
Good video for understanding concepts for first year Chem engg students but bad video for actual engineers sizing heat exchangers. Often times people are yelling and screaming not knowing the heat transfer coefficient. That is never known. No one tells you either. You have to work it out using the dimensions number equations. This video basically shows you the last step in designing the exchanger (if you don't include pressure drop calculations) when all values are known.
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