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Using Spectroscopy to Solve for Concentrations in a Mixture 

Double0Pi
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Explains how you calculate concentrations when you have two components that absorb in similar wavelengths.
This video assumes you know about Beer's Law. If not, you may want to watch this video:
• Absorbance & Emissions...

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21 окт 2024

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Комментарии : 22   
@EduardoAlbertodePaulaCarvalho
This video was awesome. You saved me!
@MuhammadZainAmin
@MuhammadZainAmin 10 месяцев назад
Amazing explanation
@karlinramirezjimenez2936
@karlinramirezjimenez2936 11 месяцев назад
So helpful thank you and very easy to understand
@cuterobot7836
@cuterobot7836 6 месяцев назад
Thank you so much!!! This helped me to make my lab report!
@Double0pi
@Double0pi 5 месяцев назад
Always glad to help!
@raktimroy3797
@raktimroy3797 10 месяцев назад
Very impressive explanation..Thanks from India
@Double0pi
@Double0pi 5 месяцев назад
Glad I could help!
@atulnagar8132
@atulnagar8132 2 месяца назад
what is the method's name, and how can I reference it?
@vqn_uk
@vqn_uk 2 месяца назад
How can I estimate the concentration of substance A and substance B in the mixture when the info given: absorbance at the same 2 wavelengths for and B, A concentration and B concentration are the same, absorbance of mixture?? It was on paper based exam, no access to excel whatsoever xx
@Double0pi
@Double0pi 2 месяца назад
The video literally walks you through how to do this
@vqn_uk
@vqn_uk 2 месяца назад
⁠@@Double0piI have tried to follow the steps and I am not sure where do I make mistake, my concentrations come up negative 😭. Absorbance at 238nm- Phenobarbital 0.551, Oxycodone 0.477, Unknown 0.652 At 280nm- Phenobarbital 0.07, Oxycodone 0.05, Unknown 0.493. Both samples Phenobarbital and Oxycodone are at 5.20x10^-5 M concentration. The molar abs that I calculated ( molar abs= A/C ) are at 280nm- Phenobarbital 1346, Oxycodone 962. At 238nm- Phenobarbital 10596, Oxycodone 9173. step 1 result: 0.652-9173 Coxycodone/ 10596= Cpheno step 2) 0.493= 1346 (0.652- 9173 Coxy/ 10596) + 962 Coxy Step 3) 0.493= 0.0828- 1165 Coxy + 962 Coxy 0.4102= -203 Coxy Coxy= -0.002 Step 4) 0.652- 9173 (-0.002)/ 10596= Cpheno Cpheno= -17.694/ 10596= -0.00167 😭😭😭
@chadiskapascal4181
@chadiskapascal4181 2 года назад
How did you get the absorbance to be A= 0.72 and B=0.77?
@aishaomar11
@aishaomar11 Год назад
You get those from measuring the sample under the UV spectrophotometer
@Double0pi
@Double0pi 10 месяцев назад
@@aishaomar11 Exactly.
@SFUEng
@SFUEng 2 года назад
You saved my ass I can't thank you enough
@Double0pi
@Double0pi 2 года назад
Glad to help.
@music-e4k5m
@music-e4k5m 2 года назад
very helpful, thanks.😊
@battlepans1927
@battlepans1927 10 месяцев назад
Why did you pick 550 nm
@Double0pi
@Double0pi 10 месяцев назад
It's just an example. You can do this for literally any set of two wavelengths. Heck, you can do it for three if you are willing to wrestle with the math.
@battlepans1927
@battlepans1927 10 месяцев назад
@@Double0pi Thank you! You have (hopefully) saved my lab report. Idk if I did it right but I trust your lesson 😭😭
@MuhammadZainAmin
@MuhammadZainAmin 10 месяцев назад
Amazing explanation
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