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with x³ = 2 and x³ = -1 as the two trivial solutions: x³ - 2 = 0 = (x - ∛2) (x² + (∛2)x + ∛4) and x³ + 1 = 0 = (x + 1) (x² - x + 1) so we get x⁶ - x³ - 2 = 0 = (x - ∛2) (x² + (∛2)x + ∛4) (x + 1) (x² - x + 1) with two real and four complex solutions.
