Pedigrees Instructor: Genevieve Gould View the complete course: ocw.mit.edu/7-01SCF11 License: Creative Commons BY-NC-SA More information at ocw.mit.edu/terms More courses at ocw.mit.edu
I know people asked this one year ago but here is a way for doing these in like 30 seconds max: If it skips a generation anywhere, it is recessive, if not and it's in all: dominant Is it gender biased? Do you see mostly males? Then it's x linked. That way you can identify the type in 10 seconds. For probability, you need experience or just more logical thinking do this fast. Mainly, just think about possible genotypes, which one is heterozygous, which one is homozygous. And just memorize probabilities in a basic punnet square.
thanks for the first two rules .Although im 4 years late but for the probability you could apply the product rule for independent events. imo its much easier than memorizing punnette squares.
I prefer to say that in the punnet square you put not the genotype of the parents but the gametes, so it is even easy to calculate the probability as each alele has 1/2 probability in each gamete to calculate the genotype of the sons and daughters
YEESH! You'd think MIT would have digital chalkboards with touch screen drag and drop options, not a frickin CHALKBOARD LOL!!!. All joking aside amazing in depth video. Very helpful!!!
On your Punnett square exercises you ignore the probability that the progeny may be a male at exercise iii) and a female at exercise iv) but thats like telling the gametes: 'Ok listen up: you may only make an XX fertilised ovum now, and now you may only make an XY fertilised ovum now.. '
I think that's because we knew whether the offspring we were looking at was male or female. So the other half of the Punnett square wasn't necessary. We already knew whether we had XX or XY.
Something I have discovered for myself recently, that logical symbolism(all Maths are this) can be used to express situations in an exact manner and therefore exclude any other situation is something that when it can be used, should be used. Otherwise the way this exercise is described in this video is of excellent quality like pretty much all that MIT puts on the net: more power to you!
There’s no male-to-male transmission in X-linked as the father only passes on Y chromosome to the son. So if the father is affected with X-linked disease, the son will not be affected by the same disease unless the mother is a carrier.
I don’t understand what she is saying either because the son receives the X chromosome from their mother. They only receive a Y chromosome from their father. She is confusing.
Always know that if both yandx will be affected then the child will die, this much knowledge is more than everything to spit at these dhope problem, and Grann Maa you are not telling this fact part , but lecturing big bulky bullshit time waste, modern teaching,thank God still now Jeremy Wade sire is not giving PhD , he will only give that to me 😂
