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Solving equations with lambert w function  

Dr Ji Tutoring
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29 сен 2024

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Комментарии : 10   
@MsHojat
@MsHojat 6 месяцев назад
There's no explanation as to why the given solution is helpful/useful for anything though.
@NitroKitKat
@NitroKitKat 6 месяцев назад
Welcome to math
@darcash1738
@darcash1738 5 месяцев назад
It seems like the exponent needs to match the added x term to work out. I made a gen solution doing the same process. AB^(Cx^n) + Cx^n = D x^n = [-W(AB^D * lnB)/lnB + D] / C If there’s a way to do it where they don’t need to match as Cx^n, what is it?
@MarkGlowInTheDark
@MarkGlowInTheDark 6 месяцев назад
I don't have a clue what that whole explanation is. What i do know is: 2X+X=3X. So 4:3=1.666667 so X is 1.66667 in my head
@Ykulvaarlck
@Ykulvaarlck 6 месяцев назад
since when is 2^x equal to 2*x
@awaken6094
@awaken6094 6 месяцев назад
2^x is not 2x
@NitroKitKat
@NitroKitKat 6 месяцев назад
ok so fyi : 2 to the power of x isnt the same as 2 times x , if i say 2 to the power of 3 is 8 , 2*3 is 6... so its not what u think it is
@MarkGlowInTheDark
@MarkGlowInTheDark 6 месяцев назад
@@Ykulvaarlck well i am not a mathematical person and have a ton of trouble with formulas. So to keep it simple i was wrong
@MarkGlowInTheDark
@MarkGlowInTheDark 6 месяцев назад
@@NitroKitKat thanks for explaining, sounds logical. I never liked mathematics xD. That makes this sum even way more difficult
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