Texas Instruments Validation Post Interview Experience 

Eagerly waiting for more such experiences and questions. Thanks a lot for taking time to help the students. Really helpful for the upcoming placements.

Question 4:- not virtual short. answer is similar as 3rd. this is very good logical question..interviewer just ask what is virtual short.there is 2 way to answer 1.some one go through your 3rd answer and 2. someone go through infinite resistance that's problem.(bcz when infinite resistance you can't apply ohms law.V=IR)when you say high resistance so no current flow so voltage is same at both node wrong explanation..and then interviewer ask two point in air and no current flow why not voltage is same everywhere?..🤔🤔🤔...simple answer is when infinite resistance no current no ohm's law so no same voltage.

Bhaiya, I am in B.tech 5th semester. TI will be visiting our campus very soon for the internship program. It will be really helpful if you bring some more sessions like this on Analog Electronics and transients. Thank you very much.

This is like analog olympics. Bravo.

Irrespective of interview experience of the candidate.what material and notes he has prepared and get ready for the interview..provide those notes and materials..it would helps us many enthusiasts.

Hello bro,does TI conduct Off campus drive every year for analog and digital engineer role? And what was the package at your time ?

in 2nd ques. i think, capacitor would neither get full charge (but capacitor will get charge more than half of the value of input) nor fully discharge ps. : do make more contents like these , you guys are really appreciable.

LPF has cutoff freq:- 0.159 Mhz.....and input signal has f= 1Mhz.....system will not allow to pass the input signal...and hence O/p = 0

8:28 this type of plot is called “Hysteresis” Basically, when an op amp has positive feedback, it exhibits hysteresis

Thanks, Sirs very helpful, would love more videos on interview preparation especially for the 1st mcq round like resources to study and from where to practise

Please update more interview question video

I was shortlisted for fit challenge texas instrument 2022,interview went good but still I didn't get through the technical round😕

I think one way of approaching the virtual ground question would be: The negative feedback makes the amplifier closer to an ideal voltage source. Voltage-voltage feedback increases the input impedance by 1+A*beta, which is equivalent to having a (close to) ideal voltage source. The high input impedance implies that if you feed a voltage to the terminals of the op-amp, you would be able to measure it exactly across the input terminals without any drop. This implies no current draw. Just my two cents.

Thank you Sir

great video guys.. bring such videos more

Now these interview videos are so much needed and is worth watching ❤️❤️❤️..thnxx

Guys please continue the interview series

Thnks fr this experience

Very very helpful and loved the way you guys are telling your experiences along with suggestions

There's one mistake that you made. When the frequency is changed to 160 kHz, then at that time the time constant becomes much less than T/2, thus the capacitor will charge and discharge completely.

This is very useful. But add experience for analog design roles as well. I have heard that design roles ate difficult to crack

Thanks for sharing your experience. From which college you are doing Mtech?

Thank you

In last question we have direct formula for practical opamp gain

Amazing and thanks

Sir, How can I get internship in texas please help 🙏

Very helpful

Sir aapka selection hua tha?

Great Video! and an even greater initiative! I have a request that please discuss thoroughly till you arrive at the final answer (and what are potential mistakes one can commit) because a simple step might seem obvious to someone and maybe some other person gets totally stuck in that position. It would really go a long way to help the students. Nevertheless, the video is amazing!

Make more videos sir

First analog channel in RU-vid

For the last question of practical opamp, probably the interviewer wanted to listen to something like this: Acl=Aol/(1+B*Aol)=(1/B) [B*Aol/(1+B*Aol)]= (Acl)ideal * [B*Aol/(1+B*Aol)]. Now as you had already derived (Acl)ideal=-2, so you can just tell that B=1/3 and Aol=2 (given) => B*Aol=2/3. So Acl=(-2)*(2/5)= -4/5 P.S: Here no mugged up formula has been used.

What are those two guys doing in video😂 just to say ya, yes and ok

Hello bhaiya , please tell me how can I contact u , I need some help in my project work