Resonance and Q Factor in True Parallel RLC Circuits

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This video introduces true parallel RLC circuits. In this circuit, there is an inductor in parallel with a capacitor, but the internal resistance of the inductor is also taken in to consideration.
You will be shown how to calculate resonant frequency, dynamic resistance, current through the inductor coil and capacitor, as well as supply current.
Once currents throughout the circuit have been found, the Q factor (quality factor) can be determined for the given circuit at the resonant frequency.
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Опубликовано:

2 окт 2018

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Комментарии : 21

@segos2010 2 года назад

I am a teacher at a technical college in South Africa. You answered a question that I always had regarding the use of series and parallel resonant circuit formula. Thank you for your video.

@notsocrazyjohn5348 4 года назад

Thank you so much. I feel so lucky to have found this site. Cheers John

@hawaiiskjortaa 3 года назад

Who else was nervous over the sudden integral between 5:16-6:00

@EngineersAcademyLTD 3 года назад

Haha sorry to have startled you

@zdzisawk5198 2 года назад

I love your lectures. Thank you so much

@irishchocolate3872 Год назад

I wish Hewlett Packard continued to make RPN scientific calculators. They have a distinct advantage in electrical engineering over algebraic machines.

@mahdigaben2963 5 лет назад

Thank you sir!

@saudonmars 5 лет назад

Thank you

@gambitillmind 2 года назад

Amazing brother

@mtopangaprimo2556 Год назад

May I ask a question?.Is the advanced formula for all non neglible resistors on Paraller.or the formula changes with circuit setup?.am Stuck on this. Thanks for the help as well as for the videos you upload.

@EngineersAcademyLTD Год назад

The "advanced" formula is specifically for this particular circuit arrangement.

@AkashKumar-jc9kb 3 года назад

Thanks 👍

@dnowbrg6080 4 года назад

@yiansansoon3093 4 года назад

may I ask why in this advance formula need to put (R^2) /(L^2) ?

@konstantinparchevsky2031 3 года назад

Impedance of this circuit is calculated in the same way as resistivity in the DC circuit (L and R are in series and LR are in parallel with C): Z = (XL+R) || XC, where XL=iwL, XC=1/(iwC) are the impedance of the coil and the capacitor respectively, w=2 pi f is the cyclic frequency, f is the frequency, i^2=-1 is the imaginary unit, R1||R2=R1 R2/(R1+R2) is the resistivity/impedance of resistors connected in parallel. By definition, resonance occurs when current I and voltage U are in phase, which means that at resonance Z is real. So, to find the resonance frequency we need to solve equation Im[Z]=0 with respect to w, which gives the required formula.

@aljosagraovac8308 2 года назад

How to get the formula for fo? i tried with impendance but i can't get that formula. for Resonance part (imaginary part must be 0 for resonance) i get something like iwL/(R^2 + (wL)^2) + wC = 0 because of that i get a "-" which makes me problems... Any help?

@EngineersAcademyLTD 2 года назад

Kaiser has a derivation in his book, pg 5-27: books.google.co.uk/books?id=nZzOAsroBIEC&lpg=PP1&pg=SA5-PA27#v=onepage&q&f=false which may be helpful

@aljosagraovac1918 2 года назад

@@EngineersAcademyLTD thank you, i will look into it.

@FlurinKoenz Год назад

How do you derive Rd = L/(RC)? Thanks a lot!

@EngineersAcademyLTD Год назад

The derivation is not very nice, but simply put it is expressing RD as the parallel arrangement of R+jXL and -jXC, substituting the expression for f0 for frequency where it arises in the reactive terms, and then simplifying.

@FlurinKoenz Год назад

@@EngineersAcademyLTDI just figured it out: R_d = Re{Z}. The derivation was not too bad. Thanks a lot for you video, your help and your fast response!