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Parallel & Counter Flow Heat Exchangers (LMTD): Heat Transfer for Mechanical Engineers 

Mike Schertzer
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In this problem, we design a shell and tube heat exchanger. Specifically, we look at the difference in heat transfer area required by using a parallel or counter flow heat exchangers.
Heat exchanger problems typically have one of two potential main goals: (a) find the heat transferred between two fluids, OR (b) find the area needed to achieve a required target heat transfer between two fluids. In this example, we go through a systematic process to find the area required for shell and tube heat exchangers using the log mean temperature different (LMTD) method. I believe that understanding this process will allow you to solve any heat exchanger problem.

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22 мар 2020

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Комментарии : 9   
@OptimEnergy_co
@OptimEnergy_co 2 года назад
awesome thank you
@truongphamnhat7062
@truongphamnhat7062 Год назад
thank!
@nawafaleid196
@nawafaleid196 3 года назад
Your just awesome, very clear logical explaining.. Can I ask you for a copy of the matrix ?
@mikeschertzer941
@mikeschertzer941 3 года назад
Thanks. I'm not sure what the best way to do this would be. It might be easiest for you to take a snip or screen capture of the matrix when it's in the frame (e.g. 2:35)?
@davidholmes2157
@davidholmes2157 Год назад
thanks a lot, great explanation! Maybe you should consider using a pop filter over your mic. Just trying to help and not trying to be rude.
@mikeschertzer941
@mikeschertzer941 Год назад
Thanks David. These were some of the first videos i made. I agree that the pop filter helps.
@mahirkarim9566
@mahirkarim9566 Год назад
When calculating the area of the parallel or counter flow heat exchanger, I noticed that the units in the denominator do not align. You left the log-mean temperature in units of Celsius but the overall HT coefficient as W/m^2 K. In this case, wouldn't we have to convert the log-mean temperature to Kelvin in order to get the correct area for the heat exchangers?
@mentor1324
@mentor1324 Год назад
no
@sevenmaster7820
@sevenmaster7820 2 месяца назад
I don't have effective heat transfer co efficient value! And not even hi and ho value
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