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Lifting weights to extend a spring. 

Ian Gostling
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26 май 2024

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Комментарии : 8   
@pyrrho314
@pyrrho314 2 месяца назад
this is the best demonstration of what's going on ever. I said a long time ago it's twice the difference AND twice the weight, so four times the work. This is a good picture of it that is demonstrated at the simplest level. Meanwhile the cat is out of the bag on how the Force by time thing works, it takes ANY amount of energy up or down.
@Ian.Gostling
@Ian.Gostling 2 месяца назад
I don't think Gary agrees with that summation thanks Lol!
@Space-ff6vb
@Space-ff6vb 2 месяца назад
1 mass × 1 distance = 1 2 mass × 2 distance = 4
@stephenbrough8132
@stephenbrough8132 2 месяца назад
Does he still think he's due a Nobel prize? ... And that they're gonna erect a statue of him? When someone has that kind of unrealistic dream it must be hard to let go of. It's all he's got to live for. If you're not careful he'll cross you off his Christmas list.
@_John_Sean_Walker
@_John_Sean_Walker 2 месяца назад
Point 21 of the famous Crackpot Index!
@michaelfowell223
@michaelfowell223 2 месяца назад
All hail the Great and powerful Wizard of Goofster, in reality he is more like the 3 seeking the wizard rolled into one, as a Brain and Heart and Courage are serverly in need. 👍😂
@The_Green_Man_OAP
@The_Green_Man_OAP 2 месяца назад
I think that there's a major difference between the case where the potential energy change is for a "static" spring (constant velocity mass drop, perhaps via a small platform attached to an electric motor) versus the change for a "dynamic" spring (accelerating mass drop, then decelerating due to spring), where the spring itself has momentum put into it by the falling mass. Much more energy for the dynamic case. There are two scenarios being falsely conflated into one. I think that is the source of his confusion. If dx = constant: => Uₛ= -k ₀∫ˣ x dx = -½kX² If dx = dxₜ , a function of time? => Uₛ= -k ₀∫ˣ xₜ dxₜ = ?
@_John_Sean_Walker
@_John_Sean_Walker 2 месяца назад
You can describe a spring that is not oscillating and not doing any work as a "static" spring. In physics and engineering, the term "static" generally refers to a state where a system or object is in equilibrium and there are no dynamic forces or motions involved. For a spring, this means that it is in a state of rest with no oscillations or applied forces causing it to change its state. The forces acting on it are balanced, and it remains in a fixed position. When describing a static spring, you can consider the following scenarios: - The spring is at its natural length (neither stretched nor compressed), which is its equilibrium position. - The spring is stretched or compressed but held in a fixed position by an external force, maintaining a constant deformation without movement. In both cases, the spring is not undergoing any dynamic changes, making "static" an appropriate descriptor.
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