These answers are wrong because the values in the square root are positive in absolute value. The value of log3-2 is negative. When the square of this value goes outside the square root, it should be 2-log3. Kind regards.. time:<a href="#" class="seekto" data-time="414">6:54</a>
Your point of view is correct and I've taken it seriously going back to rewatch the video .But after applying your method the answer reverts to the one shown on the video. Thanks for your ardent analysis. This video is very classic because it teaches something new, thought provoking solution. I think I could have gone into details on how I manoeuvred through the square roots.
Thanks a lot for step-by-step solving process. By letting 3(x+3) = t, the given becomes t^(log(t)) = 10. taking log both sides log(t)•log(t) = log(10); [log(t)]^2 =1; log(t) = 1 or -1. t = 10 or 1/10 That is, 3(x+3) = 10 or 3(x+3) =1/10 will be a little simpler.
А не проще логарифмировать Получаем простое квадратное уравнение относительно log (x+3) log (x+3)*(log(x+3)+log 3)=1-log3 Я думаю что решение будет 2-3 минуты, а не 14 минут как на видео
