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Can You Use Lambert's W Function? 

SyberMath
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29 сен 2024

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Комментарии : 15   
@mbmillermo
@mbmillermo 11 месяцев назад
I solved it "by inspection". Basically, doing what you did but skipping the W(). Just write ln4 as 2ln2 = ln2*e^ln2, and you can see that the answer is x = ln2. Many of your problems work that way, but then I'm always wondering "is that the only solution" -- I can hear your voice in my head when I say that!
@SyberMath
@SyberMath 11 месяцев назад
😁
@BlaqRaq
@BlaqRaq 11 месяцев назад
I almost forget to like (already subscribed).
@SyberMath
@SyberMath 11 месяцев назад
you must be. You write good comments
@thorinpalladino2826
@thorinpalladino2826 11 месяцев назад
Not sure you need some special function. X*e^X= ln4 can be rewritten in exponential notation as e^(X*e^X)=4 or (e^X)^e^X=4 or (e^X)^e^X=2^2 So e^X=2 X=ln2
@tsar_asterov17
@tsar_asterov17 11 месяцев назад
Hey that would be right yeah! That's pretty cool. I guess he wanted to just use it as an example to show the lambert W function, which is a very cool function.
@saliryakouli1260
@saliryakouli1260 9 месяцев назад
Maybe not for this equation but you need it for other equation that can't be solved otherwise
@dr.rolandzagler8831
@dr.rolandzagler8831 2 месяца назад
Hello, in yt there are a few videos which are dealing with the so-called „g(log)-function (e^x=zx). It is said that the g(log) method can be used instead of the „W Lambert function“, but for the g(log) function no results of calculations are shown, neither by Wolfram Alpha, nor by the function curve itself. It would please me, if you gave me some detailed informations of the status of g(log) 😇. THX very much. Roland
@SidneiMV
@SidneiMV 5 месяцев назад
x = W(2ln2) = ln2
@saliryakouli1260
@saliryakouli1260 9 месяцев назад
x=w(ln(4))
@rakenzarnsworld2
@rakenzarnsworld2 11 месяцев назад
x = ln2
@trojanleo123
@trojanleo123 11 месяцев назад
x = ln2
@남이명준-s1b
@남이명준-s1b 11 месяцев назад
x=ln2
@mathswan1607
@mathswan1607 11 месяцев назад
x=ln 2
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