Great video. Since multimeters and clamp style current meters are ubiquitous and can easily measure RMS voltages, currents and resistance, would this be a "practial" approach? Measure the resitance of the coils in the motor, and then measure the voltage applied to the motor. Then, take a clamp style meater to measure the current drawn by the motor. With V and A, we can calculate apparent power (VA). With the amps and resistance of the motor, we can calculate real power. PF can then be computed.
VAR is easier to understand if you explain it as Voltage Amp Reactance which is what VAR means. Also very easy to explain that VAR is power that is bounced back and forth (absorbed and supplied) between the source and the load but not absorbed by the circuit. Where as real power is absorbed by the circuit.
Bit misleading as at the beginning you state that Var and Watt are equivalent, however you state that the circuit is using 10 ‘amps’ at 240 v which has to be equivalent to a total power use of 2400VA as you stated or in any case 2400 watts as per your statement of equivalents. Than later is calculated a wild value for the reactive power, which does not relate to the overall power use, if as you stated that ‘Var’ and ‘Watt’ are equivalent. Reactive field effect loss Is I believe the sum of the ‘ESO’ effect self opposition and the frequency reactive actions. If it is assumed to be 60hz it is the self opposing effect of the inductor at that frequency. Plus the small wire resistance value.
