Resonance and Q Factor in Series RLC AC Circuits

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This tutorial discusses resonance in series RLC circuits. At a particular frequency (resonant frequency), the reactance of the capacitor and inductor cancel, therefore we only have resistance in the circuit. This gives rise to a surge in current.
We are able to select capacitors to effectively cancel inductive reactance at a given frequency. This has the benefit of improving power and efficiency.
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Опубликовано:

18 сен 2018

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Комментарии : 27

@whoknewinfinity1021 3 года назад

we are using your lessons in South Africa. Siyabonga (thank you)

@AtomkeySinclair 4 года назад

Studying for my Amateur Radio Extra Class exam - thanks for the instruction. Excellent content.

@JRJunior8624 3 года назад

I can be pretty critical of some of these, but this one, is outstanding, makes it nice and simple. Excellent work

@masimbamusodza9045 11 месяцев назад

Wooow. I hav been going through other explanations and has been very diffficult to understand. You made everyone travel with you through out the presentation with very simplified explanations. I undestand Series Resonance. Off course i will ask my friends to check you on RU-vid.

@kabandajamir9844 Год назад

The world's best teacher thanks sir

@jammyscoot3646 Год назад

Great video!! Very helpful, I was very confused before finding your videos.

@brandonmwms 3 года назад

Fantastic video. Very clear and intuitive instruction. Thank you. (I am studying for an advanced amateur radio license exam).

@spelunkerd 2 года назад

Isn't it interesting that the formula for resonant frequency is the same, regardless of whether it is a parallel or a series circuit. I scratched my head about that, until I realized that you are simply trying to balance the reactance, so you get 1/(2pifC)=2pifL. Isolate and simplify and you get the formula. This applies whether parallel or series, provided parallel resistance isn't very high.

@raedar7784 4 года назад

you are way better than my professor when explaining these topics

@martyrossiter8485 4 года назад

Very nice explanation

@frankimhof8124 5 лет назад

Very clear explanation. Thank you!

@johnpatrickobra5405 3 года назад

You can also use XL=XC XL=2π(50)(56x10^-3) XL=17.593 17.593=XC 17.593=1/((2π)(50)C) C=1/((17.593)(2π)(50)) C=180.930microF

@EngineersAcademyLTD 3 года назад

Very true - in fact the formula for resonant frequency is derived from the relationship XL=XC that you propose here, since: XL = XC 2*pi*f*L = 1/(2*pi*f*C) f^2 = 1 / (4*pi^2*C*L) f = 1 / (2*pi*SQRT(LC))

@MclarenF1rocket 4 года назад

Great explanation ! subbed!

@aryanviolett4606 4 года назад

damn... this video is amazing! thanks man :)

@user-hy3tr3rx9z 3 года назад

Thank you sir for this, it is help me a lot.

@italktoomuch6442 5 лет назад

I hope that this channel's views, in future, are most conveniently plotted on a logarithmic scale.

@EngineersAcademyLTD 5 лет назад

Thanks for the topical comment Niall! Have you seen our tutorials on log graphs?!

@hackercop 2 года назад

This was a great video thanks

@rickyjohnson1342 3 года назад

You deserve more subs 👍🏻👍🏻

@Genet665 4 года назад

Thanks!

@Learn-Math-And-Science Год назад

Good video

@swethasathuraman3118 4 года назад

Thanks

@jakemackenzie4936 2 года назад

What formulas would you use to calculate the current when the frequency value changes?

@EngineersAcademyLTD 2 года назад

Hi Jake - this video discusses the method for series RLC circuits at a given frequency: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-gq8cU1IbLeU.html