If you are trying to determine this size of cpc to use, then how are you calculating Zs which is Ze +R1+R2. R2 is cpc so how are u getting your Zs to find your fault current.
Great video, just watched it for a second time. I take it this can be applied for main earth sizing as well? Just use a Ze instead of a Zs and it’ll all be the same? That would be the only time I would use the equation i think.
Great video! Question:- Does the factor of K @ 30 degrees not get used? If the initial temperature isn't >70 degrees? In which case 143 would be used, not 115? (As 115 is assumed initial temperature of >70, but in a house etc >70 is potentially unrealistic?)
Hi Ricky1396. Thanks for watching. Good question. My understanding is, when dealing with fault current calculations the value of K is to correspond with the final temperature.