SN1 Exercises (1) Simple Examples

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In this video, you'll find straightforward SN1 exercises with the intent to practice where the bonds form, where the bonds break, basically figure out what the product of this reaction is. The second little wrinkle in this reaction is that you should draw out all substitution products, so there will be some cases where you will have just one product and some where you have two.
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Practice working on doing simple SN1 exercises. Organic chemistry exam prep

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17 сен 2024

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Комментарии : 41

@JeanEtteHeavens 7 лет назад

i wish you were my teacher. Thank you so much.

@HalfPriceTutors 10 лет назад

These videos are really awesome. Great job!

@keziahfongod7975 2 года назад

I will start by thanking you so much for the videos. They were so helpful. I have a question tho... Concerning the first exercise, why is there only one product? From my understanding, there have to be two products formed since a carbocation is sp2 hybridized. Thanks in advance for your reply.

@toritavernier419 2 года назад

Because there is no stereocenter! If there were, then it would be 2! Hope this helps:)

@helenamarek7926 2 года назад

It’s achiral, so it isn’t possible to form a racemic mixture of an achiral molecule as they are optically inactive

@keziahfongod7975 2 года назад

@@toritavernier419 thank you

@keziahfongod7975 2 года назад

@@helenamarek7926 thanks alot

@MasterOrganicChem 2 года назад

You're welcome! If you found this video helpful, Our MOC membership has a lot to offer. Check it out here: bit.ly/2YctxPb

@OrcjaEnglish 6 месяцев назад

It was helpful. Thank you, Sir.

@sportsport1654 5 лет назад

Thank you very much this are onlyone vudeis on youtube ehich explains nucleophilic reactions to be understood and on the end I know it solve by myself. So thank you very much.

@AyushRaj-wp8dr 2 года назад

keep making this type of they are just awesome

@imanihalley98 Год назад

In the last one why did you not do a hydride shift. Since it is adjacent to an allylic carbon which is much more stable then a secondary

@MaMalykPoptart 7 лет назад

In the second problem, why does the oxygen on the left attack the carbocation? There are two oxygens with the same amount of lone pairs so why can't the oxygen with double bond attack the carbocation?

@SherryKao16 6 лет назад

Because the other oxygen has a double bond and that's harder to break

@superhessu3 3 года назад

@@SherryKao16 is it also partly because I -ion will take H+ from OH which causes O to be O negative and that's why the main product is ester and minor product is HI?

@travguy56 8 лет назад

Thank you so much!!!! I actually understand all of this now!!!! Its nice to finally not feel clueless in orgo lol

@roshinvarghese6879 5 лет назад

same here man

@pinkybananas1 8 лет назад

in the second exercise, are there no stereoisromers bc there is no asymetrc center?

@user-ce5fp2qu5z 2 года назад

Why is the alcohol from problem 1 not deprotonated but it is in problems 3 and 4?

@lisanation2203 6 лет назад

how do you know when your carbocation is flat or not?

@lisanation2203 6 лет назад

please help URGENT 🙏🙏🙏🙏

@chemistry7197 3 года назад

@@lisanation2203 hybridization of a carbocation is sp2 and sp2 is palnar

@uppermoonzeroo 3 года назад

hey i have Q i could use the proton transfor for cl to make HCl

@yegimousavi5097 4 года назад

Thanks a lot✌🏼

@bnirtlepmc 8 лет назад

thank you!

@nob3814 2 года назад

why didn't we draw the strereoisomeres?

@urluvpac 3 года назад

Cool

@zehra4422 4 года назад

thank you so much🌸

@urluvpac 3 года назад

Awesome

@JeanEtteHeavens 7 лет назад

I have a question, I realized on eqn 1 and 4, the final products had lone pairs but the final products for 2 and 3 didn't have. Is there a specific reason or you just chose not to put them there?

@Dsmlee105 7 лет назад

The lone pairs are implied in 2 and 3.

@Kymv8382 7 лет назад

Yeah, I'm pretty sure he just felt lazy didnt wanna put them lol .

@ibrahimrehman8737 3 года назад

I heard from my teacher that sn 1 or 2 reaction only occurs in alkyl halide

@IamYou26 Год назад

Yes

@Mohana_15 7 лет назад

where did the hydrogen go in 1st,3rd,4th reactions?

@MasterOrganicChem 7 лет назад

There are ways of answering "where did the hydrogen go" ? 1. Missing acid-base reactions: In the first reaction, H2O attacks the carbocation and becomes -OH2(+). One of the hydrogens is then removed in an acid-base reaction by another molecule of H2O, leading to H3O(+)Cl(-) [drawn in red] and the neutral alcohol product. In the interest of space, the acid-base reactions that give the neutral products are omitted in the 2nd, 3rd, and 4th reactions. 2. "Hidden" or "implied" hydrogens not drawn in 4th reaction. Note that HOCH2CH3 attacks the carbocation, and a hydrogen is drawn in, but not drawn in the next diagram. However it is still there - this is an example of a "hidden" or "implied" hydrogen from a line diagram. In the figure where the new C-O bond is a "wedge", there is a "hidden" hydrogen on a dash. In the figure where the new C-O bond is a "dash", there is a "hidden" hydrogen on a wedge. They were not drawn in to save space, although in retrospect I should have put them in. Thanks for your comment!

@user13947 12 лет назад

I think im gona get another A....!!!!!!!

@user13947 12 лет назад

I love you

@da_kamisama 4 года назад

❓❔❔❔❓

@urluvpac 3 года назад

Awesome

@MasterOrganicChem 2 года назад

Thank you! If this video was helpful, you may want to check out our month-to-month MOC membership for access to over 1500 quizzes, Flashcards, the Reaction Guide, and more. Check it out here: bit.ly/2YctxPb