Let me add my two cents to it... this is a very strong second order LPF due to huge capacitors. If you calculate the pole frequencies you will get very small values, both less than 1 Hz (by putting s=jw in the T/F). The input is a periodic square wave with a fundamental frequency of 1000 Hz ie the first sinusoidal component in its Fourier series expansion will be of 1000 Hz frequency. The average value of the periodic square wave over one time period which corresponds to its dc content turns out to be 2.5 volts. Since the poles will start the rolling-off of the magnitude at frequencies as small as 1Hz, this attenuation will become huge at frequency even of the first fundamental (1000Hz). This is the reason why the voltage across capacitors is almost equal to dc content of the input. In frequency domain it's much easier to figure things out.
Thanks a lot for detailed discussion. This is very helpful for analog interviews. Finding analog interview questions is very tough. Keep posting more. A good initiative.
Its basically PWM modulation on a second order LPF, if the duty cycle is 50% then answer is half of vdd which is 2.5. If you change the duty cycle, then output will change accordingly
Hi there thanks for the videos! Keep em coming! Just out of curiosity, may I know why the discharge and charging time constants are not equal initially?
Thank you bro for such wonderful video. I saw your videos and understood new concepts. On that basis I'm able to join Texas instruments for internship as an analog intern. Thank you once again...keep uploading...keep rocking !!
@@analogeasy-peasy7559 request for you...Will you suggest me some necessary stuffs or topics or some softwares which might be useful for an analog engineer; so that I can prepare for it and work better during my internship...Any suggestion based on your experience...!? It will be great help for me 🙏
Nice video. Sir I am not able to understand how the waveform is converging to 2.5 volts. I tried to derive from the equation but not getting the result.
Why not add two switches,one is above capacitor 1f and the other is above 10f capacitor??😊 Time is t1 and t2😊 First t1 closed and then or First t2 closed and then ....
Brother every one are telling RC Circuit is very important concept . Could you tell any sources for preparation of RC circuit so that we can answer in written test and interview
Nagendra Krishnapura lectures are freely available on RU-vid you can refer that. Also go through all the GATE EE and EC questions bank for Networks at least. Else Transient and Frequency response is what the interview goes around. :)
Hii Naveen, actually we guys have shifted to Bangalore like on 4 th April. We are trying to find a good flat and settle in hear. There are many new challenges to handle in the new city but surely we need to get some time and get back to what we love the most. ^_^
@@nidhigupta4461i believe that 1khz square wave input is of 50% duty cycle. The RC network acts like a low pass filter and averages out the 50% duty square wave to approximately 2.5V (50% of 5V)
