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Texas Instruments Analog Design Engineer Interview Question

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Analog Design Interview/Screening Test questions for Texas Instrument ,Micron Technology, ST Microelectronics, Synopsys, Steradian semiconductor, NXP Semiconductor, Analog Devices, Intel, Samsung etc.
find opamp output voltage.
#opamp
#circuits
#texasinstruments
#analogdesign
#analog_circuits
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All important interview question-
*Analog Design Engineer Interview Question:
• Find small signal Vo f...
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Опубликовано:

2 мар 2024

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Комментарии : 13

@saivamsi1480 5 месяцев назад

Superb question followed by good explanation

@MANISHKUMAR-ee2ty 21 день назад

Good question with very good explanation. We can apply node analysis at V- and Vo is coming 5Volts. If i am wrong, please Correct me.

@AllenSA_Lily 2 дня назад

Comporator with no feedback circuit and then V+=0,v-＝-1 v+>v- So vo=+Saturation.... ANswer

@dhirajbhoi1639 5 месяцев назад

Please confirm again. How to calculate feedback gain of a opamp step wise. Let me say few steps 1. De-energies the independence source . i) voltage source -Short circuit ii) Current source -Open circuit. Here in state of current source if the source was a voltage source of 1v. Then the opamp have a negative feedback and output of opamp will be 1v. please correct me if I make any mistake.

@AmitBar-Analog_Circuits 5 месяцев назад

Will be depending on the polarity of that 1 V voltage source.

@Hariharan_KA 5 месяцев назад

shouldnt we take -Vdd as -5 volts?

@AmitBar-Analog_Circuits 5 месяцев назад

you can

@AllenSA_Lily Месяц назад

Reverse the direction of the current source And then v-=1v So v->v+ and then vo=-saturation voltage=-5v

@EnlightenedJourney1012 5 месяцев назад

Why did not you use virtual ground concept here... V+ = V-

@AmitBar-Analog_Circuits 5 месяцев назад

Clearly mentioned,as there is not negative feedback.

@AmitBar-Analog_Circuits 5 месяцев назад

And the concepts is "virtual short" not virtual ground

@somswyd 5 месяцев назад

This is purely a hypothetical question with NO practical significance... If the Vo = +5V as described in the video , first of all how is the 1mA current source going to flow in the direction shown ? When the 1mA current "can not flow" , V(-) becomes 0V and Vo becomes 0 as it is ideal opamp... Even in this case the current source can not flow ( if the current source has to flow a current in the direction, its left side has to be + and right side - and is NOT possible here ) in the direction shown and hence v(-) remains at 0v and Vo remains at 0v

@thecreed644 21 день назад

it's an ideal current source, the IV characteristics of this device is a straight horizontal line if we ignore shunt source resistance of the source. This basically means it can provide a constant current output no matter the voltage across it. Current output from a source has no dependency on terminal voltage drops.