Voltage Multiplier Circuit Explained (Voltage Doubler, Voltage Tripler and Quadrupler Circuits) 

The timestamps for the different topics covered in the video. 0:21 What is Voltage Multiplier Circuit? 1:41 Application of Voltage Multiplier Circuits 2:32 Voltage Doubler Circuit 8:40 Voltage Tripler and Quadrupler circuit

I love how you break it up into half-waves and remove diodes that are off. Makes it so much easier to visualize what’s happening

Clearest explanation I've seen on how this circuit works. The first stage is easy. It gets a bit harder to see subsequent stages. Your explanation makes it easy.

6:35 brought a smile to my face because I've been searching for an explanation of what happens at the midway point of the half cycles when the diodes begin to discharge. I'm happy you explained it and I now understand perfectly. Thanks!

earlier i used to find electronics very difficult ,bt your lucid explanation makes it easy to understand,Thanks a lot sir

Excellent video. Very detailed and clear instruction on the voltage doubler circuit. It's one of the best out there. Thank you for taking the time to share you knowledge. This is a very important circuit for learning AC circuits. It's used in microwave ovens as well at the output of the step-up transformer to power the magnetron.

Thanks for this awesome video. I like how you have analyzed the circuit from fundamentals!

Excellent tutorial. This is the only correct video on youtube that matches realworld and simulation observations. Other videos such as those by 'Organic Chemistry Tutor' and loads of other guys who have received positive reviews are wrong!! They all claim that diode D1 is forward biased all through a half cycle and capacitor C2 gets doubled in the other half. I was always wondering why diode D2 doesn't conduct in the 1/4th cycle and thanks to this channel for clarifying the correct working principle.

Believe me you explain things better than most university professors. I just understood this nagging topic from you. Many thanks

Thanks for this amazing video 👌👍

Nicely explained... Thanks!

Thank you for sharing your demonstration. I am looking forward to learning more about amplifiers.

@11:41 assuming C2 = C3 during this cycle there is charge sharing therefore C2 does NOT dump ALL of its voltage(2Vm) into C3 in the first cycle, first iteration will have 0.5*(2Vm) volts across both C2 and C3. It takes X amount of iteration for C3 to have a voltage 2Vm depending on input voltage. What happening here is C2 is constantly getting charged from the supply then shares its charge with C3 UNTIL the voltage across C3 = 2Vm. In summary, due to charge sharing between C2 and C3 it takes multiple iterations for C2 and C3 to reach 2Vm. The math is Vc2 = Vc3 = 0.5*(2Vm) -> first cycle Vc2 = Vc3 = 0.5*(2Vm + Vinitial) = 0.5*(2Vm + 0.5*(2Vm)) -> second cycle Vc2 = Vc3 = 0.5*(2Vm + Vinitial) = 0.5(2Vm + 0.5*(2Vm + 0.5*(2Vm))) -> third cycle Vc2 = Vc3 = 0.5*(2Vm + Vinitial) = 0.5*(2Vm + 0.5(2Vm + 0.5*(2Vm + 0.5*(2Vm)))) ->fourth cycle . . . . . Until Vc2 = Vc3 = 2*Vm

Very well explained, thankyou ❤️

Thank you, you are awesome.

Thanks for the great explanation. Can you include a section on how to calculate the necessary values of the diodes and capacitors?

I need help designing a Voltage Tripler circuit with an input voltage of 110VAC that will power a 330VDC / 2 watt light bulb. Will the voltage tripler circuit that you have designed at 9 minutes work? And what size caps and diodes should I use? I appreciate any help. Thanks!

Nice video but I think that the analysis that you do for the voltage doubler may be wrong. First of all it seems that you are analyzing the initial transient of the circuit, which means that the initial state of your circuit is characterized by all capacitor discharged. The moment, in which I think you commit the first error is at 4.02. you say that the capacitor C1 charges to Vm when the sinusoidal signal reaches the positive peak and then you say that when the sinusoidal signal becomes negative then the diode 2 turns on and D1 turns off. But what happen between the positive peak of the sinusoidal signal and the negative part of the sinusoidal signal? You forgot to analyze that part. In fact, the diode D2 should turn on immediately after the peak of the positive sinusoidal signal. and D1 should turn off in the same moment. So the two diodes change their states much earlier than the moment in which the sinusoidal signal becomes negative. Missing the analysis of that part, will make your analysis not correct. Furthermore, it seems that in your analysis, C1 remains charged to Vm for all the negative cycle of the sinusoidal signal. what make you think that the voltage of C1 will remain constant during the negative cycle? I did not find any reason why that should happen. Try to simulate the circuit and look at the first period of the initial transient: at the first negative peak of the sinusoidal signal the voltage across C1 is actually 0V and not Vm as you state in your video. Overall the dynamic of the circuit is a bit more complicated than what you claim. I am not convinced by your analysis, which in my opinion is just a method to force the correct result. Anyway, feel free to correct me if I am wrong. :) In general, I like your videos, but I do not think that everything can have a short explanation. Good luck for the next videos

Great Video ! Crystal clear explanation !!!

Great work sir...amazing wonderful.

Lot of videos of this topi c,,,but u r the best

Thanks

Amazing Content 💥🔥🔥🔥👍👍

Thanks for making I am understanding it very well

awesome sir..,it helps me lot

best video on the topic out there hope friends will find it

GREAT VIDEO. VERY WELL EXPLAINED. 👍👍👍

Superbb way you are explaining...thanku sr...

beautifully explained.

i am from ethiopian thanks very much

pls make a video explaining the bjt operations ... thank you

Damn, there is something about Indian accent English that makes things easy to understand :D, nice vid man

Thank you so much for the effort

Good explanation, Thank you

Thank you.

thanks for your sharing , a litter confused @7:20 , voltage across c1 is -Vm, Vin is -Vm, according to KVL , Voltage apply for C2 is -2Vm, Why it is -Vm in your presentation ?

It's a very good video

very nice explanation

thank u sir very helpful and nice explanation

This is like the capacitor and diode increase voltage circuit.

Excellent

Shukria Bai

Please make videos on Transducers and sensors

Very good 👍👍

9:50 Why the capacitors will not charge if they are uncharged. (I think all capacitors were initially uncharged, then with your reason even the capacitor c1 should not charge).

In RF energy harvesting system, voltage multiplier is used extensively..

What software did you use for your circuit simulation?

Thank you for the video, very useful especially to initial ramp-up section which is not covered usually in other tutorials. I wanted to find out how i can do AC analysis of this doubler? What is the AC equivalent circuit? I am asking since this circuit is usually connected to AC sources and i want to look at the matching problems. Thank you

good explanation

Tks

pls make videos on transistors

Plz make video on low voltage low power adders and multipliers for mtech students

for the simulations, how do we calculate the values of te capacitors and diodes?

You Slightly Miss An Error At Point When -vm

So c1 only charges from 0 to positive peak and discharges from positive peak to negative peak? But from negative peak to 0, does c1 remain 0 until it reaches passed 0 to positive peak?

At 9.56, why is there no current on C2 and C3?

11:44 I don't think so capacitor c3 will get charge by that path, because the D1 which you short circuited, has V(k)=2Vm and V(A)=Vm, hence that D1 will act as open circuit not short Circuit.... You have simply put a closed path without analysing... ( Don't mistaken me, I really like the content ❤️)

How to calculate the value of capacitor in voltage doubler circuit?

Are polarized capacitors used for these circuits? Doesn’t ac pass through capacitors? How does the charge remain during different cycles?

Excellent video Plz, can this curcuit operate motor 2 amp 100 volt ? Help

Do you know, how to calculate output current for a load of say R, or maximum current output? Thanks.

If we apply a voltage directly to a capacitor only, does it conducts any current? If not then why?

Ok so basically c1 capacitor becomes charged like a battery when the current passes through D1 diode. And capacitor c1 acting as a battery plus the actual power source it doubles the voltage almost. So it's like the power source is a 1.5v ( AC) battery, which releases the current through the c1 capacitor and the capacitor becomes charged 1.5v. And after the first cycle, the direction of the current changes in the main power source battery(because it's AC voltage reverses direction of the current), as a result we end up with 1.5v battery attached to 1.5v capacitor, becoming two batteries 1.5v+1.5v=3v attached to each other plus-minu-plus-minus like inside toy battery pack.

How capacitor C1 discharged through voltage source and charge C2 to Vm , please explain 6:42

@11:45 during 2nd positive cycle Vin and Vc1 cancel each other and cathode of D1 is at +2Vp from capacitor C2 so I do not see how D1 is forward biased. Do you understand my question ? Thank you great video as usual.

⭕⭕⭕Check 11:44 here you are telling that the C3 is getting charged through the path of D1. But current cannot flow through D1 from C2 because 11:28 see the circuit, I mean considering C2, D1 is reverse bias condition. Please check and let me know!

During the negative half cycle equivalent circuit outer capacitor polarities are reversed why Does it possible in practical circuits

sir, how the process stop after doubleing voltage ?

Can we store the voltage that is multiplied by voltage multiplier?

Thank you for explanation. In this exercise, are all capacitor sizes same or different?

What if our input of voltage multipler is continuously fluxing 'varying' ...?what type of multipler is should use?

I don't understand how you can put a polarized capacitor in an ac circuit. C1 gets the ac signal and should explode anyway?

in which software did you do your simulation?

Aap Hindi mein bata dete toh achha hota aur aapne kvl bolake explain Kiya toh aapne likh ke diya hota to achha hota . But all concept is clear..

12:44 which software did sir use for stimulation ?

Hello sir will you please know me what software did you use for simulation??

Please mention the values of the capacitors and their voltages. Thanks.

what is the software that you are using?

Why this circuit we cant use for big loads bro.I mean if capacitor capacity is big then? What about current? Current also added or what? Actually I am a commerce student but also studying little bit electronic plz answer.

In v multiplier current also will multiply or it will reduce...

why did you not consider capacitor voltages when finding the diode states? You have just considered cycle states.

Sir Why will the Vc2 capacitor not charge upto 3Vm in the next cycle?

Is the Ampere at the output will remain same as input

What software do you use to simulate the circuit? Is it paid?

I don't understand when C2 chargues C3 , its current is going against the diode polarity it shouldnt conduce that way my brain is a mess xD

When I made connection of multipler . Output of circuit not desirable as when 6 volt AC applied to doubler circuit .It give15 volts output . also in triplet circuit 23 output Why this happened can u help me Thanks.

At the 4 min mark your schematic shows c2 with the cathode facing towards the positive rail ?. Ami wrong LOL.

Why did the direction of capacitor C2 change

what's the difference between transformer and voltage multiplier? transformers just make the amplitude of the power bigger while voltage multiplier just offsets the power wave?

Will it work with AC and DC both?

Arigatho

how capacitor charged by ac signal?

Why d2 is on while decreasing +ve current

what is the name of the graph software?

what the aplication simulation you use?

8:41

5:30

Send some link of whatsapp group about electronic

Its better if you show the actual

In same circuit, two different explanations of circuit.